/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 The Hayden Planetarium, at the M... [FREE SOLUTION] | 91Ó°ÊÓ

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The Hayden Planetarium, at the Museum of Natural History in New York City, boasts a dome that has a diameter of \(20 \mathrm{~m}\). The dome is a hemisphere, or half a sphere. What is the volume enclosed by the dome at the Hayden Planetarium? Use 3.14 for \(\pi\) and round to the nearest hundredth.

Short Answer

Expert verified
The volume enclosed by the dome is approximately \(2093.34\, \mathrm{m}^3\).

Step by step solution

01

Understand the Shape and Given Measurements

The problem describes the dome as a hemisphere, which means it is half of a full sphere. The diameter of the sphere is given as \(20\, \mathrm{m}\). To find the volume of the hemisphere, we need to understand that we will first find the volume of the full sphere and then divide it by 2.
02

Calculate the Radius

The radius \(r\) of a sphere is half of the diameter. Given the diameter is \(20\, \mathrm{m}\), the radius \(r\) is calculated as follows:\[ r = \frac{20}{2} = 10\, \mathrm{m}\]
03

Calculate the Volume of the Full Sphere

The formula for the volume \(V\) of a sphere is:\[ V = \frac{4}{3} \pi r^3\]Substituting the values, we find:\[ V = \frac{4}{3} \times 3.14 \times (10)^3 = \frac{4}{3} \times 3.14 \times 1000\]The calculation: \[ V = \frac{4}{3} \times 3140 = 4186.67\, \mathrm{m}^3\]
04

Calculate the Volume of the Hemisphere

Since the dome is a hemisphere, it encloses half the volume of the full sphere. Thus, we divide the volume of the full sphere by 2:\[ \text{Volume of Hemisphere} = \frac{4186.67}{2} = 2093.34\, \mathrm{m}^3\]
05

Round to the Nearest Hundredth

The calculated volume of the hemisphere is \(2093.34\, \mathrm{m}^3\). Since the problem requests rounding to the nearest hundredth, our answer is already rounded appropriately.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hemisphere Volume Calculation
To find the volume of a hemisphere, it's helpful to first understand that a hemisphere is exactly half of a sphere. The process to calculate the volume of a hemisphere involves a simple modification to the formula used for a full sphere.

Here's the step-by-step guide:
  • Start with the formula for the volume of a sphere, which is \( V = \frac{4}{3} \pi r^3 \).
  • Calculate the volume of the full sphere as if the hemisphere were complete.
  • Divide the calculated volume by 2 to find the hemisphere's volume.
In the case of the Hayden Planetarium, after calculating the volume of the full sphere based on a radius of 10 meters, we find the full sphere's volume to be approximately \( 4186.67 \, \text{m}^3 \).

Remember to divide this by 2, which gives us \( 2093.34 \, \text{m}^3 \), and that's the volume for the hemisphere.
Geometry Formulas
Geometry often involves applying specific formulas to calculate various properties of shapes, whether two-dimensional or three-dimensional. When it comes to solids like spheres or hemispheres, these formulas are invaluable tools that simplify complex volumetric calculations.
  • Volume of a sphere: \( V = \frac{4}{3} \pi r^3 \)
  • Surface area of a sphere: \( A = 4 \pi r^2 \)
  • Diameter to radius conversion: \( r = \frac{d}{2} \)
Understanding and memorizing these geometry formulas allows both students and professionals to solve real-world problems efficiently. Whether you are designing, building, or analyzing structures, knowing these formulas is essential. Always ensure you substitute correctly and complete calculations step-by-step to avoid errors.
In exercises like those involving a hemisphere, correct application and modification, such as adding divisions for halves, are key. Recognizing that such minor adjustments can drastically change an outcome is crucial when dealing with geometric problems.
Radius and Diameter Relationship
The radius and diameter are fundamental measurements in geometry. Their relationship is simple yet crucial in many calculations, especially those involving circles or spheres.

Understanding this relationship:
  • The diameter is twice the length of the radius: \( d = 2r \)
  • The radius is half of the diameter: \( r = \frac{d}{2} \)
In the context of Hayden Planetarium's dome, knowing the diameter (20 meters) allows us to quickly determine the radius by dividing the diameter by 2. This calculation provides us with a radius of 10 meters.

Since the radius is used directly in calculating the volume of spheres and hemispheres, grasping this relationship helps ensure accurate computations. Many geometric problems will present either the diameter or radius, and having the ability to interchange between the two is extremely advantageous. Remember, any miscalculation here can lead to significant errors in resultant measurements, such as volume or surface area.

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Most popular questions from this chapter

Determine whether the measurement in each statement is reasonable. Water heated to \(110^{\circ} \mathrm{F}\) will boil.

The giant Coca-Cola billboard in Times Square is lit by more than 2.6 million LEDs, which are completely powered by wind energy. This huge advertisement measures approximately 44 feet by 65 feet. Find the perimeter of the sign in yards.

There are a number of factors that determine the dimensions of a rectangular soccer field. Use the table below to answer $$\begin{array}{|l|c|c|} \hline & \text{ Soccer Field Width and Length } \\ \hline Age & \text{Width Min-Max} & \text{Length Min-Max} \\ \hline \text{Under } 6/7: & 15-20 \text{ yards} & 25-30 \text{ yards} \\ \hline \text{Under } 8: & 20-25 \text{ yards} & 30-40 \text{ yards} \\ \hline \text{Under } 9: & 30-35 \text{ yards} & 40-50 \text{ yards} \\ \hline \text{Under } 10: & 40-50 \text{ yards} & 60-70 \text{ yards} \\ \hline \text{Under } 11: & 40-50 \text{ yards} & 70-80 \text{ yards} \\ \hline \text{Under } 12: & 40-55 \text{ yards} & 100-105 \text{ yards} \\ \hline \text{Under } 13: & 50-60 \text{ yards} & 100-110 \text{ yards} \\ \hline \text{International}: & 70-80 \text{ yards} & 110-120 \text{ yards} \\ \hline \end{array}$$ a. Find the minimum length and width of a soccer field for 8-year-old children. (Carefully consider the age.) b. Find the perimeter of this field.

Solve. Choose the figure that has the greater distance around. a. Find the circumference of each circle. Approximate the circumference by using 3.14 for \(\pi\) b. If the diameter of a circle is doubled, is its corresponding circumference doubled?

Simplify. $$ 6 \cdot(8+2) $$

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