/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 The following regression output ... [FREE SOLUTION] | 91Ó°ÊÓ

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The following regression output is for predicting the heart weight (in g) of cats from their body weight (in \(\mathrm{kg}\) ). The coefficients are estimated using a dataset of 144 domestic cats. $$\begin{array}{rrrrr} \hline & \text { Estimate } & \text { Std. Error } & \text { t value } & \operatorname{Pr}(>|\mathrm{t}|) \\ \hline \text { (Intercept) } & -0.357 & 0.692 & -0.515 & 0.607 \\ \text { body wt } & 4.034 & 0.250 & 16.119 & 0.000 \\ \hline s=1.452 & R^{2}=64.66 \% & \quad R_{a d j}^{2}=64.41 \% \end{array}$$ (a) Write out the linear model. (b) Interpret the intercept. (c) Interpret the slope. (d) Interpret \(R^{2}\). (e) Calculate the correlation coefficient.

Short Answer

Expert verified
(a) \( y = -0.357 + 4.034x \); (b) Intercept isn't meaningful; (c) 4.034 g increase per kg body weight; (d) 64.66% variance explained; (e) \( r \approx 0.804 \).

Step by step solution

01

Write the Linear Model

The regression equation is of the form: \( y = \beta_0 + \beta_1 x \), where \( \beta_0 \) is the intercept and \( \beta_1 \) is the slope. From the output given, the linear model equation is: \( \text{Heart Weight} = -0.357 + 4.034 \times \text{Body Weight} \).
02

Interpret the Intercept

The intercept, \(-0.357\), represents the estimated heart weight when the body weight is zero. However, it is not practically interpretable in this context since a body weight of zero is biologically meaningless for cats.
03

Interpret the Slope

The slope, \(4.034\), indicates that for each additional kilogram of body weight, the heart weight is expected to increase by approximately 4.034 grams. This means there is a positive relationship between body weight and heart weight.
04

Interpret R-squared

\(R^{2}\) is 64.66%, which indicates that approximately 64.66% of the variation in heart weight is explained by the variation in body weight in this model. This suggests a good fit of the model to the data.
05

Calculate the Correlation Coefficient

The correlation coefficient \(r\) is the square root of \(R^{2}\). Since the slope is positive, \(r\) will be positive. Thus, \( r = \sqrt{0.6466} \approx 0.804 \). This value suggests a strong positive linear relationship between the body weight and heart weight of cats.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Analysis
Regression analysis is a powerful statistical technique used to examine the relationship between two or more variables. In the context of the provided exercise, we are looking at a linear regression model that predicts the heart weight of cats based on their body weight.
The essence of regression analysis is to determine how one variable, called the dependent variable, is affected by another, known as the independent variable. Here, heart weight is the dependent variable, and body weight is the independent variable.
  • Regression models help to quantify the strength and nature of the relationship between variables.
  • A linear regression model is characterized by a line that best fits the data points on a scatterplot.
By using a dataset, regression analysis estimates coefficients like the intercept and slope that are used to make predictions. This model can identify trends and forecast outcomes, which is especially useful in scientific research and practical applications.
Correlation Coefficient
The correlation coefficient, often denoted as \( r \), is a statistical measure that evaluates the strength and direction of a linear relationship between two continuous variables. In our linear regression example, we calculated \( r \) from \( R^2 \).
Finding the correlation coefficient involves taking the square root of \( R^2 \), the coefficient of determination. Since the equation indicates a positive correlation (due to the positive slope), \( r \) is also positive.
  • A correlation coefficient closer to 1 implies a strong positive relationship.
  • A value near -1 indicates a strong negative relationship.
  • If \( r \) is 0, it suggests no linear relationship between the variables.
In the exercise, \( r = 0.804 \) shows a strong positive linear correlation, meaning that as a cat's body weight increases, its heart weight tends to increase as well.
R-squared Interpretation
\( R^2 \), or the coefficient of determination, is a key output of regression analysis. It provides the proportion of variance in the dependent variable that is predictable from the independent variable.
In our example, the \( R^2 \) is 64.66%, indicating that approximately 65% of the variation in heart weight can be explained by the variation in body weight. This means the model has a good fit as it captures a significant portion of the relationship.
  • An \( R^2 \) close to 1 indicates that the model explains most of the variability in the response data around its mean.
  • A value of 0 means the model explains none of the variability.
  • Keep in mind, a high \( R^2 \) does not imply causation but merely association.
It is essential to contextualize \( R^2 \) with subject matter expertise to judge the model's practical significance in a realistic setting.
Linear Model Interpretation
Interpreting a linear model involves understanding the meaning of its coefficients in the context of the real-world problem being studied.
The linear equation derived from our regression output can be written as: \( \text{Heart Weight} = -0.357 + 4.034 \times \text{Body Weight} \).
  • **Intercept (-0.357):** This coefficient represents the estimated heart weight when the body weight is zero. In our case, it's not practically meaningful because a cat cannot have zero body weight. It serves mainly as a mathematical constant necessary for the linear equation.
  • **Slope (4.034):** This is the coefficient of the body weight variable and indicates that for every additional kilogram of body weight, the heart weight is expected to increase by about 4.034 grams. This suggests a positive linear relationship between body weight and heart weight in cats.
Analyzing the coefficients allows us to derive insights into how changes in explanatory variables impact the response variable, providing essential information for decision-making and prediction tasks.

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Most popular questions from this chapter

What would be the correlation between the ages of husbands and wives if men always married woman who were (a) 3 years younger than themselves? (b) 2 years older than themselves? (c) half as old as themselves?

Exercise 8.26 presents regression output from a model for predicting the heart weight (in g) of cats from their body weight (in kg). The coefficients are estimated using a dataset of 144 domestic cat. The model output is also provided below. $$\begin{array}{rrrrr}\hline & \text { Estimate } & \text { Std. Error } & \text { t value } & \operatorname{Pr}(>|\mathrm{t}|) \\\\\hline \text { (Intercept) } & -0.357 & 0.692 & -0.515 & 0.607 \\ \text { body wt } & 4.034 & 0.250 & 16.119 & 0.000 \\ \hline\end{array}$$ \(s=1.452 \quad R^{2}=64.66 \% \quad R_{a d j}^{2}=64.41 \%\) (a) We see that the point estimate for the slope is positive. What are the hypotheses for evaluating whether body weight is positively associated with heart weight in cats? (b) State the conclusion of the hypothesis test from part (a) in context of the data. (c) Calculate a \(95 \%\) confidence interval for the slope of body weight, and interpret it in context of the data. (d) Do your results from the hypothesis test and the confidence interval agree? Explain.

A study conducted at the University of Denver investigated whether babies take longer to learn to crawl in cold months, when they are often bundled in clothes that restrict their movement, than in warmer months. \({ }^{6}\) Infants born during the study year were split into twelve groups, one for each birth month. We consider the average crawling age of babies in each group against the average temperature when the babies are six months old (that's when babies often begin trying to crawl). Temperature is measured in degrees Fahrenheit ( \({ }^{\circ} \mathrm{F}\) ) and age is measured in weeks. (a) Describe the relationship between temperature and crawling age. (b) How would the relationship change if temperature was measured in degrees Celsius \(\left({ }^{\circ} \mathrm{C}\right)\) and age was measured in months? (c) The correlation between temperature in \({ }^{\circ} \mathrm{F}\) and age in weeks was \(r=-0.70\). If we converted the temperature to \({ }^{\circ} \mathrm{C}\) and age to months, what would the correlation be?

Many people believe that gender, weight, drinking habits, and many other factors are much more important in predicting blood alcohol content (BAC) than simply considering the number of drinks a person consumed. Here we examine data from sixteen student volunteers at Ohio State University who each drank a randomly assigned number of cans of beer. These students were evenly divided between men and women, and they differed in weight and drinking habits. Thirty minutes later, a police officer measured their blood alcohol content (BAC) in grams of alcohol per deciliter of blood. \(^{19}\) The scatterplot and regression table summarize the findings. $$\begin{array}{rrrrr} \hline & \text { Estimate } & \text { Std. Error } & \mathrm{t} \text { value } & \operatorname{Pr}(>|\mathrm{t}|) \\ \hline \text { (Intercept) } & -0.0127 & 0.0126 & -1.00 & 0.3320 \\ \text { beers } & 0.0180 & 0.0024 & 7.48 & 0.0000 \\ \hline\end{array}$$ (a) Describe the relationship between the number of cans of beer and \(\mathrm{BAC}\). (b) Write the equation of the regression line. Interpret the slope and intercept in context. (c) Do the data provide strong evidence that drinking more cans of beer is associated with an increase in blood alcohol? State the null and alternative hypotheses, report the p-value, and state your conclusion. (d) The correlation coefficient for number of cans of beer and \(\mathrm{BAC}\) is \(0.89 .\) Calculate \(R^{2}\) and interpret it in context. (e) Suppose we visit a bar, ask people how many drinks they have had, and also take their BAC. Do you think the relationship between number of drinks and BAC would be as strong as the relationship found in the Ohio State study?

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