Chapter 41: Problem 885
Discuss the rational integral equation \(x^{2}-2 x y+y^{2}+2 x-3=0\), and plot its graph.
Short Answer
Expert verified
The rational integral equation given is \((x - y)^2 + 2x - 3 = 0\), which is non-linear and symmetric with respect to x and y. To plot its graph, we solve for y in terms of x, obtaining \(y = x \mp\sqrt{-2x + 3}\) for \(x \le \dfrac{3}{2}\). The graph is symmetric about the line y = x and exists in the region where x is less than or equal to \(\dfrac{3}{2}\).
Step by step solution
01
Rewrite the equation in a more familiar form
The given equation is \(x^2 - 2xy + y^2 + 2x - 3 = 0\). Let's rewrite this equation to make it easier to work with. Note that the equation is a quadratic in both x and y. We can rewrite the equation as follows:
\((x - y)^2 + 2x - 3 = 0\)
Now we have a squared term and a linear term.
02
Discuss notable properties of the equation
In the given equation, \((x - y)^2 + 2x - 3 = 0\), both x and y are squared. Therefore, it is non-linear. The equation is also symmetric with respect to x and y, meaning that if we swap x and y, the equation remains unchanged. To see this, let's swap x and y:
\((y - x)^2 + 2y - 3 = 0\)
The equation remains the same as the original equation.
Furthermore, since the equation involves both x and y variables, we cannot separate the equation into two individual equations involving a single variable. The graph of the equation will likely involve both x and y coordinates.
03
Plot the graph of the equation
To plot the graph of the equation \((x - y)^2 + 2x - 3 = 0\), we can try to solve for y in terms of x or vice versa. Here, let's solve for y in terms of x:
\((x - y)^2 + 2x - 3 = 0\)
\((x - y)^2 = -2x + 3\)
Since we do not want to work with the square root of a negative number, we consider cases where the right side of the equation is non-negative. That is, \(3 \ge 2x\), or \(x \le \dfrac{3}{2}\).
For non-negative values of \(-2x + 3\), we can now find y in terms of x:
\(x - y = \pm\sqrt{-2x + 3}\)
\(y = x \mp\sqrt{-2x + 3}\)
We can now plot the graph of the equation using the above relationships between x and y. The graph will be symmetric about the line y = x due to the symmetrical nature of the equation and will exist in the region where x is less than or equal to \(\dfrac{3}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a vital concept in mathematics. It is an equation of degree two, which means its highest exponent is two. The general form of a quadratic equation is given by \( ax^2 + bx + c = 0 \), where \( a eq 0 \). In this exercise, the equation can be seen as quadratic in terms of \( x \) and \( y \) because both variables are squared. This means you have a term like \( (x-y)^2 \). This 'square' part of the equation gives it the characteristic curve form when graphed. To recognize a quadratic equation in the context of both variables, look for:
- Squared terms (like \( x^2 \) or \( y^2 \))
- Coefficients that guide the specifics of the curve's height and direction
Non-Linear Equations
Non-linear equations can seem complex at first, mainly because their graphs do not form a straight line. In simpler terms, a non-linear equation involves powers greater than one or results from products of variables. Our given equation \((x - y)^2 + 2x - 3 = 0\) is non-linear. This is identifiable because of the squared term \((x-y)^2\). Non-linear equations are essential for modeling real-world scenarios where relationships are not straightforward. Properties of non-linear equations include:
- The potential for multiple solutions
- Curved graphs instead of straight lines
- They can be symmetric - as in our equation, swapping \( x \) and \( y \) leaves the equation unchanged.
Graph of Equation
Visualizing an equation through its graph gives significant insight into its behavior and the relationship between variables. To graph the equation \((x - y)^2 + 2x - 3 = 0\), we solve it for one variable in terms of the other and find the feasible range of values. Let's break down the steps:
- First, express \( y \) explicitly as it relates to \( x \): \( y = x \mp \sqrt{-2x + 3} \).
- Next, acknowledge that \( -2x + 3 \geq 0 \). This inequality means that \( x \leq \frac{3}{2} \).
- Finally, draw the functions given by \( y = x + \sqrt{-2x + 3} \) and \( y = x - \sqrt{-2x + 3} \).
Solving for y
Solving for one variable in terms of another is a significant step in graphing equations and understanding their relationships. Sometimes, you might need to solve for \( y \) from a complex expression like \((x - y)^2 + 2x - 3 = 0\). Here, the steps to isolate \( y \) include:
- Start with rearranging the equation so that all terms involving \( y \) are isolated. In our case, we simplify \((x - y)^2 = -2x + 3 \).
- Apply square roots on both sides, careful about both the positive and negative roots: \( x - y = \pm \sqrt{-2x + 3} \).
- Finally, express \( y \) in terms of \( x \): \( y = x \mp \sqrt{-2x + 3} \).