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Compute the standard deviations for the following sample of measurements, given that \(\underline{\mathrm{X}}=8.0\) and \(\left.\mathrm{s}=\sqrt{[\\{}^{\mathrm{n}} \sum_{\mathrm{i}=1}\left(\mathrm{X}_{\mathrm{i}}-\underline{\mathrm{X}}\right)^{2}\right\\} /\) n] and \(\mathrm{X}=5,7,8,9,11\).

Short Answer

Expert verified
The standard deviation for the given sample measurements \(\mathrm{X} = 5, 7, 8, 9, 11\) with mean \(\underline{\mathrm{X}} = 8.0\) is 2.

Step by step solution

01

Identify given values

The given sample measurements are \(\mathrm{X} = 5, 7, 8, 9, 11\) and their mean is \(\underline{\mathrm{X}} = 8.0\). We’ll use these values to compute the standard deviation using the provided formula.
02

Compute the squared deviations

First, calculate the squared deviations of the measurements from their mean. We have \(\left(\mathrm{X}_{\mathrm{i}}-\underline{\mathrm{X}}\right)^{2}\) for each measurement: \[ \left(5 - 8\right)^2 = (-3)^2 = 9 \\ \left(7 - 8\right)^2 = (-1)^2 = 1 \\ \left(8 - 8\right)^2 = (0)^2 = 0 \\ \left(9 - 8\right)^2 = (1)^2 = 1 \\ \left(11 - 8\right)^2 = (3)^2 = 9 \]
03

Calculate the sum of squared deviations

Now, sum the squared deviations calculated in Step 2: \[ \sum_{\mathrm{i}=1}^{n}\left(\mathrm{X}_{\mathrm{i}}-\underline{\mathrm{X}}\right)^{2} = 9 + 1 + 0 + 1 + 9 = 20 \]
04

Apply the standard deviation formula

Using the computed sum of squared deviations (20) and the total number of sample measurements (n=5), apply the standard deviation formula: \[ \mathrm{s} = \sqrt{[\\{}^{\mathrm{n}}\sum_{\mathrm{i}=1}\left(\mathrm{X}_{\mathrm{i}}-\underline{\mathrm{X}}\right)^{2}]/n} = \sqrt{20/5} = \sqrt{4} \]
05

Compute the standard deviation

Finally, compute the standard deviation s: \(\mathrm{s} = \pm\sqrt{4} = \pm2\) Since standard deviation is always positive, the standard deviation for the given sample measurements is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Analysis
Statistical analysis encompasses a broad range of techniques used to understand data. It enables us to collect, analyze, interpret, present, and organize data to uncover patterns, trends, and relationships. A fundamental element of statistical analysis is the ability to accurately describe the dispersion or spread of a dataset - this is where measures such as range, variance, and standard deviation come into play.

For students grappling with new statistical concepts, focusing on the interpretation of results - like what a high standard deviation indicates about a data set - can provide practical insights for real-world applications. Developing a strong foundation in statistical analysis is crucial in various fields, from business to science, as it forms the basis for data-driven decision-making.
Mean of Sample
The mean of a sample, often referred to as the 'average', is a measure of the central tendency within a set of numbers. It is computed by adding up all the individual values in a sample and then dividing by the total number of values. Illustrated by the symbol \(\bar{X}\), the mean represents a typical value in the dataset. For instance, in a classroom, the mean test score gives an idea of the overall performance of the class.

Understanding the mean is vital, as it's used as a reference point for other statistical measures like variance and standard deviation. When interpreting the mean, students should also consider the shape of the data distribution; for example, in skewed distributions, the mean may not be the most informative measure of central tendency.
Squared Deviations
Squared deviations are used in statistics to quantify how far individual values are from the mean of the sample. To compute a squared deviation, you subtract the sample mean from an individual value and then square the result. This squaring process is crucial as it converts negative differences to positive values, allowing us to focus on the magnitude of the deviation irrespective of the direction.

The concept of squared deviations is the cornerstone of more complex statistical measures such as variance and standard deviation. It removes the issue that simply summing up the deviations would give a total of zero (due to positive and negative differences canceling each other out), making it a clear way to express the variability within a dataset. Students should grasp that squaring larger deviations will give them more weight compared to smaller ones, thereby highlighting outliers.
Variance
Variance in statistics measures how widely individual numbers in a dataset are spread out from their mean. Conceptually, it's the average of the squared deviations that were discussed earlier. Calculating variance involves summing up all the squared deviations and then dividing by the number of values in the sample. Represented by \(\sigma^2\) for population variance or \(s^2\) for sample variance, variance gives us the 'average squared deviation' from the mean.

A larger variance indicates that data points are more spread out from the mean, while a smaller variance suggests they are closer. For students, understanding variance is an essential step towards comprehending how data is distributed around the mean, and it sets the stage for calculating the standard deviation, which is a more interpretable measure of spread.

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