Chapter 3: Problem 2
Determine the second derivative of each of the following: a. \(y=x^{10}+3 x^{6}\) b. \(f(x)=\sqrt{x}\) c. \(y=(1-x)^{2}\) d. \(h(x)=3 x^{4}-4 x^{3}-3 x^{2}-5\) e. \(y=4 x^{\frac{3}{2}}-x^{-2}\) f. \(f(x)=\frac{2 x}{x+1}\) \(\mathrm{g} \cdot y=x^{2}+\frac{1}{x^{2}}\) h. \(g(x)=\sqrt{3 x-6}\) i. \(y=(2 x+4)^{3}\) j. \(h(x)=\sqrt[3]{x^{5}}\)
Short Answer
Step by step solution
Step 1a: First Derivative of (a)
Step 2a: Second Derivative of (a)
Step 1b: First Derivative of (b)
Step 2b: Second Derivative of (b)
Step 1c: First Derivative of (c)
Step 2c: Simplify the First Derivative
Step 3c: Second Derivative of (c)
Step 1d: First Derivative of (d)
Step 2d: Second Derivative of (d)
Step 1e: First Derivative of (e)
Step 2e: Second Derivative of (e)
Step 1f: Rewrite (f) for Simplification
Step 2f: First Derivative of (f)
Step 3f: Simplify First Derivative
Step 4f: Second Derivative of (f)
Step 1g: First Derivative of (g)
Step 2g: Second Derivative of (g)
Step 1h: First Derivative of (h)
Step 2h: Second Derivative of (h)
Step 1i: First Derivative of (i)
Step 2i: Second Derivative of (i)
Step 1j: First Derivative of (j)
Step 2j: Second Derivative of (j)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
For example, in the function \( y = x^{10} + 3x^6 \), the derivative is calculated by applying the Power Rule to both terms individually:
- For \( x^{10} \): the derivative is \( 10x^9 \).
- For \( 3x^6 \): the derivative is \( 18x^5 \) because you multiply the coefficient 3 by the new exponent 6.
Using constant notation clarify: if \( c \) is a constant, the derivative of \( cx^n \) becomes \( cnx^{n-1} \). So the rule works uniformly whether there's a coefficient or not!
Chain Rule
For example, consider the function \( y = (1-x)^2 \). Here, \( (1-x) \) is the inner function and the square is the outer function. Applying the Chain Rule involves:
- Differentiating the outer function: bring down the 2 and leave the inner function unchanged: \( 2(1-x) \).
- Then, multiply by the derivative of the inner function: for \( 1-x \), the derivative is \(-1\).
Quotient Rule
Take, for instance, \( f(x) = \frac{2x}{x+1} \):
- First, identify \( u(x) = 2x \) and \( v(x) = x+1 \).
- The derivatives are \( u'(x) = 2 \) and \( v'(x) = 1 \).
- Applying the Quotient Rule: \( \frac{(x+1)(2) - (2x)(1)}{(x+1)^2} \) simplifies to \( \frac{2}{(x+1)^2} \).
Second Derivative
Consider the function \( f(x) = \sqrt{x} \). The first derivative is \( f'(x) = \frac{1}{2}x^{-1/2} \). The second derivative is thus found by differentiating \( f'(x) \), yielding \( f''(x) = -\frac{1}{4}x^{-3/2} \).
- This tells us about the rate of change of the rate of change, doubling the value of insight.
Differentiation Techniques
These techniques include:
- Power Rule: Ideal for polynomial expressions and any term expressed as \( x^n \).
- Product Rule: Useful when differentiating products of two functions, expressing \( (u \cdot v)' \) as \( u'v + uv' \).
- Quotient Rule: Essential for functions presented as \( \frac{u}{v} \), following the formula \( \frac{vu' - uv'}{v^2} \).
- Chain Rule: Tackles nested functions by emphasizing the derivative of the outer function with respect to the inner function's derivative.