/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Suppose that the \(m \times n\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that the \(m \times n\) matrix \(A\) has the singular value decomposition \(A=U S V^{t}\). Express the Nullity \((A)\) in terms of \(\operatorname{Rank}(S)\).

Short Answer

Expert verified
The Nullity of \(A\) is equal to \(n -\) Rank of \(S\).

Step by step solution

01

Understanding matrix A

We are given that the matrix \(A\) has the singular value decomposition \(A=U S V^t\), where \(U\) and \(V\) are orthogonal matrices and \(S\) is a diagonal matrix containing the singular values of \(A\) in descending order. The dimensions of \(A\) are \(m \times n\).
02

Recall the definitions of Nullity and Rank

In linear algebra, the Nullity of a matrix \(A\) is the dimension of the null space of \(A\), i.e., the number of linearly independent solutions of the homogeneous equation \(Ax = 0\). The Rank of a matrix \(A\) is the maximum number of linearly independent rows (or columns) in \(A\). Based on the rank-nullity theorem, for any \(m \times n\) matrix \(A\), the Rank of \(A\) plus the Nullity of \(A\) is equal to \(n\), the number of columns of \(A\).
03

Relate the Nullity of A to the Rank of S

Since \(S\) is a diagonal matrix containing the singular values of \(A\), the Rank of \(S\) is also the Rank of \(A\). Therefore, we can replace the Rank of \(A\) in the rank-nullity theorem with the Rank of \(S\). This gives us that the Nullity of \(A\) equals \(n -\) Rank of \(S\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nullity of a matrix
In linear algebra, understanding the nullity of a matrix is fundamental for solving systems of linear equations. The nullity of a matrix, denoted as Nullity(A), refers to the dimension of the null space of A. The null space comprises all the vectors that, when multiplied by the matrix A, result in a zero vector. Essentially, it's the set of all solutions to the homogeneous equation \(Ax = 0\).

For instance, if a matrix A has a nullity of 3, this means that there are three linearly independent vectors that can be multiplied by A to give the zero vector. Understanding the concept of nullity is crucial, as it provides insights into the structure of solutions to the equation \(Ax = 0\) and has implications for the solvability and consistency of linear systems.
Rank of a matrix
Closely related to the concept of nullity is the rank of a matrix. The rank of a matrix, denoted as Rank(A), is the maximal number of linearly independent rows or, equivalently, columns in the matrix A. It offers a measure of the 'information content' in the matrix, and it is critical in determining whether a system of equations has a unique solution.

If we have a matrix with a high rank, it means that the matrix's rows or columns have a broad span in their respective vector space, which usually implies fewer constraints and a reduced dimension of the solution space. In the context of singular value decomposition (SVD), the rank is intimately connected with the number of non-zero singular values in matrix S. Thus, identifying the rank of A through S gives us a clearer view of A's inherent properties.
Rank-nullity theorem
An indispensable tool in linear algebra is the rank-nullity theorem. This theorem serves as a bridge connecting the rank and nullity of a matrix. It states that for any \(m \times n\) matrix A, the Rank(A) plus the Nullity(A) equals the number of columns n of A. Formally, it is expressed as \(\text{Rank}(A) + \text{Nullity}(A) = n\).

This theorem provides a balance between the dimensions of the column space (rank) and null space (nullity) for matrix A. It signifies the fundamental trade-off in a matrix's linearly independent vectors—the more vectors contributing to the rank, the fewer vectors there can be in the null space and vice versa. This insight is particularly useful when solving linear systems, analyzing matrix transformations, or studying subspaces associated with a matrix.
Orthogonal matrices
Orthogonal matrices hold a special place in various mathematical computations and transformations, including singular value decomposition. An orthogonal matrix Q is a square matrix whose columns and rows are orthogonal unit vectors. In other words, Q satisfies the condition \(Q^{t}Q = QQ^{t} = I\), where I is the identity matrix and \(t\) denotes the transpose operation.

Orthogonal matrices are important because they preserve the length of vectors upon transformation and the angle between vectors, making them invaluable in preserving the geometric integrity of data during manipulations. In the context of SVD, orthogonal matrices U and V play a pivotal role in decomposing the original matrix A such that the transformation doesn't affect the singular values in matrix S, thus maintaining the rank characteristics of the original matrix.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that if \(A\) is an \(m \times n\) matrix and \(P\) is an \(n \times n\) orthogonal matrix, then \(P A\) has the same singular values as \(A\).

A persymmetric matrix is a matrix that is symmetric about both diagonals; that is, an \(N \times N\) matrix \(A=\left(a_{i j}\right)\) is persymmetric if \(a_{i j}=a_{j i}=a_{N+1-i, N+1-j}\), for all \(i=1,2, \ldots, N\) and \(j=1,2, \ldots, N\). A number of problems in communication theory have solutions that involve the eigenvalues and eigenvectors of matrices that are in persymmetric form. For example, the eigenvector corresponding to the minimal eigenvalue of the \(4 \times 4\) persymmetric matrix $$ A=\left[\begin{array}{rrrr} 2 & -1 & 0 & 0 \\ -1 & 2 & -1 & 0 \\ 0 & -1 & 2 & -1 \\ 0 & 0 & -1 & 2 \end{array}\right] $$ gives the unit energy-channel impulse response for a given error sequence of length 2 , and subsequently the minimum weight of any possible error sequence. a. Use the Geršgorin Circle Theorem to show that if \(A\) is the matrix given above and \(\lambda\) is its minimal eigenvalue, then \(|\lambda-4|=\rho(A-4 I)\), where \(\rho\) denotes the spectral radius. b. Find the minimal eigenvalue of the matrix \(A\) by finding all the eigenvalues \(A-4 I\) and computing its spectral radius. Then find the corresponding eigenvector. c. Use the Geršgorin Circle Theorem to show that if \(\lambda\) is the minimal eigenvalue of the matrix $$ B=\left[\begin{array}{rrrr} 3 & -1 & -1 & 1 \\ -1 & 3 & -1 & -1 \\ -1 & -1 & 3 & -1 \\ 1 & -1 & -1 & 3 \end{array}\right] $$ then \(|\lambda-6|=\rho(B-6 I)\). d. Repeat part (b) using the matrix \(B\) and the result in part (c).

Suppose that \(A\) has the singular value decomposition \(A=U S V^{t}\). Determine, with justification a singular value decomposition of \(A^{t}\).

$$ \text { Suppose that } A \text { is an } m \times n \text { matrix } A \text {. Show that } \operatorname{Rank}(A) \text { is the same as the } \operatorname{Rank}\left(A^{t}\right) \text {. } $$

$$ \text { Prove that if } Q \text { is nonsingular matrix with } Q^{t}=Q^{-1} \text {, then } Q \text { is orthogonal. } $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.