Chapter 7: Problem 18
The vector \(\vec{a}\) is a unit vector, and the vector \(\vec{b}\) is any other nonzero vector. If \(\vec{c}=(\vec{b} \cdot \vec{a}) \vec{a}\) and \(\vec{d}=\vec{b}-\vec{c},\) prove that \(\vec{d} \cdot \vec{a}=0\)
Short Answer
Expert verified
\(\vec{d} \cdot \vec{a} = 0\) because \(\vec{d}\) is perpendicular to \(\vec{a}\).
Step by step solution
01
Understanding the Problem
Given vectors \(\vec{a}\), \(\vec{b}\), \(\vec{c}\), and \(\vec{d}\), with \(\vec{a}\) being a unit vector, we need to show that \(\vec{d} \cdot \vec{a} = 0\). First, let's explore what is given.
02
Express \(\vec{c}\) in Terms of Dot Product
We are given \(\vec{c} = (\vec{b} \cdot \vec{a}) \vec{a}\). This means that \(\vec{c}\) is the component of \(\vec{b}\) along the direction of \(\vec{a}\).
03
Define \(\vec{d}\)
From the problem, we have \(\vec{d} = \vec{b} - \vec{c}\). Thus, \(\vec{d}\) represents the component of \(\vec{b}\) that is perpendicular to \(\vec{a}\).
04
Calculate the Dot Product \(\vec{d} \cdot \vec{a}\)
To prove \(\vec{d} \cdot \vec{a} = 0\), substitute \(\vec{d} = \vec{b} - \vec{c}\) into the dot product: \[\vec{d} \cdot \vec{a} = (\vec{b} - \vec{c}) \cdot \vec{a} = \vec{b} \cdot \vec{a} - \vec{c} \cdot \vec{a}\].
05
Evaluate and Simplify \(\vec{c} \cdot \vec{a}\)
Since \(\vec{c} = (\vec{b} \cdot \vec{a}) \vec{a}\), the dot product \(\vec{c} \cdot \vec{a}\) can be simplified:\[\vec{c} \cdot \vec{a} = ((\vec{b} \cdot \vec{a}) \vec{a}) \cdot \vec{a} = (\vec{b} \cdot \vec{a})(\vec{a} \cdot \vec{a})\] Since \(\vec{a}\) is a unit vector, \(\vec{a} \cdot \vec{a} = 1\), thus \(\vec{c} \cdot \vec{a} = \vec{b} \cdot \vec{a}\).
06
Conclude \(\vec{d} \cdot \vec{a} = 0\)
Substitute \(\vec{c} \cdot \vec{a} = \vec{b} \cdot \vec{a}\) back into the equation:\[\vec{d} \cdot \vec{a} = \vec{b} \cdot \vec{a} - \vec{b} \cdot \vec{a} = 0\]This confirms that \(\vec{d}\) is perpendicular to \(\vec{a}\), proving \(\vec{d} \cdot \vec{a} = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Vector
A unit vector is a vector with a magnitude of one. It is generally used to specify a direction. The simplicity of unit vectors enables them to exclusively represent direction, making them extremely useful in problems that focus on vector directionality. Any vector can be turned into a unit vector by dividing it by its own magnitude.
Key features of unit vectors include:
Key features of unit vectors include:
- Their length is always 1, which simplifies calculations involving them.
- They maintain the direction of the original vector.
- Unit vectors are often denoted with a "hat", for example, \( \hat{i} \), \( \hat{j} \), and \( \hat{k} \) in three dimensions, which point along the axes of a Cartesian coordinate system.
Vector Components
Vector components are the projections of a vector along the axes of a coordinate system. They enable the simplification of vector arithmetic and geometry by reducing the vector into manageable parts. By expressing a vector in terms of its components, we can perform operations on each part separately.
Understanding how vector components work:
Understanding how vector components work:
- A vector can be broken down into its horizontal and vertical components in 2D or further split along the \( x, y, \) and \( z \) axes in 3D.
- Components are essential for projecting vectors onto other vectors, which simplifies the understanding of vector interactions.
Perpendicular Vectors
Perpendicular vectors are vectors that meet at a right angle. This means their dot product equals zero. Understanding this property of perpendicular vectors is crucial as it can simplify the problem-solving process when analyzing vector relationships.
Key concepts about perpendicular vectors:
Key concepts about perpendicular vectors:
- If two vectors \( \vec{u} \) and \( \vec{v} \) are perpendicular, their dot product \( \vec{u} \cdot \vec{v} = 0 \).
- Perpendicular vectors are orthogonal, meaning they hold no component in each other's direction.