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91Ó°ÊÓ

If \(c=-1 / 5\), evaluate \(-c^{2}\).

Short Answer

Expert verified
The value of \(-c^2\) is \(-\frac{1}{25}\).

Step by step solution

01

Understand the Expression

The expression we need to evaluate is \(-c^2\). This means that we first need to square the value of \(c\) and then multiply the result by \(-1\).
02

Substitute the Value of \(c\)

The problem states that \(c = -\frac{1}{5}\). Substitute this value into the expression, giving us \(-(-\frac{1}{5})^2\).
03

Square the Value of \(c\)

Carry out the squaring operation: \((-\frac{1}{5})^2 = (-1)^2 \times (\frac{1}{5})^2 = 1 \times \frac{1}{25} = \frac{1}{25}\).
04

Apply the Negative Sign

Finally, apply the negative sign outside the squared value:\(-c^2 = -\frac{1}{25}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Numbers
Negative numbers are numbers that are less than zero. They have a minus sign (-) in front of them. These numbers can be found on the left side of the number line.
For example,
  • -1
  • -3.5
  • -10
Negative numbers represent a variety of real-world concepts such as debts, decreases, or temperatures below zero. When dealing with negative numbers in math, their behavior changes according to specific rules:
  • Addition: Adding a negative number is like subtracting its absolute value. For instance, 5 + (-3) = 5 - 3 = 2.
  • Subtraction: Subtracting a negative number is the same as adding its absolute value. For example, 5 - (-3) = 5 + 3 = 8.
  • Multiplication: Multiplying two negative numbers results in a positive product. For instance, (-2) x (-3) = 6.
  • Division: Dividing two negative numbers also results in a positive quotient. For example, (-6) / (-3) = 2.
Understanding how to manipulate negative numbers is crucial for working successfully with mathematical expressions.
Exponents
Exponents are a way to express repeated multiplication of the same number. For example, 3 squared (written as \(3^2\)) means 3 multiplied by itself: 3 x 3. The small number, known as the exponent, tells you how many times to use the base as a factor. Here's a quick breakdown of basic exponent rules:
  • Power of zero: Any non-zero number raised to the power of zero equals one. For example, \(5^0 = 1\).
  • Power of one: Any number raised to the power of one is the number itself. For example, \(7^1 = 7\).
  • Multiplication of same bases: When multiplying like bases, you add the exponents. For example, \(x^a \times x^b = x^{a+b}\).
  • Division of same bases: When dividing like bases, you subtract the exponents. For example, \(x^a / x^b = x^{a-b}\).
When dealing with negative bases and exponents, the sign of the result depends on whether the exponent is even or odd. An even exponent results in a positive number, while an odd exponent results in a negative number. Consider \((-2)^2\) compared to \((-2)^3\):
  • Since 2 is even, \((-2)^2 = 4\).
  • Since 3 is odd, \((-2)^3 = -8\).
Getting comfortable with exponents can make solving advanced calculations faster and more efficient.
Substitution Method
The substitution method is a technique in algebra used to replace a variable with its known value in an expression or equation. This method simplifies calculations and allows you to solve for other unknowns easily. Here's how it works:
  • Identify the variable and its given value in the problem. For example, if you know \(x = 3\), you can substitute 3 for any occurrence of \(x\) in an equation.
  • Rewrite the original expression or equation with the substituted value. This step reduces the problem to numerical calculations, removing the variable.
  • Perform the arithmetic operations to solve the expression or equation. With the variable substituted, you can solve for the remaining unknowns or evaluate the expression.
In our example regarding \(c = -\frac{1}{5}\), using the substitution method helps us transform the original expression \(-c^2\) into an easily solvable mathematical expression. After substitution, the expression becomes \(-(-\frac{1}{5})^2\), which simplifies further by following the steps of calculation like squaring and multiplying the result by -1. The substitution method is a vital tool in handling more complex algebraic problems efficiently.

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