Chapter 9: Problem 10
The point \(A(2,4,-5)\) is reflected in the line with equation \(\vec{r}=(0,0,1)+s(4,2,1), s \in \mathbf{R},\) to give the point \(A^{\prime} .\) Determine the coordinates of \(A^{\prime}\)
Short Answer
Expert verified
The coordinates of \( A' \) are \( \left( \frac{38}{21}, -\frac{44}{21}, \frac{167}{21} \right) \).
Step by step solution
01
Identify Point and Line Components
The point given is \( A(2, 4, -5) \). The line is given by the equation \( \vec{r} = (0,0,1) + s(4,2,1) \). We can interpret this as the line passing through point \( P(0,0,1) \) with direction vector \( \vec{d} = (4,2,1) \). Our goal is to reflect point \( A \) across this line.
02
Find Projection of A on Line
To reflect point \( A \) over the line, we first need to find the projection of \( A \) onto the line. The formula for projection of vector \( \vec{AP} \) on \( \vec{d} \) is \[\mathrm{proj}_{\vec{d}} \vec{AP} = \frac{\vec{AP} \cdot \vec{d}}{\vec{d} \cdot \vec{d}} \cdot \vec{d}\]where \( \vec{AP} = (2, 4, -6) \) because we subtract point \( P(0,0,1) \) from point \( A(2, 4, -5) \). Calculate\[\vec{AP} \cdot \vec{d} = (2, 4, -6) \cdot (4, 2, 1) = 8 + 8 - 6 = 10\]\[\vec{d} \cdot \vec{d} = (4, 2, 1) \cdot (4, 2, 1) = 16 + 4 + 1 = 21\].Thus, the projection is \[\frac{10}{21} \cdot (4, 2, 1) = \left( \frac{40}{21}, \frac{20}{21}, \frac{10}{21} \right)\].
03
Find Image A' Using Reflection Formula
The formula to find the reflection \( A' \) in terms of an original point \( A \) and its projection onto a line \( B \) is \[ \vec{A'} = 2\vec{B} - \vec{A} \]where \( B \) is the point on the line closest to \( A \):\[ B = P + \mathrm{proj}_{\vec{d}} \vec{AP} = \left( 0, 0, 1 \right) + \left( \frac{40}{21}, \frac{20}{21}, \frac{10}{21} \right) = \left( \frac{40}{21}, \frac{20}{21}, \frac{31}{21} \right)\].So,\[ \vec{A'} = 2\left( \frac{40}{21}, \frac{20}{21}, \frac{31}{21} \right) - (2, 4, -5) \].This simplifies to\[ \vec{A'} = \left( \frac{80}{21}, \frac{40}{21}, \frac{62}{21} \right) - (2, 4, -5) \]resulting in\[ A' = \left( \frac{80}{21} - \frac{42}{21}, \frac{40}{21} - \frac{84}{21}, \frac{62}{21} + \frac{105}{21} \right) = \left( \frac{38}{21}, -\frac{44}{21}, \frac{167}{21} \right)\].
04
Conclude with the Reflection Point
Finally, the coordinates of point \( A' \) are \( \left( \frac{38}{21}, -\frac{44}{21}, \frac{167}{21} \right) \). This is the result of reflecting \( A(2, 4, -5) \) across the line described by \( \vec{r}=(0,0,1)+s(4,2,1) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Projection
Vector projection is a critical concept in linear algebra and physics, especially when it comes to decomposing vectors into components. To project a vector onto another, you think of "casting a shadow" of one vector onto the other. Imagine you have a flashlight shining from above. The shadow cast on the floor by any object is similar to what projection is like in mathematics.
A vector projection of vector \( \vec{a} \) onto vector \( \vec{b} \) helps us identify how much of \( \vec{a} \) is in the direction of \( \vec{b} \). This is calculated using the formula:
\[ \mathrm{proj}_{\vec{b}} \vec{a} = \frac{\vec{a} \cdot \vec{b}}{\vec{b} \cdot \vec{b}} \cdot \vec{b} \]
Here, \( \vec{a} \cdot \vec{b} \) is the dot product, capturing how much \( \vec{a} \) aligns with \( \vec{b} \). Scalar multiplication with \( \vec{b} \) then scales this alignment back onto the direction of \( \vec{b} \).
In the given problem, the projection of \( \vec{AP} \) onto the line's direction gives us a vector originating from point \( P \) that points towards \( A \)'s shadow on line \( \vec{r} \). This helps us find a point on the line that is closest to \( A \), crucial for reflection.
A vector projection of vector \( \vec{a} \) onto vector \( \vec{b} \) helps us identify how much of \( \vec{a} \) is in the direction of \( \vec{b} \). This is calculated using the formula:
\[ \mathrm{proj}_{\vec{b}} \vec{a} = \frac{\vec{a} \cdot \vec{b}}{\vec{b} \cdot \vec{b}} \cdot \vec{b} \]
Here, \( \vec{a} \cdot \vec{b} \) is the dot product, capturing how much \( \vec{a} \) aligns with \( \vec{b} \). Scalar multiplication with \( \vec{b} \) then scales this alignment back onto the direction of \( \vec{b} \).
In the given problem, the projection of \( \vec{AP} \) onto the line's direction gives us a vector originating from point \( P \) that points towards \( A \)'s shadow on line \( \vec{r} \). This helps us find a point on the line that is closest to \( A \), crucial for reflection.
Vector Operations
Vector operations, such as the dot and scalar multiplication, lie at the heart of understanding and manipulating vectors. Let's explore them more closely:
Understanding vector operations is vital in performing complex transformations, including reflections, rotaries, and translations.
- **Dot Product**: This operation, symbolized as \( \vec{a} \cdot \vec{b} \), is akin to finding the "similarity" between two vectors. It not only helps in computing projections but also in determining angles between vectors since it can depict cosine of the angle.
- **Scalar Multiplication**: It scales a vector by a constant. When you multiply a vector \( \vec{v} \) by a scalar \( k \), you stretch or shrink \( \vec{v} \) while maintaining its direction. It's like adjusting the size of a shadow while keeping its direction constant.
Understanding vector operations is vital in performing complex transformations, including reflections, rotaries, and translations.
Line Reflection
Line reflection of a point across a line involves "flipping" the point over the line as if the line were a mirror. It's a concept dealing deeply with symmetry and geometric transformation. When we reflect a point \( A \) across a line, we are finding its mirror image, \( A' \), on the opposite side but equidistant from the line.
This involves a few steps:
This involves a few steps:
- **Identify Closest Point on Line**: Using projection, identify \( B \), the point on the line closest to \( A \).
- **Calculate Reflection Point**: Use the formula \( \vec{A'} = 2\vec{B} - \vec{A} \). This mathematical expression dictates taking double the vector that reaches the closest point on the line from the origin of \( A \), essentially guaranteeing a perfect reflection.