Chapter 8: Problem 15
Determine \(k\) so that the point \((-1, k)\) is a solution of \(y=-5 x+3\).
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Chapter 8: Problem 15
Determine \(k\) so that the point \((-1, k)\) is a solution of \(y=-5 x+3\).
These are the key concepts you need to understand to accurately answer the question.
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The points \(A(-4,2), B(3,2), C(3,4)\), and \(D(-4,4)\) are the vertices of a rectangle. Plot these points, draw the rectangle \(A B C D\), then compute the perimeter of rectangle \(A B C D\).
The points \(A(-1,1), B(1,1), C(1,2)\), and \(D(-1,2)\) are the vertices of a rectangle. Plot these points, draw the rectangle \(A B C D\), then compute the area of rectangle \(A B C D\).
Which of the given equations is a linear equation? $$y=x+7, y=\sqrt{x+7}, y=x^{2}+7, y=x^{2}+x+7$$
Which of the given equations is a linear equation? $$y=6 x^{2}+4, y=x^{2}+6 x+4, y=6 x+4, y=\sqrt{6 x+4}$$
Plot the points \(A(-3,-2)\) and \(B(2,2)\) and find the straight-line distance between the two points. Hint: Create a right triangle, then use the Pythagorean Theorem.
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