Chapter 4: Problem 24
For each of the following equations, complete the given table. $$2 x-y=6$$ $$\begin{array}{l|l} \hline x & y \\ \hline 1 & \\ \hline & 6 \\ \hline-6 & \\ \hline & -6 \end{array}$$
Short Answer
Expert verified
Fill the table with (1, -4), (6, 6), (-6, -18), and (0, -6).
Step by step solution
01
Solve for y using the first equation
Given the equation is \(2x - y = 6\). We need to solve for \(y\) in terms of \(x\).Rearranging the equation gives:\[ y = 2x - 6 \]This formula can be used to find the missing \(y\) values in the table when \(x\) is given.
02
Calculate y for x = 1
Substitute \(x = 1\) into the equation \(y = 2x - 6\):\[ y = 2(1) - 6 = 2 - 6 = -4 \]So, \(y = -4\) when \(x = 1\). The first row in the table is (1, -4).
03
Solve for x when y = 6
Given \(y = 6\), use the equation \(y = 2x - 6\):\[ 6 = 2x - 6 \]Add 6 to both sides:\[ 12 = 2x \]Divide both sides by 2:\[ x = 6 \]Thus, when \(y = 6\), \(x = 6\). The second row in the table is (6, 6).
04
Calculate y for x = -6
Substitute \(x = -6\) into the equation \(y = 2x - 6\):\[ y = 2(-6) - 6 = -12 - 6 = -18 \]So, \(y = -18\) when \(x = -6\). The third row in the table is (-6, -18).
05
Solve for x when y = -6
Given \(y = -6\), use the equation \(y = 2x - 6\):\[ -6 = 2x - 6 \]Add 6 to both sides:\[ 0 = 2x \]Divide both sides by 2:\[ x = 0 \]Thus, when \(y = -6\), \(x = 0\). The fourth row in the table is (0, -6).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Table Completion
Completing a table for a given linear equation is a straightforward task once you understand the relationship between the variables. Imagine the table as a way to organize potential values for your variables. Here, our task is to find the missing values in rows using the equation \(2x - y = 6\). This equation expresses a linear relationship between variables \(x\) and \(y\). Let's break down how to complete each row:
- For every known value of \(x\) or \(y\), substitute it into the equation.
- Use algebraic manipulation to solve for the unknown variable.
- Write the found value in your table under the correct column.
Variable Substitution
Variable substitution is a key method to solving for unknowns in equations. In our case, we often start with a known variable value, say \(x = 1\). We then substitute this value into the rearranged equation \(y = 2x - 6\).
This process involves:
This process involves:
- Inserting the known value into the formula: \(y = 2(1) - 6\).
- Carrying out the arithmetic operations: \(2 - 6 = -4\).
Equation Solving
Solving equations like \(2x - y = 6\) involves isolating the variable to find its value. Let's consider how to handle such equations to determine unknowns effectively:
- **Rearrangement**: This is your first task. For instance, if you need to solve for \(y\) in terms of \(x\), rearrange the equation. From \(2x - y = 6\), you add \(y\) to both sides and subtract 6: \(y = 2x - 6\).
- **Solving for a Specific Variable**: For situations where you know the value of one variable, substitute it and solve for the other. For example, if \(y = 6\), substitute into the rearranged equation: \(6 = 2x - 6\). Then process:
- **Rearrangement**: This is your first task. For instance, if you need to solve for \(y\) in terms of \(x\), rearrange the equation. From \(2x - y = 6\), you add \(y\) to both sides and subtract 6: \(y = 2x - 6\).
- **Solving for a Specific Variable**: For situations where you know the value of one variable, substitute it and solve for the other. For example, if \(y = 6\), substitute into the rearranged equation: \(6 = 2x - 6\). Then process:
- Add 6 to each side: \(12 = 2x\).
- Divide by 2 to isolate \(x\): \(x = 6\).