Chapter 2: Problem 1
Use the Bisection method to find \(p_{3}\) for \(f(x)=\sqrt{x}-\cos x\) on \([0,1]\).
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Chapter 2: Problem 1
Use the Bisection method to find \(p_{3}\) for \(f(x)=\sqrt{x}-\cos x\) on \([0,1]\).
These are the key concepts you need to understand to accurately answer the question.
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Let \(A\) be a given positive constant and \(g(x)=2 x-A x^{2}\). a. Show that if fixed-point iteration converges to a nonzero limit, then the limit is \(p=1 / A\), so the inverse of a number can be found using only multiplications and subtractions. b. Find an interval about \(1 / A\) for which fixed-point iteration converges, provided \(p_{0}\) is in that interval.
For each of the following equations, determine an interval \([a, b]\) on which fixed-point iteration will converge. Estimate the number of iterations necessary to obtain approximations accurate to within \(10^{-5}\), and perform the calculations. a. \(\quad x=\frac{2-e^{x}+x^{2}}{3}\) b. \(\quad x=\frac{5}{x^{2}}+2\) c. \(\quad x=\left(e^{x} / 3\right)^{1 / 2}\) d. \(\quad x=5^{-x}\) e. \(\quad x=6^{-x}\) f. \(\quad x=0.5(\sin x+\cos x)\)
Let \(f(x)=x^{2}-6\). With \(p_{0}=3\) and \(p_{1}=2\), find \(p_{3}\). a. Use the Secant method. b. Use the method of False Position. c. Which of a. or b. is closer to \(\sqrt{6}\) ?
Let \(f(x)=(x-1)^{10}, p=1\), and \(p_{n}=1+1 / n\). Show that \(\left|f\left(p_{n}\right)\right|<10^{-3}\) whenever \(n>1\) but that \(\left|p-p_{n}\right|<10^{-3}\) requires that \(n>1000\).
Use Newton's method to approximate, to within \(10^{-4}\), the value of \(x\) that produces the point on the graph of \(y=1 / x\) that is closest to \((2,1)\).
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