Chapter 9: Problem 33
Which is greater, \(\sqrt{65}\) or \(9 ?\) Explain your reasoning.
Short Answer
Expert verified
9 is greater than \(\sqrt{65}\).
Step by step solution
01
Understand the Problem
We are asked to compare two numbers: the square root of 65, written as \(\sqrt{65}\), and the number 9.
02
Calculate Potential Values
Since we are comparing \(\sqrt{65}\) to 9, we need to determine approximately what \(\sqrt{65}\) could be close to. To do this, consider perfect squares around 65, such as \(8^2 = 64\) and \(9^2 = 81\).
03
Approximate \(\sqrt{65}\)
Since \(64 < 65 < 81\), and \(64\) is the square of 8, while \(81\) is the square of 9, it follows that \(8 < \sqrt{65} < 9\). This means \(\sqrt{65}\) is slightly more than 8, but less than 9.
04
Conclude the Comparison
Since \(\sqrt{65} < 9\), we conclude that the number 9 is greater than \(\sqrt{65}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Root Estimation
When trying to determine the approximate value of a square root, we often turn to estimation. Square root estimation is a handy technique. We use it when dealing with non-perfect squares, which are numbers that don't have an exact square root as an integer. In our case, \ \(\sqrt{65}\ \). Instead of calculating precisely, we figure out two perfect squares it falls between.
For instance, with 65, we recognize two surrounding perfect squares. By checking, we find that \ \(8^2 = 64\ \) and \ \(9^2 = 81\ \). Therefore, 65 lies between 64 and 81. This implies that the square root of 65 must lie between 8 and 9. This is why \ \(8 < \sqrt{65} < 9\ \).
By narrowing it down to these boundaries, we make estimation easier. In essence:
For instance, with 65, we recognize two surrounding perfect squares. By checking, we find that \ \(8^2 = 64\ \) and \ \(9^2 = 81\ \). Therefore, 65 lies between 64 and 81. This implies that the square root of 65 must lie between 8 and 9. This is why \ \(8 < \sqrt{65} < 9\ \).
By narrowing it down to these boundaries, we make estimation easier. In essence:
- Identify surrounding perfect squares.
- Know that the root lies between the roots of these perfect squares.
Perfect Squares
Perfect squares play a vital role not only in square root estimation but also in other mathematical applications. A perfect square is simply an integer that is the square of another integer. For instance, \ \(64\ \) is a perfect square since \ \(8^2 = 64\ \). Similarly, 81 is a perfect square because \ \(9^2 = 81\ \).
Understanding perfect squares helps you when confronted with square roots and needing quick approximations. These numbers form clear benchmarks for estimating where a non-perfect square's root might lie. In our example:
Understanding perfect squares helps you when confronted with square roots and needing quick approximations. These numbers form clear benchmarks for estimating where a non-perfect square's root might lie. In our example:
- 64 and 81 are used due to their proximity to 65.
- They help frame the root of 65 between them, giving a range.
Inequality Comparison
In the realm of math, comparing numbers often involves inequalities. An inequality tells us which number is greater or lesser. In our exercise, we established that \ \(8 < \sqrt{65} < 9\ \). This insight was crucial for comparing \ \(\sqrt{65}\ \) to 9.
To tackle inequalities efficiently, you can follow these steps:
- Convert complex expressions into simpler forms by using known values (like perfect squares).
- Place expressions in context with numbers you can compare directly through inequalities.
When \ \(\sqrt{65}\ \) was approximated, it was confirmed through inequalities that \ \(\sqrt{65}\ \) remains less than 9. This ensures that 9 is greater, considering the comparison \ \(\sqrt{65} < 9\ \). Understanding inequalities allows such deductions to be made confidently, reinforcing the use of efficient approximation and comparison strategies.
To tackle inequalities efficiently, you can follow these steps:
- Convert complex expressions into simpler forms by using known values (like perfect squares).
- Place expressions in context with numbers you can compare directly through inequalities.
When \ \(\sqrt{65}\ \) was approximated, it was confirmed through inequalities that \ \(\sqrt{65}\ \) remains less than 9. This ensures that 9 is greater, considering the comparison \ \(\sqrt{65} < 9\ \). Understanding inequalities allows such deductions to be made confidently, reinforcing the use of efficient approximation and comparison strategies.