Chapter 2: Problem 3
Draw the direction field for the equation \(y^{\prime}=x^{2}+y^{2}\).
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Chapter 2: Problem 3
Draw the direction field for the equation \(y^{\prime}=x^{2}+y^{2}\).
These are the key concepts you need to understand to accurately answer the question.
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Consider the initial-value problem $$ \begin{array}{r} y^{\prime}=3 y^{2 / 3}, \\ y\left(x_{0}\right)=y_{0} \end{array} $$ Discuss and sketch the solutions.
Solve the initial-value problem $$ \begin{aligned} y^{\prime} &=\alpha y-\beta y^{2}, \\ y(0) &=y_{0} \end{aligned} $$ where \(\alpha\) and \(\beta\) are small positive numbers. Show that $$ \lim _{x \rightarrow \infty} \phi(x)=\left\\{\begin{array}{ll} \alpha / \beta & \text { for } y_{0}>0, \\ 0 & \text { for } y_{0}=0 . \end{array}\right. $$ For \(y_{0}<0, \phi\) is unbounded as \(x\) approaches a certain value depending on \(y_{0}\).
If \(M=y f(x y)\) and \(N=x g(x y)\), show that \(1 /(M x-N y)\) is an integrating factor provided \(M x-N y \neq 0 .\)
An equation of the form $$ y=x p+f(p) $$ where \(p=d y / d x\), is known as a Clairaut equation. (a) Differentiate (A) with respect to \(x\) and obtain $$ \left[x+f^{\prime}(p)\right] \frac{d p}{d x}=0 $$ (b) If \(\left[x+f^{\prime}(p)\right] \neq 0\), then \(d p / d x=0\), which gives \(p=c\), and as a result \(y=c x+f(c)\) (c) If \(x+f^{\prime}(p)=0\), then a singular solution is obtained by eliminating \(p\) between the equations \(x+f^{\prime}(p)=0\) and \(y=x p+f(p)\). (d) Determine a one-parameter family of solutions of $$ y=x p+p^{2} . $$ Find the singular solution also.
By the method of separation of variables solve \(y^{\prime}=(\cos x)(y-2)\) satisfying the initial condition \(y(0)=1\). Find the unique solution of the same equation satisfying \(y(0)=2 .\) Specify the interval on which the solution is defined in each case.
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