Chapter 5: Problem 1
a. Find the equation of each line. Slope 3 and point \((4,-4)\)
Short Answer
Expert verified
The equation is \( y = 3x - 16 \).
Step by step solution
01
Identify the given information
The problem provides a slope of 3 and a specific point \(4, -4\) on the line.
02
Use the point-slope form of the equation
The point-slope form of a line's equation is \[ y - y_1 = m(x - x_1) \], where \(m\) is the slope and \( (x_1, y_1) \) is a point on the line. Here, \(m = 3\), \(x_1 = 4\), and \(y_1 = -4\).
03
Substitute the given values into the point-slope formula
Plugging in the values, the equation becomes: \[ y - (-4) = 3(x - 4) \].
04
Simplify the equation
The equation simplifies to: \[ y + 4 = 3(x - 4)\]. Then, \[ y + 4 = 3x - 12\]. Subtract 4 from both sides to solve for \(y\): \[ y = 3x - 16\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Slope-Intercept Form
The slope-intercept form of a linear equation is a common and useful way to represent a straight line. It is written as \y = mx + b\, where \(m\) is the slope of the line, and \(b\) is the y-intercept, which is the point where the line crosses the y-axis. This form is particularly helpful because it provides clear information about the line's slope and its intersection with the y-axis. For instance, if you have the equation \y = 3x - 16\, here \(m = 3\) tells us the line increases by 3 units vertically for every 1 unit it moves horizontally. The \(b = -16\) indicates the line crosses the y-axis at \y = -16\. To find the equation of a line when given a slope and a point, you can first use point-slope form and then convert it to slope-intercept form.
How to Use the Point-Slope Form
The point-slope form of a linear equation is another way to write the equation of a line. It is given by \y - y_1 = m(x - x_1)\. In this formula:
- \(m\) is the slope of the line.
- \((x_1, y_1)\) represents a point on the line.
Solving Linear Equations
Solving linear equations involves finding the value of the variable that makes the equation true. When working from point-slope form to slope-intercept form, it's important to perform accurate algebraic manipulations. For example, starting from \y + 4 = 3(x - 4)\, the first step is to simplify the right-hand side: \y + 4 = 3x - 12\. Then, isolate \(y\) by subtracting 4 from both sides, resulting in \y = 3x - 16\. Throughout this process, keep in mind the goal is to solve for \(y\) in terms of \(x\) to arrive at a result in slope-intercept form. This practice of linear equation solving is handy not only in mathematics but in many applied fields like physics and economics where modeling relationships between quantities is required.