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Comparing Areas The length of a side in a square is 20 inches. If all four sides are decreased by 4 inches, by how much is the area decreased?

Short Answer

Expert verified
The area is decreased by 144 square inches.

Step by step solution

01

Calculate the Original Area

The area of a square is given by the formula \( A = s^2 \), where \( s \) is the length of a side. For a square with sides of 20 inches, the original area is: \[ A_{\text{original}} = 20^2 = 400 \text{ square inches} \]
02

Calculate the New Side Length

Each side of the square is decreased by 4 inches, so the new side length is: \[ s_{\text{new}} = 20 - 4 = 16 \text{ inches} \]
03

Calculate the New Area

Using the new side length, calculate the area of the smaller square: \[ A_{\text{new}} = 16^2 = 256 \text{ square inches} \]
04

Determine the Decrease in Area

To find out how much the area has decreased by, subtract the new area from the original area: \[ A_{\text{decrease}} = A_{\text{original}} - A_{\text{new}} = 400 - 256 = 144 \text{ square inches} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Comparing Areas
When comparing the areas of two geometric shapes, especially when one has changed dimensions, it's important to understand both initial and new measurements. In this exercise, we start with a square where each side measures 20 inches. The area of this square is calculated as the square of the side length. This means we find the area by taking 20 inches and multiplying it by itself, which results in an area of 400 square inches.

Comparing areas becomes insightful when the dimensions change. Here the sides are reduced by four inches each. A new calculation is needed to understand how this alteration affects the total area. By comparing the original and new area calculations, we find that the area gets reduced to 256 square inches, a decrease of 144 square inches. This helps us to observe how even a small reduction in dimension can result in a significant change in area.
Decrease in Dimensions
Understanding the effect of a decrease in dimensions is crucial in identifying changes in area. In this exercise, each side of the square is decreased by 4 inches. Originally, the sides were 20 inches, but they are now reduced to 16 inches each.

This might seem like a minor change, but such a decrease results in a significant impact on the area of the square. It's critical to recognize that a percent decrease in dimensions will typically result in a larger percent decrease in area since area relates to the square of the side length. When we reduce the side length by 20% (from 20 inches to 16 inches), the area decreases by 36% (from 400 square inches to 256 square inches). This concept is key in many real-world applications like material usage, construction, and design.
Geometric Calculations
Geometric calculations are fundamental in determining the attributes of shapes like squares. For squares, these calculations primarily involve determining the area or perimeter. In our exercise, we focus on the area of a square, calculated using the formula \( A = s^2 \), where \( s \) is the side length of the square.

The formula \( A = s^2 \) embodies why the area changes significantly with changes in side length—as the side length is squared, small changes in \( s \) can lead to larger changes in \( A \). Knowing this formula and understanding its applications can be extensively helpful in solving various geometric problems, from simple exercises to complex real-world scenarios.
Prealgebra Problems
Prealgebra problems often entail calculations with variables to help students understand the foundational principles of mathematics. This particular prealgebra problem is an excellent example of how mathematical concepts apply to real-world-like scenarios. It introduces the relationship between dimensions (side lengths) and area—a critical concept not only in geometry but in broader mathematical and practical contexts.

Students learn how to systematically calculate changes in area as dimensions are modified. By working through the problem, they develop skills in basic algebraic manipulation and enhance their understanding of how algebra relates to geometry. These prealgebra problems are stepping stones to more advanced topics, providing students with a firm grounding in mathematical reasoning that will serve them in more complex subject matter later.

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