Chapter 1: Problem 2
Construct the graph of the function: (i) \(f(x)=|x-1|+|x+1|\) (ii) \(f(x)=\left\\{\begin{array}{lr}3^{x} ; & -1 \leq x \leq 1 \\ 4-x ; & 1 \leq x<4\end{array}\right.\) (iii) \(f(x)=[x]+|x-1| ; \quad-1 \leq x \leq 3\) (where [ ] denotes greatest integer function) (iv) \(f(x)= \begin{cases}x^{4} ; & x^{2}<1 \\ x ; & x^{2} \geq 1\end{cases}\)
Short Answer
Step by step solution
Graph of f(x) = |x - 1| + |x + 1|
Graph of f(x) for piecewise function
Graph of f(x) = [x] + |x - 1|
Graph of f(x) with cases based on x^2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Functions
Functions like \( f(x) = |x - 1| + |x + 1| \) use this property. We identify critical points, where the behavior of the absolute value changes the function - in this case at \(x = 1\) and \(x = -1\). List out:**
- For \(x < -1\), break the function into \( |x-1| = -x + 1 \) and \( |x+1| = -x - 1 \), resulting in \(-2x\).
- For \(-1 \leq x < 1\), the absolute changes direction, giving \(2\) as the function's output.
- For \(x \geq 1\), each absolute value resolves to a positive term, resulting in \(2x\).
Piecewise Functions
An example is \(f(x)\) being defined in two distinct parts:
- For \(-1 \leq x \leq 1\), it is governed by the exponential \(f(x) = 3^x\).
- For \(1 < x < 4\), the expression transitions to linear with \(f(x)=4-x\).
Greatest Integer Function
Consider the function \(f(x) = [x] + |x - 1|\). This is evaluated in different intervals based on \([x]\):
- For \(-1 \leq x < 0\), evaluate as \(-x\).
- From \(0 \leq x < 1\), the result adjusts to \(1-x\).
- For \(1 \leq x < 2\), the calculation is static at \(1\).
- Lastly, for \(2 \leq x < 3\), compute as \(x + 1\).
Polynomial Functions
Consider a simple piecewise polynomial function like \(f(x)\) with quadratic and linear components:
- For \(|x| < 1\), represented by \(f(x) = x^4\), creating a U-shaped parabola.
- For \(|x| \geq 1\), \(f(x) = x\) presents linear components extending to both sides.