Chapter 5: Problem 2
Prove that there is no rational number whose square is equal to 12 .
Short Answer
Expert verified
No rational number squared equals 12 because it leads to a contradiction about the form of the rational number.
Step by step solution
01
- Assume a Rational Solution
Assume that there exists a rational number such that its square is 12. A rational number can be expressed as a fraction \( \frac{a}{b} \), where \( a \) and \( b \) are integers with no common factors other than 1 (i.e., \( \frac{a}{b} \) is in its lowest terms). So, we assume \( \left( \frac{a}{b} \right)^2 = 12 \).
02
- Set Up the Equation
Squaring \( \frac{a}{b} \) gives us \( \frac{a^2}{b^2} = 12 \). Multiplying both sides of the equation by \( b^2 \) results in \( a^2 = 12b^2 \).
03
- Analyze the Implications
From the equation \( a^2 = 12b^2 \), we see that \( a^2 \) is divisible by 12. Since 12 factors into primes as \( 2^2 \times 3 \), for \( a^2 \) to be divisible by 12, \( a \) itself must be divisible by both 2 and 3, making \( a \) divisible by 6. Hence, let \( a = 6k \), where \( k \) is an integer.
04
- Substitute and Simplify
Substituting \( a = 6k \) into \( a^2 = 12b^2 \) yields \( (6k)^2 = 12b^2 \), which simplifies to \( 36k^2 = 12b^2 \). Dividing both sides of the equation by 12 results in \( 3k^2 = b^2 \).
05
- Reach a Contradiction
The equation \( 3k^2 = b^2 \) implies that \( b^2 \) is divisible by 3. This means \( b \) must be divisible by 3. We now have that both \( a \) and \( b \) are multiples of 3, contradicting our initial assumption that \( \frac{a}{b} \) is in its lowest terms.
06
- Conclude the Proof
Since assuming the existence of a rational number whose square is 12 leads to a contradiction, our initial assumption must be false. Therefore, there is no rational number whose square is equal to 12.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
rational numbers
Rational numbers are numbers that can be expressed as a fraction \( \frac{a}{b} \), where \( a \) and \( b \) are integers and \( b \) is not zero. This means that any whole number, fraction, or terminating decimal is a rational number.
If a number can be written in this fractional form, with \( a \) and \( b \) having no common factors other than 1, it's in its simplest form (or lowest terms).
For example, \( \frac{1}{2} \) and \( \frac{3}{4} \) are rational numbers.
Understanding rational numbers is key to recognize when a number cannot be expressed as such, which leads us to the problem of whether \( \sqrt{12} \) is rational.
If a number can be written in this fractional form, with \( a \) and \( b \) having no common factors other than 1, it's in its simplest form (or lowest terms).
For example, \( \frac{1}{2} \) and \( \frac{3}{4} \) are rational numbers.
Understanding rational numbers is key to recognize when a number cannot be expressed as such, which leads us to the problem of whether \( \sqrt{12} \) is rational.
proof by contradiction
Proof by contradiction is a method used to prove that a statement is true by showing that assuming the opposite leads to a contradiction.
Here’s how it works:
In our problem, we started by assuming that there is a rational number whose square is 12. After following logical steps, we reached a contradiction. Therefore, our initial assumption must be false, proving that no rational number can square to 12.
Here’s how it works:
- Assume the opposite of what you want to prove (the negation).
- Show that this assumption leads to an impossible situation or a logical inconsistency.
- Conclude that the original statement must be true.
In our problem, we started by assuming that there is a rational number whose square is 12. After following logical steps, we reached a contradiction. Therefore, our initial assumption must be false, proving that no rational number can square to 12.
square roots
The square root of a number \( n \) is a value that, when multiplied by itself, gives \( n \). It is denoted as \( \sqrt{n} \).
For example, \( \sqrt{4} = 2 \) because \( 2 \times 2eq4\).
Square roots are not always whole numbers. For example, \( \sqrt{2}\) and \( \sqrt{3} \) are irrational numbers because they cannot be expressed exactly as a fraction of two integers.
In our proof, we assumed \( \sqrt{12} \) was rational and wrote it as \( \frac{a}{b} \). By working through the steps, we showed that this led to a contradiction. Hence, \( \sqrt{12} \) is irrational.
Understanding square roots deeply helps in recognizing why certain numbers are irrational, and why they can't be neatly expressed as fractions of integers.
For example, \( \sqrt{4} = 2 \) because \( 2 \times 2eq4\).
Square roots are not always whole numbers. For example, \( \sqrt{2}\) and \( \sqrt{3} \) are irrational numbers because they cannot be expressed exactly as a fraction of two integers.
In our proof, we assumed \( \sqrt{12} \) was rational and wrote it as \( \frac{a}{b} \). By working through the steps, we showed that this led to a contradiction. Hence, \( \sqrt{12} \) is irrational.
Understanding square roots deeply helps in recognizing why certain numbers are irrational, and why they can't be neatly expressed as fractions of integers.