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Chapter 5: Problem 702

In the following exercises, solve. $$ \frac{h}{0.5}=4.38 $$

Short Answer

Expert verified
h = 2.19

Step by step solution

01

Understand the Equation

We are given the equation \ \[ \frac{h}{0.5} = 4.38 \ \]. Our goal is to find the value of h that satisfies this equation.
02

Eliminate the Denominator

To eliminate the denominator, multiply both sides of the equation by 0.5. This gives us: \ \[ h = 4.38 \times 0.5 \ \]
03

Perform the Multiplication

Now, perform the multiplication: \ \[ 4.38 \times 0.5 = 2.19 \ \]. So, h = 2.19.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equation Solving
When solving an equation, our primary goal is to find the value of the variable that makes the equation true. In this case, our equation is \ \( \frac{h}{0.5} = 4.38 \) \.
To solve it, we need to isolate \( h \) by performing the same operation on both sides of the equation.
Remember, whatever you do to one side, you must do to the other to keep the equation balanced.
This fundamental principle helps in gradually rearranging the equation to solve for the unknown variable.
Multiplication
Multiplication is a mathematical operation that adds a number to itself a certain number of times.
It is often used in equations to simplify and solve for variables. In our problem, we multiplied both sides of the equation by 0.5 to eliminate the denominator.
Here, the multiplication process is straightforward: \ \( 4.38 \times 0.5 = 2.19 \) \. This gives us the value of \( h \).
Multiplication can also help clear fractions and simplify arithmetic operations in equations.
Eliminating Denominators
Eliminating denominators is a valuable technique in equation solving. It transforms equations with fractions into simpler forms.
In our exercise, the equation is \ \( \frac{h}{0.5} = 4.38 \) \.
To get rid of the fraction, we multiply both sides by 0.5, the denominator.
This step clears the fraction and leaves us with a simpler equation: \ \( h = 4.38 \times 0.5 \).
This method makes the equation straightforward to solve, emphasizing the importance of operations to simplify and isolate variables in an equation.

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