Chapter 9: Problem 1
Man untersuche die Lösbarkeit der linearen Randwertaufgabe$$ y^{\prime \prime}+y=1 $$ unter den verschiedenen Randbedingungen a) \(\quad y(0)=0, \quad y(\pi / 2)=1\), b) \(\quad y(0)=0, \quad y(\pi)=1\) c) \(y(0)=0, \quad y(\pi)=2\), auf Grund der allgemeinen Theorie mit Hilfe der Fun damentalmatrix des homogenen Differenzialgleichungssystems.
Short Answer
Step by step solution
Find the general solution to the homogeneous equation
Find a particular solution to the non-homogeneous equation
Form the general solution to the non-homogeneous equation
Apply boundary conditions for scenario (a)
Analyze solvability for scenario (b)
Analyze solvability for scenario (c)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Randwertprobleme
- Scenario (a): The conditions are set as \( y(0) = 0 \) and \( y(\pi/2) = 1 \). After substituting these values, we found a solution with specific values for the constants.
- Scenario (b): The conditions \( y(0) = 0 \) and \( y(\pi) = 1 \) led to an inconsistency, indicating no solutions exist.
- Scenario (c): With \( y(0) = 0 \) and \( y(\pi) = 2 \), the conditions were satisfied, allowing for infinitely many solutions.
Fundamentalmatrix
For our differential equation \( y'' + y = 0 \), the homogeneous equation, the characteristic roots are \( r = i \) and \( r = -i \). These roots lead us to the general solution for the homogeneous part, often written with sinusoidal functions due to the imaginary roots:
- \( y_h(x) = C_1 \cos(x) + C_2 \sin(x) \)
Homogene Differenzialgleichungen
The solutions to these equations primarily rely on the roots of their characteristic equations. For \( y'' + y = 0 \), the characteristic equation \( r^2 + 1 = 0 \) results in complex roots \( r = i \) and \( r = -i \). The general solution involves:
- Trigonometric functions, such as \( \cos(x) \) and \( \sin(x) \), due to the nature of imaginary roots.
- Coefficients \( C_1 \) and \( C_2 \), representing the amplitudes of these functions.
Partikuläre Lösung
For the equation \( y'' + y = 1 \), the particular solution aims to balance the equation by considering the free term (\(1\) in this case). The particular solution is found by proposing a simple constant solution, since the non-homogeneous term is constant:
- Assume \( y_p = A \), a constant solution.
- Balancing the equation by substituting gives \( A = 1 \).