Chapter 7: Problem 5
Calculate the area of the parallelogram formed by the following pairs of vectors: a. \(\vec{a}=(1,1,0)\) and \(\vec{b}=(1,0,1)\) b. \(\vec{a}=(1,-2,3)\) and \(\vec{b}=(1,2,4)\)
Short Answer
Expert verified
a. Area is \(\sqrt{3}\); b. Area is \(\sqrt{213}\).
Step by step solution
01
Understanding the Formula
To find the area of a parallelogram formed by two vectors, we use the cross product of the vectors. The magnitude of the cross product gives the area. If the vectors are \(\vec{a}\) and \(\vec{b}\), the formula for the area \(A\) is:\[ A = \| \vec{a} \times \vec{b} \| \]
02
Calculate Cross Product for Part a
For vectors \(\vec{a}=(1,1,0)\) and \(\vec{b}=(1,0,1)\), find the cross product \(\vec{a} \times \vec{b}\):\[\vec{a} \times \vec{b} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \1 & 1 & 0 \1 & 0 & 1 \\end{vmatrix}= (1 \cdot 1 - 0 \cdot 0)\hat{i} - (0 \cdot 1 - 1 \cdot 1)\hat{j} + (1 \cdot 0 - 1 \cdot 1)\hat{k}= \hat{i} + \hat{j} - \hat{k}\]
03
Calculate Magnitude of Cross Product for Part a
Find the magnitude of \(\vec{a} \times \vec{b}\):\[ \| \vec{a} \times \vec{b} \| = \sqrt{1^2 + 1^2 + (-1)^2} = \sqrt{3} \]Thus, the area of the parallelogram for vectors \(\vec{a}=(1,1,0)\) and \(\vec{b}=(1,0,1)\) is \(\sqrt{3}\).
04
Calculate Cross Product for Part b
For vectors \(\vec{a}=(1, -2, 3)\) and \(\vec{b}=(1, 2, 4)\), find the cross product \(\vec{a} \times \vec{b}\):\[\vec{a} \times \vec{b} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \1 & -2 & 3 \1 & 2 & 4 \\end{vmatrix}= (-8 - 6)\hat{i} - (4 - 3)\hat{j} + (2 + 2)\hat{k}= -14\hat{i} - \hat{j} + 4\hat{k}\]
05
Calculate Magnitude of Cross Product for Part b
Find the magnitude of \(\vec{a} \times \vec{b}\):\[ \| \vec{a} \times \vec{b} \| = \sqrt{(-14)^2 + (-1)^2 + 4^2} = \sqrt{196 + 1 + 16} = \sqrt{213} \]Thus, the area of the parallelogram for vectors \(\vec{a}=(1,-2,3)\) and \(\vec{b}=(1,2,4)\) is \(\sqrt{213}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a crucial operation used in vector calculus that results in a vector perpendicular to two original vectors in three-dimensional space. Unlike the dot product, which results in a scalar, the cross product produces another vector. This operation only applies to vectors in 3D. The cross product is defined as follows for vectors \(\vec{a} = (a_1, a_2, a_3)\) and \(\vec{b} = (b_1, b_2, b_3)\):
\[\vec{a} \times \vec{b} = (a_2b_3 - a_3b_2)\hat{i} - (a_1b_3 - a_3b_1)\hat{j} + (a_1b_2 - a_2b_1)\hat{k}\]This formula is determined using a 3x3 determinant with the unit vectors \(\hat{i}, \hat{j}, \hat{k}\).
\[\vec{a} \times \vec{b} = (a_2b_3 - a_3b_2)\hat{i} - (a_1b_3 - a_3b_1)\hat{j} + (a_1b_2 - a_2b_1)\hat{k}\]This formula is determined using a 3x3 determinant with the unit vectors \(\hat{i}, \hat{j}, \hat{k}\).
- \(\hat{i}\), \(\hat{j}\), and \(\hat{k}\) represent unit vectors in the x, y, and z directions, respectively.
- The resulting vector is perpendicular to both \(\vec{a}\) and \(\vec{b}\).
Magnitude of a Vector
Understanding the magnitude of a vector is essential when dealing with vector operations like the cross product.
The magnitude (or length) of a vector \(\vec{v} = (v_1, v_2, v_3)\) in three-dimensional space is given by:
\[\|\vec{v}\| = \sqrt{v_1^2 + v_2^2 + v_3^2}\]
This scalar value represents how long the vector is, regardless of direction.
The magnitude (or length) of a vector \(\vec{v} = (v_1, v_2, v_3)\) in three-dimensional space is given by:
\[\|\vec{v}\| = \sqrt{v_1^2 + v_2^2 + v_3^2}\]
This scalar value represents how long the vector is, regardless of direction.
- If all components of the vector are zero, the vector's magnitude is zero, meaning it is a zero vector.
- The calculation involves squaring each component, summing them, and taking the square root of the result.
Area of Parallelogram
The area of a parallelogram can be easily calculated using the cross product of two vectors.
When two vectors \(\vec{a}\) and \(\vec{b}\) form the sides of a parallelogram, the area \(A\) of that parallelogram is the magnitude of their cross product:
\[A = \|\vec{a} \times \vec{b}\|\]
When two vectors \(\vec{a}\) and \(\vec{b}\) form the sides of a parallelogram, the area \(A\) of that parallelogram is the magnitude of their cross product:
\[A = \|\vec{a} \times \vec{b}\|\]
- The cross product, \(\vec{a} \times \vec{b}\), gives a vector that is perpendicular to the plane containing \(\vec{a}\) and \(\vec{b}\).
- The magnitude of this vector corresponds directly to the area, giving us a scalar value.