Chapter 11: Problem 172
In the following exercises, graph using the intercepts. $$ 3 x+2 y=12 $$
Short Answer
Expert verified
Find intercepts \( (4, 0) \) and \( (0, 6) \), plot them, and draw the line through these points.
Step by step solution
01
Title - Find the x-intercept
To find the x-intercept, set \( y = 0 \) in the equation \( 3x + 2(0) = 12 \) Simplify: \( 3x = 12 \) Solve for \( x \): \( x = \frac{12}{3} \) So, the x-intercept is \( (4, 0) \).
02
Title - Find the y-intercept
To find the y-intercept, set \( x = 0 \) in the equation \( 3(0) + 2y = 12 \) Simplify: \( 2y = 12 \) Solve for \( y \): \( y = \frac{12}{2} \) So, the y-intercept is \( (0, 6) \).
03
Title - Plot the intercepts
Plot the points \( (4, 0) \) and \( (0, 6) \) on the coordinate plane. These points are the intercepts found in Steps 1 and 2.
04
Title - Draw the line
Draw a line passing through both intercepts: \( (4, 0) \) and \( (0, 6) \). This is the graph of the equation \( 3x + 2y = 12 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-intercept
To start understanding how to graph using intercepts, we first need to find the x-intercept. The x-intercept is where the graph crosses the x-axis.
When a line crosses the x-axis, the value of y is always zero.
Knowing this, you can find the x-intercept by setting y to 0 in the equation and solving for x.
In the given exercise \(3x + 2y = 12\), let's set \(y = 0\).
This gives us: \[ 3x + 2(0) = 12 \] Simplifying further, we have:
\[ 3x = 12 \] Solving for x: \[ x = \frac{12}{3} \] Therefore, the x-intercept is \( (4, 0) \). This means the graph will cross the x-axis at the point (4, 0).
When a line crosses the x-axis, the value of y is always zero.
Knowing this, you can find the x-intercept by setting y to 0 in the equation and solving for x.
In the given exercise \(3x + 2y = 12\), let's set \(y = 0\).
This gives us: \[ 3x + 2(0) = 12 \] Simplifying further, we have:
\[ 3x = 12 \] Solving for x: \[ x = \frac{12}{3} \] Therefore, the x-intercept is \( (4, 0) \). This means the graph will cross the x-axis at the point (4, 0).
y-intercept
Next, let's find the y-intercept, which is the point where the line crosses the y-axis.
For this, the value of x will always be zero because the point is on the y-axis.
Using the same equation \(3x + 2y = 12\), set x to 0 and solve for y: \[ 3(0) + 2y = 12 \] Simplifying further, we have:
\[ 2y = 12 \] Solving for y: \[ y = \frac{12}{2} \] So the y-intercept is \( (0, 6) \).
This means the graph will cross the y-axis at the point (0, 6). Finding these intercepts allows us to plot the two key points necessary to draw our line.
For this, the value of x will always be zero because the point is on the y-axis.
Using the same equation \(3x + 2y = 12\), set x to 0 and solve for y: \[ 3(0) + 2y = 12 \] Simplifying further, we have:
\[ 2y = 12 \] Solving for y: \[ y = \frac{12}{2} \] So the y-intercept is \( (0, 6) \).
This means the graph will cross the y-axis at the point (0, 6). Finding these intercepts allows us to plot the two key points necessary to draw our line.
coordinate plane
The coordinate plane is a two-dimensional surface where we can plot points, lines, and curves.
It consists of two axes: the x-axis (horizontal) and the y-axis (vertical). Where the two axes meet is the origin, labeled as (0,0).
The coordinate plane is divided into four quadrants:
For example, the point (4,0) lies on the x-axis 4 units to the right of the origin.
The point (0,6) lies on the y-axis 6 units above the origin. Once the intercepts are plotted on the coordinate plane, drawing a line through them completes the graphing.
It consists of two axes: the x-axis (horizontal) and the y-axis (vertical). Where the two axes meet is the origin, labeled as (0,0).
The coordinate plane is divided into four quadrants:
- Quadrant I: Both x and y values are positive
- Quadrant II: x is negative, y is positive
- Quadrant III: Both x and y values are negative
- Quadrant IV: x is positive, y is negative
For example, the point (4,0) lies on the x-axis 4 units to the right of the origin.
The point (0,6) lies on the y-axis 6 units above the origin. Once the intercepts are plotted on the coordinate plane, drawing a line through them completes the graphing.
linear equations
Understanding linear equations is crucial for graphing using intercepts.
A linear equation is an equation that forms a straight line when graphed.
It can be written in the standard form \(Ax + By = C\), where A, B, and C are constants.
In our exercise, the linear equation is \(3x + 2y = 12\). Each linear equation has a constant slope and can be easily graphed using intercepts.
To graph a linear equation, follow these steps:
This method allows you to visually see the behavior of the equation and understand its relationship between the x and y values.
A linear equation is an equation that forms a straight line when graphed.
It can be written in the standard form \(Ax + By = C\), where A, B, and C are constants.
In our exercise, the linear equation is \(3x + 2y = 12\). Each linear equation has a constant slope and can be easily graphed using intercepts.
To graph a linear equation, follow these steps:
- Find the x-intercept by setting y to 0.
- Find the y-intercept by setting x to 0.
- Plot these intercepts on the coordinate plane.
- Draw a line through the points.
This method allows you to visually see the behavior of the equation and understand its relationship between the x and y values.