Chapter 7: Problem 20
Graph each equation using the slope and \(y\) -intercept. $$x+y=0$$
Short Answer
Expert verified
Graph the line through (0, 0) and (1, -1) on a coordinate plane.
Step by step solution
01
Write the Equation in Slope-Intercept Form
The slope-intercept form of an equation is given by \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. Start by solving for \( y \) in the equation \( x + y = 0 \). Subtract \( x \) from both sides to get \( y = -x \). This equation is already in slope-intercept form with \( m = -1 \) and \( b = 0 \).
02
Identify the Slope and Y-Intercept
From the equation \( y = -x \), we see that the slope \( m \) is \(-1\), and the \( y \)-intercept \( b \) is \(0\). The line crosses the \( y \)-axis at the point \( (0, 0) \).
03
Graph the Y-Intercept
Plot the \( y \)-intercept on the graph. This is the point where the line crosses the \( y \)-axis. In this case, plot the point \( (0, 0) \).
04
Use the Slope to Plot Another Point
The slope \(-1\) can be interpreted as \(-1/1\). From the \( y \)-intercept at \( (0, 0) \), move down 1 unit and right 1 unit to locate the next point, which is \( (1, -1) \). Plot this point on the graph.
05
Draw the Line
With the points \( (0, 0) \) and \( (1, -1) \) plotted, draw a straight line through these points. This line represents the equation \( x + y = 0 \). Ensure the line extends in both directions and passes through both points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
Graphing linear equations can be made easier by using the slope-intercept form. This form of a linear equation is written as \( y = mx + b \). Here, \( m \) represents the slope of the line, and \( b \) is the \( y \)-intercept. The slope \( m \) tells us how steep the line is, and the \( y \)-intercept \( b \) is the point where the line crosses the \( y \)-axis. To express an equation in this form, sometimes you need to rearrange it to solve for \( y \).
In our exercise, the equation \( x + y = 0 \) was transformed into slope-intercept form by subtracting \( x \) from both sides, resulting in \( y = -x \). Once in this shape, it's easy to spot the slope and \( y \)-intercept. In this example, the slope is \(-1\) and the \( y \)-intercept is \(0\). This reformulation of equations is the first critical step in graphically representing a line.
In our exercise, the equation \( x + y = 0 \) was transformed into slope-intercept form by subtracting \( x \) from both sides, resulting in \( y = -x \). Once in this shape, it's easy to spot the slope and \( y \)-intercept. In this example, the slope is \(-1\) and the \( y \)-intercept is \(0\). This reformulation of equations is the first critical step in graphically representing a line.
Y-Intercept
The \( y \)-intercept is an essential part of understanding and graphing linear equations. It is the point where the line crosses the \( y \)-axis on a graph. In mathematical terms, it's the value of \( y \) when \( x = 0 \).
In the context of the specific equation \( y = -x \), the \( y \)-intercept is \( (0, 0) \). This means the line passes through the origin. Locating the \( y \)-intercept helps to anchor the graph. By plotting this point first, you create a start for your line, making it easier to choose additional points based on the slope for further accuracy.
To locate the \( y \)-intercept in any equation, simply substitute \( x = 0 \) into the expression and solve for \( y \). Then, mark this point on the graph. This helps ensure the line accurately represents the solution of the equation.
In the context of the specific equation \( y = -x \), the \( y \)-intercept is \( (0, 0) \). This means the line passes through the origin. Locating the \( y \)-intercept helps to anchor the graph. By plotting this point first, you create a start for your line, making it easier to choose additional points based on the slope for further accuracy.
To locate the \( y \)-intercept in any equation, simply substitute \( x = 0 \) into the expression and solve for \( y \). Then, mark this point on the graph. This helps ensure the line accurately represents the solution of the equation.
Plotting Points
Once you've found the \( y \)-intercept, the next step is plotting additional points using the slope. The slope, denoted as \( m \), is a fraction \( \Delta y / \Delta x \), where \( \Delta y \) is the change in \( y \), and \( \Delta x \) is the change in \( x \).
For the equation \( y = -x \), the slope is \(-1\), which can be rewritten as \(-1/1\). Starting from the \( y \)-intercept \( (0, 0) \), move down 1 unit in the \( y \) direction and right 1 unit in the \( x \) direction to find the next point at \( (1, -1) \). Plot this point on your graph as well.
By connecting these points with a straight line, you visually demonstrate the relation between \( x \) and \( y \) in your equation. Drawing multiple unique points using slope helps ensure accuracy in your graph and confirms that the plotted line is correct.
For the equation \( y = -x \), the slope is \(-1\), which can be rewritten as \(-1/1\). Starting from the \( y \)-intercept \( (0, 0) \), move down 1 unit in the \( y \) direction and right 1 unit in the \( x \) direction to find the next point at \( (1, -1) \). Plot this point on your graph as well.
By connecting these points with a straight line, you visually demonstrate the relation between \( x \) and \( y \) in your equation. Drawing multiple unique points using slope helps ensure accuracy in your graph and confirms that the plotted line is correct.