Chapter 4: Problem 8
Zur Lösung des nichtlinearen Gleichungssystems $$ \begin{aligned} &4.72 \sin (2 x)-3.14 e^{y}-0.495=0 \\ &3.61 \cos (3 x)+\sin (y)-0.402=0 \end{aligned} $$ verwende man mit den Startwerten \(x^{(0)}=1.5, y^{(0)}=-4.7\) das Verfahren von Newton, das vereinfachte Verfahren von Newton, das Newtonsche Einzelschrittverfahren und das SOR-NewtonVerfahren für verschiedene Werte von \(\omega .\)
Short Answer
Step by step solution
Understand the Problem
Understanding Newton's Method Basics
Solve Using Standard Newton's Method
Simplified Newton's Method
Single-Step Newton's Method
SOR-Newton Method
Calculate and Compare Results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Newton's Method
- \[ x^{(k+1)} = x^{(k)} - J^{-1}(x^{(k)})F(x^{(k)}) \]
Nonlinear Systems
- These systems can have multiple solutions or none at all.
- Sensitivity to initial conditions can lead to vastly different results.
Jacobian Matrix
- For a function \( F(x) = [f_1(x,y), f_2(x,y)] \), the Jacobian \( J \) will be: \[ J(x,y) = \begin{bmatrix} \frac{\partial f_1}{\partial x} & \frac{\partial f_1}{\partial y} \\frac{\partial f_2}{\partial x} & \frac{\partial f_2}{\partial y} \end{bmatrix} \]
- It assesses how changes in one variable affect others, providing crucial information for iterative adjustment.
Successive Over-Relaxation
- The formula is: \[x^{(k+1)} = x^{(k)} + \omega (x_\text{Newton} - x^{(k)})\]
- Here, \( \omega \) is a factor between 0 and 2, controlling the portion of the Newton step added to the current approximation.
Convergence Analysis
- **Rate of Convergence:** Describes the speed at which a sequence approaches its limit. For Newton's Method, it is typically quadratic, meaning it doubles the number of correct digits at every step under ideal conditions.
- **Precision:** Ensures that the method approximates the solution to the desired accuracy.