Chapter 5: Problem 1
Use the two-point forward-difference formula to approximate \(f^{\prime}(1)\), and find the approximation error, where \(f(x)=\ln x\), for (a) \(h=0.1\) (b) \(h=0.01\) (c) \(h=0.001\).
Short Answer
Expert verified
Answer: The approximation errors for \(h = 0.1\), \(h = 0.01\), and \(h = 0.001\) are approximately 0.0909, 0.0100, and 0.0010, respectively.
Step by step solution
01
Calculate \(f^{\prime}(1)\) using the forward-difference formula for each value of \(h\)
A first derivative of the function \(f(x) = \ln x\) is \(f^{\prime}(x) = \frac{1}{x}\). Using the two-point forward-difference formula, we have:
For \(h = 0.1\),
$$
f^{\prime}(1) \approx \frac{\ln(1+0.1)-\ln(1)}{0.1}
$$
For \(h = 0.01\),
$$
f^{\prime}(1) \approx \frac{\ln(1+0.01)-\ln(1)}{0.01}
$$
For \(h = 0.001\),
$$
f^{\prime}(1) \approx \frac{\ln(1+0.001)-\ln(1)}{0.001}
$$
02
Evaluate the derivatives
Calculate the derivatives for each value of \(h\):
For \(h = 0.1\),
$$
f^{\prime}(1) \approx \frac{\ln(1.1)-\ln(1)}{0.1} \approx 0.9091
$$
For \(h = 0.01\),
$$
f^{\prime}(1) \approx \frac{\ln(1.01)-\ln(1)}{0.01} \approx 0.9900
$$
For \(h = 0.001\),
$$
f^{\prime}(1) \approx \frac{\ln(1.001)-\ln(1)}{0.001} \approx 0.9990
$$
03
Calculate the exact value of \(f^{\prime}(1)\)
The exact value of the derivative of \(f(x) = \ln x\) is \(f^{\prime}(x) = \frac{1}{x}\). So the exact value of \(f^{\prime}(1)\) is:
$$
f^{\prime}(1) = \frac{1}{1} = 1
$$
04
Calculate the approximation errors
The approximation error for each value of \(h\) is given by the difference between the exact value of \(f^{\prime}(1)\) and their respective approximations:
For \(h = 0.1\),
$$
\text{Error} = |1 - 0.9091| \approx 0.0909
$$
For \(h = 0.01\),
$$
\text{Error} = |1 - 0.9900| \approx 0.0100
$$
For \(h = 0.001\),
$$
\text{Error} = |1 - 0.9990| \approx 0.0010
$$
So, the approximation errors for (a) \(h = 0.1\), (b) \(h = 0.01\), and (c) \(h = 0.001\) are approximately 0.0909, 0.0100, and 0.0010, respectively.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Forward-Difference Formula
Numerical differentiation is a technique used to estimate the derivative of a function using discrete data points. One common method is the forward-difference formula. It is particularly useful when we're unable to find the derivative analytically, or when dealing with real-world data that doesn't come with neat functions.
The forward-difference formula is written as: \[f^{\prime}(x) \approx \frac{f(x+h) - f(x)}{h}\] This formula estimates the slope of the function at a given point using a small step size, denoted by \(h\). The calculation involves taking the difference between the function values at \(x + h\) and \(x\), divided by \(h\). This effectively gives us an average rate of change over the interval from \(x\) to \(x + h\).
It's an essential tool because it provides a way to approximate derivatives using simple algebraic operations, which can be easily implemented in programming and is fast for computation.
The forward-difference formula is written as: \[f^{\prime}(x) \approx \frac{f(x+h) - f(x)}{h}\] This formula estimates the slope of the function at a given point using a small step size, denoted by \(h\). The calculation involves taking the difference between the function values at \(x + h\) and \(x\), divided by \(h\). This effectively gives us an average rate of change over the interval from \(x\) to \(x + h\).
It's an essential tool because it provides a way to approximate derivatives using simple algebraic operations, which can be easily implemented in programming and is fast for computation.
- Easy to perform for basic problem solving
- Versatile for different types of functions
- Useful for simplifying complex derivative calculations
Approximation Error
In the realm of numerical differentiation, approximation error is inevitable and is a crucial concept to understand. The approximation error measures the difference between the estimated derivative from a numerical method and the true analytical derivative of the function.
The error for a derivative approximation can be defined as:\[\text{Error} = \left| f^{\prime}(x) - \text{Numerical approximation}\right|\] In our forward-difference formula, the error decreases as the step size \(h\) becomes smaller. However, choosing \(h\) too small can introduce round-off errors due to the limitations of digital computers in maintaining precision. Thus, finding a balance for \(h\) is key to minimizing the overall error.
Understanding this concept helps you:
The error for a derivative approximation can be defined as:\[\text{Error} = \left| f^{\prime}(x) - \text{Numerical approximation}\right|\] In our forward-difference formula, the error decreases as the step size \(h\) becomes smaller. However, choosing \(h\) too small can introduce round-off errors due to the limitations of digital computers in maintaining precision. Thus, finding a balance for \(h\) is key to minimizing the overall error.
Understanding this concept helps you:
- Improve the accuracy of your numerical solutions
- Understand the limitations of numerical methods
- Select an optimal step size for calculations
Derivative Calculation
Calculating derivatives is a fundamental concept in calculus. It represents the rate at which a function changes and is vital in various fields such as physics, engineering, and economics. For the function \( f(x) = \ln x \), the derivative can be found analytically as \( f^{\prime}(x) = \frac{1}{x} \).
This analytical solution gives us the exact rate of change at every point \(x\). However, in numerical methods, like the forward-difference formula, we seek to approximate this value using calculations based on discrete points.
To calculate a derivative:
This analytical solution gives us the exact rate of change at every point \(x\). However, in numerical methods, like the forward-difference formula, we seek to approximate this value using calculations based on discrete points.
To calculate a derivative:
- Identify the function you need to differentiate
- Choose a numerical method if an analytical solution isn't clear
- Implement the method consistently to approximate the derivative at specific points