Chapter 4: Problem 10
Prove that for any vector norm and its subordinate matrix norm, and for any \(n \times n\) matrix \(A\), there corresponds a vector \(x \neq 0\) such that \(\|A x\|=\|A\|\|x\|\).
Short Answer
Expert verified
There exists a vector \(x \neq 0\) with \(\|x\|=1\) such that \(\|Ax\|=\|A\|\|x\|\).
Step by step solution
01
Understanding the Problem
We need to show that for any matrix norm \( \|A\| \), which is subordinate to a vector norm \( \|\cdot\| \), there exists a vector \( x eq 0 \) such that the equality \( \|Ax\| = \|A\| \|x\| \) holds true. Here, \( Ax \) denotes the matrix-vector product.
02
Defining Subordinate Matrix Norm
A matrix norm \( \|A\| \) is called subordinate to a vector norm if for all vectors \( x \), \( \|Ax\| \leq \|A\| \|x\| \). This means the matrix norm is defined in terms of the vector norm.
03
Choosing the Vector x
By the definition of the subordinate matrix norm, \( \|A\| = \max_{\|x\| = 1} \|Ax\| \). This implies that there exists at least one vector \( x \) with \( \|x\| = 1 \) such that \( \|Ax\| = \|A\| \).
04
Proving the Existence of Vector x
The existence of a vector \( x \) for which \( \|Ax\| = \|A\| \) (with the constraint \( \|x\| = 1 \)) directly implies that \( \|Ax\| = \|A\| \|x\| \) since \( \|x\| = 1 \). Hence, there exists a non-zero vector satisfying the equation for a given \( A \).
05
Confirming the Non-Zero Condition
Since the supremum is taken over vectors \( x \) with \( \|x\| = 1 \), the vector \( x \) is non-zero, fulfilling the requirement of \( x eq 0 \) in the statement \( \|Ax\| = \|A\| \|x\| \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Norm
A vector norm is a function that assigns a positive length or size to each vector in a vector space, except the zero vector which is assigned a length of zero. It is denoted as \( \|x\| \) for a vector \( x \). There are different types of vector norms, each measuring the size of the vector in slightly different ways:
- **Euclidean Norm:** This is the most common type of vector norm, also known as the \( L^2 \) norm, which calculates the "straight-line" distance from the origin to the point \( x \). It is represented by \( \|x\|_2 = \sqrt{x_1^2 + x_2^2 + ... + x_n^2} \).
- **Manhattan Norm:** Also known as the \( L^1 \) norm, it is the sum of the absolute values of the vector components, \( \|x\|_1 = |x_1| + |x_2| + ... + |x_n| \).
- **Infinity Norm:** The maximum absolute value of the vector components, \( \|x\|_\infty = \max(|x_1|, |x_2|, ..., |x_n|) \).
Matrix-Vector Product
The matrix-vector product is the result of multiplying a matrix with a vector, producing another vector. If \( A \) is an \( n \times n \) matrix and \( x \) is a vector with \( n \) elements, then the matrix-vector product \( Ax \) is defined in such a way that each element of the resulting vector is a linear combination of the columns of the matrix \( A \).
Mathematically, this can be expressed as:
This operation is fundamental in linear algebra and has applications in various fields such as computer graphics, machine learning, and engineering. The matrix-vector product is instrumental in expressing systems of linear equations and transformations.
Mathematically, this can be expressed as:
- The vector \( Ax \) at position \( i \) is equal to the dot product of the \( i \)-th row of \( A \) and the vector \( x \), or \( (Ax)_i = a_{i1}x_1 + a_{i2}x_2 + ... + a_{in}x_n \).
This operation is fundamental in linear algebra and has applications in various fields such as computer graphics, machine learning, and engineering. The matrix-vector product is instrumental in expressing systems of linear equations and transformations.
Existence of Vector
In the context of subordinate matrix norms, we aim to find a specific vector that satisfies certain conditions involving matrix norms. The statement we are exploring asserts that, for any matrix \( A \) and its subordinate matrix norm \( \|A\| \), there exists a non-zero vector \( x \) such that \( \|Ax\| = \|A\|\|x\| \).
To prove this, consider that the subordinate matrix norm is defined as \( \|A\| = \max_{\|x\|=1} \|Ax\| \). This implies there exists at least one unit vector \( x \) such that \( \|Ax\| \) achieves this maximum value \( \|A\| \).
To prove this, consider that the subordinate matrix norm is defined as \( \|A\| = \max_{\|x\|=1} \|Ax\| \). This implies there exists at least one unit vector \( x \) such that \( \|Ax\| \) achieves this maximum value \( \|A\| \).
- The phrase "unit vector" means \( \|x\| = 1 \), so these unit vectors are not the zero vector, automatically fulfilling the non-zero criterion.
- This vector \( x \) shows that the matrix-vector product maintains the equality \( \|Ax\| = \|A\|\|x\| \). It reflects that the scalar stretching by the matrix \( A \) has a specific vector direction for which the matrix applies its maximum effect.