Chapter 1: Problem 1
Show that \(\left|x^{2}-4\right|<\varepsilon\) when \(0<|x-2|<\varepsilon(5+\varepsilon)^{-1}\) and prove \(\lim _{x \rightarrow 2} x^{2}=4\) by using these inequalities.
Short Answer
Expert verified
Given \(0<|x-2|<\frac{\varepsilon}{5+\varepsilon}\), it ensures \(|x^2-4|<\varepsilon\), proving \(\lim_{x \to 2} x^2 = 4\).
Step by step solution
01
Understand the Given Inequality
The goal is to show that \[ \left| x^{2} - 4 \right| < \varepsilon \]when \[ 0 < |x-2| < \frac{\varepsilon}{5+\varepsilon}. \]This means we are looking to manipulate the expression for \( \left| x^2 - 4 \right| \) in such a way that it can be related to the given condition on \( |x-2| \).
02
Expand and Simplify the Expression
Notice that\[ x^2 - 4 = (x - 2)(x + 2). \]Therefore,\[ |x^2 - 4| = |x - 2| \cdot |x + 2|. \]The approach will be to connect \(|x-2|\) and \(|x+2|\) to the function \(\varepsilon\).
03
Bind |x + 2| to a Range
Since\[ 0 < |x-2| < \frac{\varepsilon}{5+\varepsilon}, \]we can determine a range for \(|x+2|\). Since \(|x-2|\) is small, assume \(x\) is close to 2. For practical manipulation set, consider\[ x = 2 + \delta \]where \delta\ is such that \( |\delta| < \frac{\varepsilon}{5+\varepsilon} \). This indicates\[ |x + 2| = |2 + \delta + 2| = |4 + \delta|. \]
04
Use Triangle Inequality
We approximate using the triangle inequality:\[ |4 + \delta| \leq 4 + |\delta|. \]Given \( |\delta| < \frac{\varepsilon}{5+\varepsilon}, \)\[ |4 + \delta| < 4 + \frac{\varepsilon}{5+\varepsilon}. \] Thus, multiply this by \(|x-2|\):\[ |x^2 - 4| < \frac{\varepsilon}{5+\varepsilon} \cdot (4 + \frac{\varepsilon}{5+\varepsilon}). \]
05
Simplify and Recognize the Condition
Rewrite the expression:\[ (4 + \frac{\varepsilon}{5+\varepsilon}) = \frac{4(5+\varepsilon) + \varepsilon}{5+\varepsilon} = \frac{20 + 4\varepsilon + \varepsilon}{5+\varepsilon} = \frac{20 + 5\varepsilon}{5+\varepsilon}. \]Thus,\[ \left|x^{2}-4\right| < \frac{\varepsilon}{5+\varepsilon} \cdot \frac{20 + 5\varepsilon}{5+\varepsilon} = \varepsilon. \]Hence, the inequality \(|x^{2}-4|<\varepsilon\) is satisfied.
06
Prove the Limit
We are now in a position to prove that \( \lim_{x \to 2} x^2 = 4 \). The definition of this limit is for every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that whenever \( 0 < |x-2| < \delta \), it follows that \( |x^2 - 4| < \varepsilon \). In this case, we have shown that if \[ \delta = \frac{\varepsilon}{5+\varepsilon}, \]then \(|x^2 - 4| < \varepsilon\), thus proving the limit statement.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
limit proof
In mathematical analysis, proving a limit revolves around introducing a rigorous framework that ensures a specified condition is always met. Think of it as showing that as the input to a function (in this case, value of \( x \)) gets closer to a number (here, 2), the output of the function (\( x^2\)) approaches a particular value (4).
To establish the limit \( \lim_{x \to 2} x^2 = 4 \), we need to manipulate expressions using basic algebraic operations and inequalities. The task is to ensure that the proximity between \( x^2 \) and 4 can be made as small as desired by restricting how close \( x \) is to 2.
In practical terms, this involves demonstrating that whenever \( x \) lies within a certain distance (\( \delta \)) from 2, \( x^2 \) lies within a similar tight range from 4. The core of the proof lies in defining such precise bounds.
To establish the limit \( \lim_{x \to 2} x^2 = 4 \), we need to manipulate expressions using basic algebraic operations and inequalities. The task is to ensure that the proximity between \( x^2 \) and 4 can be made as small as desired by restricting how close \( x \) is to 2.
In practical terms, this involves demonstrating that whenever \( x \) lies within a certain distance (\( \delta \)) from 2, \( x^2 \) lies within a similar tight range from 4. The core of the proof lies in defining such precise bounds.
epsilon-delta definition
The epsilon-delta definition is a formal way to describe limits in calculus. It's like building a logical map that shows how small changes in inputs (\( x \)) affect the outcome (\( x^2 - 4 \)).
The definition works on an 'if-and-only-if' basis: For every \( \varepsilon > 0 \) (epsilon), representing the maximum allowable error in \( x^2 - 4 \), there exists a corresponding \( \delta > 0 \) (delta), setting a permissible error margin for \( x - 2 \). This delta defines how tightly \( x \) must hug the number 2.
The definition works on an 'if-and-only-if' basis: For every \( \varepsilon > 0 \) (epsilon), representing the maximum allowable error in \( x^2 - 4 \), there exists a corresponding \( \delta > 0 \) (delta), setting a permissible error margin for \( x - 2 \). This delta defines how tightly \( x \) must hug the number 2.
- First, choose an \( \varepsilon > 0 \), dictating how close \( x^2 \) must be to 4.
- Next, find a \( \delta \) such that for every \( x \) within \( \delta \) of 2, \( |x^2 - 4| < \varepsilon \).
inequalities in calculus
Inequalities are a powerful tool in calculus, used to form bounds and constrain variables effectively. When proving limits, they help ensure that expressions remain within a certain range.
In proving \( \lim _{x \to 2} x^2 = 4 \), we manipulate inequalities like \( |x^2 - 4| < \varepsilon \) using algebraic rewriting and known inequalities.
In proving \( \lim _{x \to 2} x^2 = 4 \), we manipulate inequalities like \( |x^2 - 4| < \varepsilon \) using algebraic rewriting and known inequalities.
- Start by expressing \( x^2 - 4 \)) as a product: \( (x - 2)(x + 2) \).
- Use properties like the triangle inequality to simplify and set bounds.
- Combine known conditions (e.g., \( |x-2| < \frac{\varepsilon}{5+\varepsilon} \)) to pin down the range \( |x + 2| \) can take.