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Swaziland has the highest HIV prevalence in the world: \(25.9 \%\) of this country's population is infected with HIV. \(^{65}\) The ELISA test is one of the first and most accurate tests for HIV. For those who carry HIV, the ELISA test is \(99.7 \%\) accurate. For those who do not carry HIV, the test is \(92.6 \%\) accurate. If an individual from Swaziland has tested positive, what is the probability that he carries HIV?

Short Answer

Expert verified
The probability is approximately 34.58% that the individual has HIV after testing positive using the ELISA test.

Step by step solution

01

Identify the Bayes' Theorem

To find the probability that an individual who tested positive actually has HIV, we will use Bayes' Theorem. It relates the conditional and marginal probabilities of random events.
02

Define the Known Probabilities

Let \( P(H) \) be the probability of having HIV = \(25.9\% = 0.259\). Let \( P(+ | H) \) be the probability of testing positive if you have HIV = \(99.7\% = 0.997\). Let \( P(+ | H^c) \) be false positive rate = \(100\% - 92.6\% = 7.4\% = 0.074\).
03

Find P(+), The Total Probability of Testing Positive

Using the law of total probability: \[ P(+) = P(+ | H) \cdot P(H) + P(+ | H^c) \cdot P(H^c) \] where \( P(H^c) = 1 - P(H) = 0.741 \).
04

Calculate P(+) Value

Substitute the known values into the total probability equation: \[ P(+) = 0.997 \times 0.259 + 0.074 \times 0.741 = 0.005647 + 0.054834 = 0.07481 \]
05

Apply Bayes' Theorem

Use Bayes' Theorem to find the probability that someone has HIV given a positive test result: \[ P(H | +) = \frac{P(+ | H) \times P(H)}{P(+)} = \frac{0.997 \times 0.259}{0.07481} = \frac{0.258743}{0.07481} \approx 0.3458 \] or \( 34.58\% \).
06

Interpret the Result

The probability that an individual who tested positive actually has HIV is approximately \(34.58\%\). This implies a substantial chance, but also highlights the importance of further confirmatory testing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory forms the backbone of statistical analysis and is essential in measuring the likelihood of various events. It tells us how likely an event is to occur compared to all other possible outcomes. In our exercise with the HIV testing, probability theory helps us understand how to calculate the odds or chances of someone actually having HIV after a positive test result.
Probability is expressed as a number between 0 and 1, where 0 indicates an impossible event, and 1 signifies a certain event. It's important to grasp that probability is all about the ratio of favorable outcomes to the total number of possible outcomes.
A few basic rules include:
  • The sum of probabilities of all possible outcomes always equals 1.
  • Event probabilities are always non-negative.
  • Complementary events add up to 1.
In the context of our exercise, knowing the probability that an individual either has HIV or doesn't (complementary events) helps us determine overall test accuracy.
Conditional Probability
Conditional probability is a way to measure the likelihood of an event occurring given that another event has already taken place. Rather than looking at the probability of an event in isolation, it considers additional information that might affect the odds.
In our HIV example, conditional probability is used to determine the likelihood that an individual has HIV after receiving a positive result on the ELISA test. This question isn't about the general probability of having HIV but rather "Given a positive test result, what is the probability of actually having the disease?"
Understanding conditional probability involves Bayes' Theorem, which combines separate probabilities to calculate the likelihood of an event based on prior data. Bayes' Theorem in this scenario is crucial because it helps sift through the test's accuracy and prevalence to yield a more accurate post-test probability.
HIV Testing Accuracy
Accuracy in HIV testing is paramount as it affects both the diagnosis and subsequent treatment plans. When dealing with HIV, testing accuracy represents two main terms: sensitivity and specificity.
  • **Sensitivity** refers to the test's ability to correctly identify those with the disease (true positive rate).
  • **Specificity** is the capacity to correctly identify those without the disease (true negative rate).
For the ELISA test discussed in the exercise, the sensitivity is 99.7%, which means it correctly identifies 99.7% of individuals with HIV. The specificity, at 92.6%, shows how often the test correctly identifies those without HIV. These two rates collectively define the test's accuracy and reveal how often the test might give false results.
In practical terms, a test with high sensitivity but lower specificity, as in this case, indicates that false positives may occur, necessitating further confirmatory testing to ensure accurate diagnosis.
ELISA Test Statistics
The ELISA test, or Enzyme-Linked Immunosorbent Assay, is one of the earliest and most common methods employed for HIV testing. It employs antibodies to detect the presence of antigens or pathogens like HIV in a person's blood.
The statistics associated with ELISA, like sensitivity and specificity, are central to its evaluation. High sensitivity suggests it’s unlikely to miss patients who actually have HIV, while specificity addresses how many false positives might occur.
While ELISA is known for its reliability, it's not perfect – false positives can lead to stress and anxiety for individuals who receive a positive test. Hence, the statistics behind the test come into play, aiding in revealing how reliable the test is and when additional tests might be needed to confirm results.

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Most popular questions from this chapter

Guessing on an exam. In a multiple choice exam, there are 5 questions and 4 choices for each question \((\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}) .\) Nancy has not studied for the exam at all and decides to randomly guess the answers. What is the probability that: (a) the first question she gets right is the \(5^{t h}\) question? (b) she gets all of the questions right? (c) she gets at least one question right?

True or false. Determine if the statements below are true or false, and explain your reasoning. (a) If a fair coin is tossed many times and the last eight tosses are all heads, then the chance that the next toss will be heads is somewhat less than \(50 \%\). (b) Drawing a face card (jack, queen, or king) and drawing a red card from a full deck of playing cards are mutually exclusive events. (c) Drawing a face card and drawing an ace from a full deck of playing cards are mutually exclusive events.

The table below shows the distribution of books on a bookcase based on whether they are nonfiction or fiction and hardcover or paperback. $$\begin{array}{lccc} & {\text { Format }} & \\ & \text { Hardcover } & \text { Paperback } & \text { Total } \\ \hline \text { Fiction } & 13 & 59 & 72 \\ \text { Nonfiction } & 15 & 8 & 23 \\ \hline \text { Total } & 28 & 67 & 95 \\ \hline\end{array}$$ (a) Find the probability of drawing a hardcover book first then a paperback fiction book second when drawing without replacement. (b) Determine the probability of drawing a fiction book first and then a hardcover book second, when drawing without replacement. (c) Calculate the probability of the scenario in part (b), except this time complete the calculations under the scenario where the first book is placed back on the bookcase before randomly drawing the second book. (d) The final answers to parts (b) and (c) are very similar. Explain why this is the case.

The relative frequency table below displays the distribution of annual total personal income (in 2009 inflation-adjusted dollars) for a representative sample of 96,420,486 Americans. These data come from the American Community Survey for 2005-2009. This sample is comprised of \(59 \%\) males and \(41 \%\) females. \({ }^{63}\) (a) Describe the distribution of total personal income. (b) What is the probability that a randomly chosen US resident makes less than $$\$ 50,000$$ per year? (c) What is the probability that a randomly chosen US resident makes less than $$\$ 50,000$$ per year and is female? Note any assumptions you make. (d) The same data source indicates that \(71.8 \%\) of females make less than $$\$ 50,000$$ per year. Use this value to determine whether or not the assumption you made in part (c) is valid. $$\begin{array}{lr}\hline \text { Income } & \text { Total } \\ \hline \$ 1 \text { to } \$ 9,999 \text { or loss } & 2.2 \% \\ \$ 10,000 \text { to } \$ 14,999 & 4.7 \% \\ \$ 15,000 \text { to } \$ 24,999 & 15.8 \% \\ \$ 25,000 \text { to } \$ 34,999 & 18.3 \% \\ \$ 35,000 \text { to } \$ 49,999 & 21.2 \% \\ \$ 50,000 \text { to } \$ 64,999 & 13.9 \% \\ \$ 65,000 \text { to } \$ 74,999 & 5.8 \% \\ \$ 75,000 \text { to } \$ 99,999 & 8.4 \% \\ \$ 100,000 \text { or more } & 9.7 \% \\ \hline\end{array}$$

\(\mathrm{P}(\mathrm{A})=0.3, \mathrm{P}(\mathrm{B})=0.7\) (a) Can you compute \(\mathrm{P}(\mathrm{A}\) and \(\mathrm{B})\) if you only know \(\mathrm{P}(\mathrm{A})\) and \(\mathrm{P}(\mathrm{B}) ?\) (b) Assuming that events \(A\) and \(B\) arise from independent random processes, i. what is \(\mathrm{P}(\mathrm{A}\) and \(\mathrm{B}) ?\) ii. what is \(\mathrm{P}(\mathrm{A}\) or \(\mathrm{B}) ?\) iii. what is \(\mathrm{P}(\mathrm{A} \mid \mathrm{B}) ?\) (c) If we are given that \(\mathrm{P}(\mathrm{A}\) and \(\mathrm{B})=0.1,\) are the random variables giving rise to events \(\mathrm{A}\) and \(\mathrm{B}\) independent? (d) If we are given that \(\mathrm{P}(\mathrm{A}\) and \(\mathrm{B})=0.1\), what is \(\mathrm{P}(\mathrm{A} \mid \mathrm{B}) ?\)

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