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Show that the following pairs of matrices are not similar. a. \(\quad A=\left[\begin{array}{ll}1 & 1 \\ 0 & 3\end{array}\right]\) and \(\quad B=\left[\begin{array}{ll}2 & 2 \\ 1 & 2\end{array}\right]\) b. \(\quad A=\left[\begin{array}{rr}1 & 1 \\ 2 & -2\end{array}\right]\) and \(\quad B=\left[\begin{array}{rr}-1 & 2 \\ 1 & 2\end{array}\right]\) c. \(A=\left[\begin{array}{rrr}1 & 1 & -1 \\ -1 & 0 & 1 \\ 0 & 1 & 1\end{array}\right]\) and \(\quad B=\left[\begin{array}{rrr}2 & -2 & 0 \\ -2 & 0 & 2 \\ 2 & 2 & -2\end{array}\right]\) d. \(\quad A=\left[\begin{array}{rrr}1 & 1 & -1 \\ 2 & -2 & 2 \\ -3 & 3 & 3\end{array}\right]\) and \(B=\left[\begin{array}{lll}1 & 2 & 1 \\ 2 & 3 & 2 \\\ 0 & 1 & 0\end{array}\right]\)

Short Answer

Expert verified
All given matrix pairs (a, b, c, d) are not similar as either their traces or determinants (or both) are not equal.

Step by step solution

01

Calculating trace and determinant for pair a

Trace of A = \(1 + 3 = 4\) and determinant of A = \(1*3 - 0*1 = 3\). Trace of B = \(2 + 2 = 4\) and determinant of B = \(2*2 - 2*1 = 2\). As the determinants are not equal, A and B are not similar.
02

Calculating trace and determinant for pair b

Trace of A = \(1 + -2 = -1\) and determinant of A = \(1*(-2) - 1*2 = -4\). Trace of B = \(-1 + 2 = 1\) and determinant of B = \(-1*2 - 2*1 = -4\). Even though the determinants are equal, the traces are not, so A and B are not similar.
03

Calculating trace and determinant for pair c

Trace of A = \(1 + 0 + 1 = 2\) and the determinant of A = \(1*(0*1 - 1*1) - 1*( -1*(1*1 - 1*1) + 1*(0*1 - -1*1) = 0\). Trace of B = \(2 + 0 - 2 = 0\) and determinant of B = \(2*(-2*(-2) - 0*2) - -2*(2*0 - 0*2) + 0*0 - 2*2 = 0\). Thus, despite A and B having equal determinants, their traces are different, so they are not similar.
04

Calculating trace and determinant for pair d

Trace of A = \(1 - 2 + 3 = 2\) and determinant of A = \(1*(-2*3 - 2*3) - 1*(1*3 + 2*(-3)) + -1*(1*2 - 2*1) = -9\). Trace of B = \(1 + 3 + 0 = 4\) and determinant of B = \(1*(3*0 - 2*2) - 2*(2*0 - 1*2) + 1*(2*1 - 2*2) = -5\). As both the traces and determinants are different, A and B are not similar.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues
Eigenvalues are fundamental in determining the properties of a matrix. They are best thought of as special numbers that stretch or shrink vectors when multiplied by a matrix. For a matrix \( A \), an eigenvalue \( \lambda \) satisfies the equation: \( A\mathbf{v} = \lambda \mathbf{v} \), where \( \mathbf{v} \) is a non-zero vector called an eigenvector.
  • Finding eigenvalues involves solving the characteristic equation \( \text{det}(A - \lambda I) = 0 \), where \( I \) is the identity matrix.
  • The eigenvalues of similar matrices are the same, highlighting their importance in matrix similarity.
When considering the similarity between two matrices, comparing their eigenvalues is crucial. If the eigenvalues are different, the matrices cannot be similar. This is because similarity doesn't change the spectrum of a matrix.
Matrix Trace
The trace of a matrix, usually denoted as \( \text{tr}(A) \), is the sum of its diagonal elements. For a matrix \( A = \left[ \begin{array}{ccc} a_{11} & a_{12} & a_{13} \ a_{21} & a_{22} & a_{23} \ a_{31} & a_{32} & a_{33} \end{array} \right] \), the trace is \( a_{11} + a_{22} + a_{33} \).
  • The trace is invariant under similarity transformations, meaning if matrices \( A \) and \( B \) are similar, \( \text{tr}(A) = \text{tr}(B) \).
  • It's a simple, yet powerful tool to quickly assess matrix equivalence along with determinant.
In matrix similarity problems, comparing the trace helps determine non-similarity quickly. If the traces are not the same, the matrices cannot be similar.
Matrix Determinant
Matrix determinant is a scalar value that provides significant insights into a matrix's properties. For a 2x2 matrix \( A = \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \), the determinant is computed as \( ad - bc \). For larger matrices, calculations involve co-factors and are more complex.
  • Determinant indicates if a matrix is invertible; a non-zero determinant means the matrix has an inverse.
  • Determinants are constant under similarity transformations. Thus, checking determinants of matrices can confirm or refute similarity if they differ.
In the context of checking matrix similarity, if two matrices have different determinants, they are not similar. This is a definitive condition because the transformation that makes them similar implies identical determinants.
Linear Algebra
Linear Algebra is a branch of mathematics focused on vector spaces and linear mappings between them. It deals not only with vectors and matrices but with operations such as matrix multiplication, inversion, and finding characteristics like eigenvalues and determinants.
  • Matrices represent linear transformations, a key concept in linear algebra.
  • Understanding concepts like matrix similarity helps reveal the broader idea of how different transformations can act in equivalent ways.
When working with matrices, linear algebra provides the foundational tools to solve systems of equations, transforms, and analyze datasets. Its principles are applied in physics, computer science, engineering, and more. Therefore, grasping these basics, such as working with matrices and understanding similarities, is crucial for advancing in any related field.

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Most popular questions from this chapter

Find the eigenvalues and associated eigenvectors of the following \(3 \times 3\) matrices. Is there a set of linearly independent eigenvectors? a. \(\quad A=\left[\begin{array}{rrr}2 & -3 & 6 \\ 0 & 3 & -4 \\ 0 & 2 & -3\end{array}\right]\) b. \(\quad A=\left[\begin{array}{lll}2 & 0 & 1 \\ 0 & 2 & 0 \\ 1 & 0 & 2\end{array}\right]\) c. \(A=\left[\begin{array}{lll}1 & 1 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 1\end{array}\right]\) d. \(\quad A=\left[\begin{array}{rrr}2 & 1 & -1 \\ 0 & 2 & 1 \\ 0 & 0 & 3\end{array}\right]\)

Modify Householder's Algorithm \(9.5\) to compute similar upper Hessenberg matrices for the following nonsymmetric matrices. a. \(\left[\begin{array}{rrr}2 & -1 & 3 \\ 2 & 0 & 1 \\ -2 & 1 & 4\end{array}\right]\) b. \(\left[\begin{array}{rrr}-1 & 2 & 3 \\ 2 & 3 & -2 \\ 3 & 1 & -1\end{array}\right]\) c. \(\left[\begin{array}{rrrr}5 & -2 & -3 & 4 \\ 0 & 4 & 2 & -1 \\ 1 & 3 & -5 & 2 \\ -1 & 4 & 0 & 3\end{array}\right]\) d. \(\left[\begin{array}{rrrr}4 & -1 & -1 & -1 \\ -1 & 4 & 0 & -1 \\ -1 & -1 & 4 & -1 \\ -1 & -1 & -1 & 4\end{array}\right]\)

Use Householder's method to place the following matrices in tridiagonal form. a. \(\left[\begin{array}{rrr}12 & 10 & 4 \\ 10 & 8 & -5 \\ 4 & -5 & 3\end{array}\right]\) b. \(\left[\begin{array}{rrr}2 & -1 & -1 \\ -1 & 2 & -1 \\ -1 & -1 & 2\end{array}\right]\) c. \(\left[\begin{array}{lll}1 & 1 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 1\end{array}\right]\) d. \(\left[\begin{array}{rrr}4.75 & 2.25 & -0.25 \\ 2.25 & 4.75 & 1.25 \\\ -0.25 & 1.25 & 4.75\end{array}\right]\)

Jacobi's method for a symmetric matrix \(A\) is described by $$ \begin{aligned} &A_{1}=A \\ &A_{2}=P_{1} A_{1} P_{1}^{t} \end{aligned} $$ and, in general, $$ A_{i+1}=P_{i} A_{i} P_{i}^{t} $$ The matrix \(A_{i+1}\) tends to a diagonal matrix, where \(P_{i}\) is a rotation matrix chosen to eliminate a large off-diagonal element in \(A_{i}\). Suppose \(a_{j, k}\) and \(a_{k, j}\) are to be set to 0 , where \(j \neq k\). If \(a_{i j} \neq a_{k k}\), then $$ \left(P_{i}\right)_{i j}=\left(P_{i}\right)_{k k}=\sqrt{\frac{1}{2}\left(1+\frac{b}{\sqrt{c^{2}+b^{2}}}\right)}, \quad\left(P_{i}\right)_{k j}=\frac{c}{2\left(P_{i}\right)_{j j} \sqrt{c^{2}+b^{2}}}=-\left(P_{i}\right)_{j k} $$ where $$ c=2 a_{j k} \operatorname{sgn}\left(a_{i j}-a_{k k}\right) \quad \text { and } \quad b=\left|a_{j j}-a_{k k}\right| $$ or if \(a_{i j}=a_{k k}\), $$ \left(P_{i}\right)_{j j}=\left(P_{i}\right)_{k k}=\frac{\sqrt{2}}{2} $$ and $$ \left(P_{i}\right)_{k j}=-\left(P_{i}\right)_{j k}=\frac{\sqrt{2}}{2} $$ Develop an algorithm to implement Jacobi's method by setting \(a_{21}=0\). Then set \(a_{31}, a_{32}, a_{41}, a_{42}\), \(a_{43}, \ldots, a_{n, 1}, \ldots, a_{n, n-1}\) in turn to zero.This is repeated until a matrix \(A_{k}\) is computed with $$ \sum_{i=1}^{n} \sum_{j=1 \atop j \neq i}^{n}\left|a_{i j}^{(k)}\right| $$ sufficiently small. The eigenvalues of \(A\) can then be approximated by the diagonal entries of \(A_{k}\).

a. Show that the rotation matrix $$ \left[\begin{array}{rr} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{array}\right] $$ applied to the vector \(\mathbf{x}=\left(x_{1}, x_{2}\right)^{t}\) has the geometric effect of rotating \(\mathbf{x}\) through the angle \(\theta\) without changing its magnitude with respect to the \(l_{2}\) norm. b. Show that the magnitude of \(\mathbf{x}\) with respect to the \(l_{\infty}\) norm can be changed by a rotation matrix.

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