/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 The General Social Survey asked ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The General Social Survey asked 1,578 US residents: "Do you think the use of marijuana should be made legal, or not?" \(61 \%\) of the respondents said it should be made legal. 13 (a) Is \(61 \%\) a sample statistic or a population parameter? Explain. (b) Construct a \(95 \%\) confidence interval for the proportion of US residents who think marijuana should be made legal, and interpret it in the context of the data. (c) A critic points out that this \(95 \%\) confidence interval is only accurate if the statistic follows a normal distribution, or if the normal model is a good approximation. Is this true for these data? Explain. (d) A news piece on this survey's findings states, "Majority of Americans think marijuana should be legalized." Based on your confidence interval, is this news piece's statement justified?

Short Answer

Expert verified
(a) 61% is a sample statistic. (b) The 95% CI is [0.5859, 0.6341]. (c) Yes, the normal model is appropriate. (d) Yes, the statement is justified.

Step by step solution

01

Determine if 61% is a sample statistic or a population parameter

A population parameter is a characteristic or measure obtained by using all of the data from a population, while a sample statistic is a characteristic or measure obtained by using the data from a sample. Since 61% refers to the proportion of the 1,578 sampled respondents and not the entire population, it is a sample statistic.
02

Calculate the 95% Confidence Interval

To construct a 95% confidence interval for the proportion of US residents who support marijuana legalization, use the formula for a confidence interval of a proportion: \(\hat{p} \pm Z \cdot \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \)where \(\hat{p} = 0.61\), \(n = 1578\), and \(Z\) for a 95% confidence level is approximately 1.96.- Calculate the standard error: \(\sqrt{\frac{0.61 \cdot (1-0.61)}{1578}} \approx 0.0123\)- Calculate the margin of error: \(1.96 \cdot 0.0123 \approx 0.0241\)- The 95% confidence interval is: \(0.61 \pm 0.0241 = [0.5859, 0.6341]\) Thus, the confidence interval is [0.5859, 0.6341].
03

Check if the normal model is appropriate

The normal model is appropriate if both \(np\) and \(n(1-p)\) are greater than 5. For this survey:- Calculate \(np = 1578 \cdot 0.61 \approx 962.58\)- Calculate \(n(1-p) = 1578 \cdot 0.39 \approx 615.42\)Since both values are greater than 5, the normal approximation is appropriate for these data.
04

Evaluate the news statement

The confidence interval [0.5859, 0.6341] does not contain 0.5, meaning the interval suggests more than 50% of the population supports legalization. Thus, stating that "a majority of Americans think marijuana should be legalized" is justified by the confidence interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Statistic
In the world of statistics, it's crucial to distinguish between sample statistics and population parameters. These terms might sound similar, but they represent different aspects of data analysis. A **sample statistic** is a measure that describes some characteristic obtained from a subset, or sample, of a population. In this case, when the survey reported that 61% of the 1,578 participants support marijuana legalization, this percentage is our sample statistic. It's derived strictly from those surveyed, not the entire population. Therefore, it provides an estimate or snapshot based on just a segment of the whole, rather than reflecting everyone’s views.
Population Parameter
The concept of a **population parameter** is essentially the counterpart to a sample statistic. While the sample statistic represents a portion of a group, the population parameter represents a characteristic of the entire population being studied. If we wanted a true population parameter in this scenario, we would need data from every US resident. However, such comprehensive data is often impractical to collect. Instead, we rely on statistical methods, like confidence intervals, to estimate these parameters. This distinction is foundational, helping us understand whether data reflects a sample or seeks to estimate broader population tendencies.
Normal Distribution
The **normal distribution** is a vital concept in statistics, often known as the bell curve due to its characteristic shape. The idea is that for many kinds of data, values will tend to cluster around the mean - the average value. In the context of the survey on marijuana legalization, the normal distribution concept helps in constructing a confidence interval. This requires the data to follow a pattern that can be approximated as normal, especially when sample sizes are large. A great rule of thumb is ensuring that both the expected number of 'successes' (people supporting legalization) and 'failures' (those opposing) are more than 5. As calculated:
  • The number of supporters: \(np = 1578 \times 0.61 \approx 962.58\)
  • The number of non-supporters: \(n(1-p) = 1578 \times 0.39 \approx 615.42\)
Both conditions are satisfied, confirming the data follows a normal distribution pattern.
Proportion Estimation
**Proportion estimation** is at the heart of understanding survey data like this. The 61% is our sample proportion, representing those in favor of legalization. Using this, we can estimate the proportion of the entire population that shares this view, giving us an insight into societal trends. We create a confidence interval to decide how confident we can be in our estimate. In this exercise, the computed confidence interval \([0.5859, 0.6341]\) allows us to say, with 95% confidence, that the true proportion of the population that supports legalization lies within this range. This calculated interval reassures us that a majority supports legalization, as it firmly exceeds 50% and provides a robust basis for making broader assertions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercise 6.11 presents the results of a poll evaluating support for a generically branded "National Health Plan" in the United States. \(79 \%\) of 347 Democrats and \(55 \%\) of 617 Independents support a National Health Plan. (a) Calculate a \(95 \%\) confidence interval for the difference between the proportion of Democrats and Independents who support a National Health Plan \(\left(p_{D}-p_{I}\right),\) and interpret it in this context. We have already checked conditions for you. (b) True or false: If we had picked a random Democrat and a random Independent at the time of this poll, it is more likely that the Democrat would support the National Health Plan than the Independent.

A professor using an open source introductory statistics book predicts that \(60 \%\) of the students will purchase a hard copy of the book, \(25 \%\) will print it out from the web, and \(15 \%\) will read it online. At the end of the semester he asks his students to complete a survey where they indicate what format of the book they used. Of the 126 students, 71 said they bought a hard copy of the book, 30 said they printed it out from the web, and 25 said they read it online. (a) State the hypotheses for testing if the professor's predictions were inaccurate. (b) How many students did the professor expect to buy the book, print the book, and read the book exclusively online? (c) This is an appropriate setting for a chi-square test. List the conditions required for a test and verify they are satisfied. (d) Calculate the chi-squared statistic, the degrees of freedom associated with it, and the p-value. (e) Based on the p-value calculated in part (d), what is the conclusion of the hypothesis test? Interpret your conclusion in this context.

Suppose that \(8 \%\) of college students are vegetarians. Determine if the following statements are true or false, and explain your reasoning. (a) The distribution of the sample proportions of vegetarians in random samples of size 60 is approximately normal since \(n \geq 30\). (b) The distribution of the sample proportions of vegetarian college students in random samples of size 50 is right skewed. (c) A random sample of 125 college students where \(12 \%\) are vegetarians would be considered unusual. (d) A random sample of 250 college students where \(12 \%\) are vegetarians would be considered unusual. (e) The standard error would be reduced by one-half if we increased the sample size from 125 to 250 .

The United States federal government shutdown of \(2018-2019\) occurred from December 22,2018 until January \(25,2019,\) a span of 35 days. A Survey USA poll of 614 randomly sampled Americans during this time period reported that \(48 \%\) of those who make less than \(\$ 40,000\) per year and \(55 \%\) of those who make \(\$ 40,000\) or more per year said the government shutdown has not at all affected them personally. A \(95 \%\) confidence interval for \(\left(p_{<40 \mathrm{~K}}-p_{\geq 40 \mathrm{~K}}\right),\) where \(p\) is the proportion of those who said the government shutdown has not at all affected them personally, is \((-0.16,0.02) .\) Based on this information, determine if the following statements are true or false, and explain your reasoning if you identify the statement as false. \(^{24}\) (a) At the \(5 \%\) significance level, the data provide convincing evidence of a real difference in the proportion who are not affected personally between Americans who make less than \(\$ 40,000\) annually and Americans who make \(\$ 40,000\) annually. (b) We are \(95 \%\) confident that \(16 \%\) more to \(2 \%\) fewer Americans who make less than \(\$ 40,000\) per year are not at all personally affected by the government shutdown compared to those who make \(\$ 40,000\) or more per year. (c) A \(90 \%\) confidence interval for \(\left(p_{<40 \mathrm{~K}}-p_{\geq 40 \mathrm{~K}}\right)\) would be wider than the (-0.16,0.02) interval. (d) A \(95 \%\) confidence interval for \(\left(p_{\geq 40 \mathrm{~K}}-p_{<40 \mathrm{~K}}\right)\) is (-0.02,0.16) .

Greece has faced a severe economic crisis since the end of \(2009 .\) A Gallup poll surveyed 1,000 randomly sampled Greeks in 2011 and found that \(25 \%\) of them said they would rate their lives poorly enough to be considered "suffering". (a) Describe the population parameter of interest. What is the value of the point estimate of this parameter? (b) Check if the conditions required for constructing a confidence interval based on these data are met. (c) Construct a \(95 \%\) confidence interval for the proportion of Greeks who are "suffering". (d) Without doing any calculations, describe what would happen to the confidence interval if we decided to use a higher confidence level. (e) Without doing any calculations, describe what would happen to the confidence interval if we used a larger sample.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.