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(Polar coordinates) Using the identity \(\theta=\tan ^{-1}(y / x)\), show that \(\dot{\theta}=(x \dot{y}-y \dot{x}) / r^{2}\)

Short Answer

Expert verified
To show that \(\dot{\theta} = \frac{x\dot{y} - y\dot{x}}{r^2}\), differentiate 胃 with respect to time using the given identity: 胃 = tan^(-1)(y/x). Apply the chain rule and implicit differentiation, and then simplify and rearrange the terms. Finally, recognize that in polar coordinates, \(r^2 = x^2 + y^2\), and substitute to obtain the final expression for the angular velocity 饾渻虈.

Step by step solution

01

Differentiate 胃 with respect to time t

To differentiate 胃 with respect to t, we use the chain rule and apply it to the inverse tangent function 胃 = tan^(-1)(y/x): \(\frac{d\theta}{dt} = \frac{d}{dt} (\tan^{-1}(\frac{y}{x}))\)
02

Use the chain rule and implicit differentiation

Now we differentiate the inside function y/x with respect to x and y and use the chain rule. \(\frac{d\theta}{dt} = \frac{1}{(1+(\frac{y}{x})^2)} \cdot (\frac{d}{dt}(\frac{y}{x}))\) We use implicit differentiation to find \( \frac{d}{dt} (\frac{y}{x}) \) : \(\frac{d}{dt} (\frac{y}{x}) = \frac{x\frac{dy}{dt} - y\frac{dx}{dt}}{x^2}\)
03

Substitute back in for dy/dt and dx/dt

Now notice that \(\frac{dy}{dt} = \dot{y}\) (the time derivative of y) and \(\frac{dx}{dt} = \dot{x}\) (the time derivative of x), so we substitute these values back into the expression: \(\frac{d\theta}{dt} = \frac{1}{(1+(\frac{y}{x})^2)} \cdot (\frac{x\dot{y} - y\dot{x}}{x^2})\)
04

Simplify and rearrange the terms

Now we simplify the expression for the time derivative of 胃: \(\frac{d\theta}{dt} = \frac{x\dot{y} - y\dot{x}}{x^2 + y^2}\) Recognizing that in polar coordinates \(r^2 = x^2 + y^2\), we get the final expression for the angular velocity 饾渻虈: \(\dot{\theta} = \frac{x\dot{y} - y\dot{x}}{r^2}\) Hence, we have shown that \(\dot{\theta} = \frac{x\dot{y} - y\dot{x}}{r^2}\) using the given identity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Implicit Differentiation
Implicit differentiation is a method used when we have a function given in terms that are not explicitly solved for one variable. In polar coordinates, for example, angles like \( \theta \) can be given in terms of several variables, such as \( x \) and \( y \).
When working with implicit differentiation, the goal is to find the derivative of one variable with respect to another, even if it's not given as a standalone function. In the exercise above, we differentiate \( \theta \) with respect to \( t \), even though \( \theta \) is an implicit function of \( x \) and \( y \).
  • First, identify the parts of the function that can be differentiated.
  • Apply differentiation rules like the chain rule on each part.
  • Relate derivatives of other embedded or related functions.
By using implicit differentiation, we're able to find derivatives without needing to first solve for \( \theta \) in terms of \( t \) explicitly.
Chain Rule
The chain rule is a fundamental tool in calculus for finding derivatives of composite functions. When functions are composed of other functions, the chain rule helps us differentiate them.
In the context of the exercise, the angle \( \theta \) is defined as \( \theta = \tan^{-1}(y/x) \). This is a composite function because \( y/x \) itself is a function, and it's inside the tangent inverse function.
To apply the chain rule:
  • Find the derivative of the outer function, \( \tan^{-1}(u) \), where \( u = y/x \).
  • Multiply this with the derivative of the inner function \( u \) with respect to time, \( t \).
The chain rule allows us to systematically handle each part of the composition, leading us to the expression involving \( \dot{y} \) and \( \dot{x} \), the time derivatives of \( y \) and \( x \). This ensures precise calculations for more complex derivatives.
Angular Velocity
Angular velocity is a measure of how quickly an angle changes over time. In polar coordinates, it is denoted \( \dot{\theta} \).
The angular velocity tells us how fast a particle is rotating around a point, which in 2D is typically the origin in polar coordinates.
The final expression \( \dot{\theta} = \frac{x\dot{y} - y\dot{x}}{r^2} \) shows that angular velocity depends on both the changes in \( x \) and \( y \) over time. It's essential in fields like physics and engineering to describe rotational motion.
Key points include:
  • Angular velocity can give insights into the rotational characteristics of a system.
  • It's derived by considering both the linear velocities in the \( x \) and \( y \) directions.
  • Relationships like this highlight the importance of calculus in translating between different types of motion and coordinates.
Time Derivatives
Time derivatives depict how a quantity changes over time. They are essential in describing dynamics in physics or any system that evolves over time.
For instance, \( \dot{y} \) denotes the rate of change of \( y \) with respect to time \( t \), commonly expressed as \( \frac{dy}{dt} \). Similarly, \( \dot{x} = \frac{dx}{dt} \).
In the given problem, to find \( \dot{\theta} \), we needed the time derivatives of \( x \) and \( y \). These provide the rates at which \( x \) and \( y \) change, crucial for calculating angular velocity.
  • Time derivatives link static geometry, like position, to dynamic states, like motion.
  • They represent the core of differential calculus applications in real-world scenarios.
  • Understanding time derivatives helps track how a system evolves, making them pivotal in fields spanning from physics to economics.
Each variable's time derivative contributes to understanding how the system behaves and evolves dynamically.

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Most popular questions from this chapter

(Nonlinear terms can change a star into a spiral) Here's another example that shows that borderline fixed points are sensitive to nonlinear terms. Consider the system in polar coordinates given by \(\dot{r}=-r, \dot{\theta}=1 / \ln r\) a) Find \(r(t)\) and \(\theta(t)\) explicitly, given an initial condition \(\left(r_{0}, \theta_{0}\right)\). b) Show that \(r(t) \rightarrow 0\) and \(|\theta(t)| \rightarrow \infty\) as \(t \rightarrow \infty\). Therefore the origin is a stable spiral for the nonlinear system. c) Write the system in \(x, y\) coordinates. d) Show that the linearized system about the origin is \(\dot{x}=-x, \dot{y}=-y\). Thus the origin is a stable star for the linearized system.

Consider the following "rabbits vs. sheep" problems, where \(x, y \geq 0\). Find the fixed points, investigate their stability, draw the nullclines, and sketch plausible phase portraits. Indicate the basins of attraction of any stable fixed points. $$ \dot{x}=x(3-x-y), \dot{y}=y(2-x-y) $$

(Dealing with a fixed point for which linearization is inconclusive) The goal of this exercise is to sketch the phase portrait for \(\dot{x}=x y, \dot{y}=x^{2}-y\). a) Show that the linearization predicts that the origin is a non-isolated fixed point. b) Show that the origin is in fact an isolated fixed point. c) Is the origin repelling, attracting, a saddle, or what? Sketch the vector field along the nullclines and at other points in the phase plane, Use this information to sketch the phase portrait. d) Plot a computer-generated phase portrait to check your answer to (c). (Note: This problem can also be solved by a method called center manifold theory, as explained in Wiggins (I990) and Guckenheimer and Holmes (1983).)

(Complex vector fields) Let \(z=x+i y\). Explore the complex vector fields \(\dot{z}=z^{k}\) and \(\dot{z}=(\bar{z})^{k}\), where \(k>0\) is an integer and \(\bar{z}=x-i y\) is the complex conjugate of \(z\) a) Write the vector fields in both Cartesian and polar coordinates, for the cases \(k=1,2,3\). b) Show that the origin is the only fixed point, and compute its index. c) Generalize your results to arbitrary integer \(k>0\).

(Unusual fixed points) For each of the following systems, locate the fixed points and calculate the index. (Hint: Draw a small closed curve \(C\) around the fixed point and examine the variation of the vector field on \(C\).) $$ \dot{x}=x y, \dot{y}=x+y $$

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