Chapter 6: Problem 22
$$ \begin{array}{l} \text { Determine the Newton interpolating polynomial for this table: }\\\ \begin{array}{l||r|r|r|r} x & 0 & 1 & 2 & 7 \\ \hline y & 51 & 3 & 1 & 201 \end{array} \end{array} $$
Short Answer
Expert verified
Newton's polynomial is \( P(x) = 51 - 48x + 23x(x-1) - \frac{16}{7}x(x-1)(x-2) \).
Step by step solution
01
Set up Divided Difference Table
Create a table with columns for each order of divided differences. Begin with the given values, starting with the table of values for \(x\) and \(y\).\[\begin{array}{c|c|c|c|c}x & f[x] & f[x_0,x_1] & f[x_0,x_1,x_2] & f[x_0,x_1,x_2,x_3] \ \hline0 & 51 & & & \1 & 3 & & & \2 & 1 & & & \7 & 201 & & & \\end{array}\]
02
Compute First Divided Differences
Calculate the first divided differences using the formula: \[ f[x_i, x_{i+1}] = \frac{f[x_{i+1}] - f[x_i]}{x_{i+1} - x_i} \]Apply this to the pairs (0,1), (1,2), and (2,7):\[ f[0,1] = \frac{3 - 51}{1 - 0} = -48 \]\[ f[1,2] = \frac{1 - 3}{2 - 1} = -2 \]\[ f[2,7] = \frac{201 - 1}{7 - 2} = 40 \]Update the table:\[\begin{array}{c|c|c|c|c}x & f[x] & f[x_0,x_1] & f[x_0,x_1,x_2] & f[x_0,x_1,x_2,x_3] \ \hline0 & 51 & -48 & & \1 & 3 & -2 & & \2 & 1 & 40 & & \7 & 201 & & & \\end{array}\]
03
Compute Second Divided Differences
Calculate the second divided differences using:\[ f[x_i, x_{i+1}, x_{i+2}] = \frac{f[x_{i+1}, x_{i+2}] - f[x_i, x_{i+1}]}{x_{i+2} - x_i} \]Apply this for the triples (0,1,2) and (1,2,7):\[ f[0,1,2] = \frac{-2 + 48}{2 - 0} = 23 \]\[ f[1,2,7] = \frac{40 + 2}{7 - 1} = 7 \]Update the table:\[\begin{array}{c|c|c|c|c}x & f[x] & f[x_0,x_1] & f[x_0,x_1,x_2] & f[x_0,x_1,x_2,x_3] \ \hline0 & 51 & -48 & 23 & \1 & 3 & -2 & 7 & \2 & 1 & 40 & & \7 & 201 & & & \\end{array}\]
04
Compute Third Divided Difference
Calculate the third divided difference using:\[ f[x_i, x_{i+1}, x_{i+2}, x_{i+3}] = \frac{f[x_{i+1}, x_{i+2}, x_{i+3}] - f[x_i, x_{i+1}, x_{i+2}]}{x_{i+3} - x_i} \]Use for (0,1,2,7):\[ f[0,1,2,7] = \frac{7 - 23}{7 - 0} = -\frac{16}{7} \]Complete the table:\[\begin{array}{c|c|c|c|c}x & f[x] & f[x_0,x_1] & f[x_0,x_1,x_2] & f[x_0,x_1,x_2,x_3] \ \hline0 & 51 & -48 & 23 & -\frac{16}{7} \1 & 3 & -2 & 7 & \2 & 1 & 40 & & \7 & 201 & & & \\end{array}\]
05
Write the Newton Polynomial
Combine the calculated divided differences into the Newton polynomial:\[ P(x) = f[x_0] + f[x_0, x_1](x - x_0) + f[x_0, x_1, x_2](x - x_0)(x - x_1) + f[x_0, x_1, x_2,x_3](x - x_0)(x - x_1)(x - x_2) \]Insert the values:\[ P(x) = 51 - 48(x - 0) + 23(x - 0)(x - 1) - \frac{16}{7}(x - 0)(x - 1)(x - 2) \]Simplify the expression.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Divided Differences
Divided differences are a fundamental tool in constructing the Newton interpolating polynomial. They essentially help in determining the coefficients of the polynomial. The divided differences are computed in a hierarchical manner, depending on the order.
- First Order Divided Differences: These are calculated between consecutive pairs of points. For example, given two points \( (x_0, y_0) \) and \( (x_1, y_1) \), the first divided difference is \( f[x_0, x_1] = \frac{y_1 - y_0}{x_1 - x_0} \).
- Second Order and Higher: The next level is calculated using previously computed divided differences. For instance, \( f[x_0, x_1, x_2] = \frac{f[x_1, x_2] - f[x_0, x_1]}{x_2 - x_0} \).
Newton's Method
Newton's Method for interpolation is not to be confused with Newton's Method for finding roots. In interpolation, it focuses on finding a polynomial that fits a given set of data points. The method uses a recursive approach to construct the interpolating polynomial in a form known as the Newton form. This approach involves starting with a base value (the first y-value in our table) and then adding terms sequentially. Each new term represents the addition of a new point to the interpolating polynomial. The format for the polynomial grows as:\[P(x) = f[x_0] + f[x_0, x_1](x - x_0) + f[x_0, x_1, x_2](x - x_0)(x - x_1) + \ldots\]This method is especially convenient because it allows for easy updating of the polynomial when new data points are added.
Polynomial Interpolation
Polynomial interpolation is a process of estimating a polynomial that fits a set of data points exactly. When given a table of values \( x \) and corresponding \( y \), the goal is to find a polynomial \( P(x) \) such that \( P(x_i) = y_i \) for each data point \( (x_i, y_i) \). Newton's divided differences provide a systematic way to build this polynomial. Key aspects of polynomial interpolation include:
- Exact Fit: The polynomial passes through all the data points exactly.
- Unique Solution: For \( n+1 \) data points, there exists a unique polynomial of degree \( n \) that interpolates the data.
- Smoothness: The resulting polynomial generally provides a smooth curve that represents trends in the data.