Chapter 1: Problem 3
State the equation and sketch the graph of each line described below. a. passing through (-4,-4) and \(\left(\frac{5}{3},-\frac{5}{3}\right)\) b. having slope 8 and \(y\) -intercept 6 c. having \(x\) -intercept 5 and \(y\) -intercept -3 d. passing through (5,6) and (5,-9)
Short Answer
Expert verified
a. \(y = \frac{7}{17}x - \frac{56}{17}\); b. \(y = 8x + 6\); c. \(y = \frac{3}{5}x - 3\); d. \(x = 5\).
Step by step solution
01
Find the equation of the line for Part a
To find the equation of the line passing through two points, use the point-slope formula. First, calculate the slope (m): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-\frac{5}{3} - (-4)}{\frac{5}{3} - (-4)} = \frac{-\frac{5}{3} + \frac{12}{3}}{\frac{5}{3} + \frac{12}{3}} = \frac{\frac{7}{3}}{\frac{17}{3}} = \frac{7}{17}. \] Use point-slope form: \[ y - y_1 = m(x - x_1). \] Choose point \((-4, -4)\): \[ y + 4 = \frac{7}{17}(x + 4). \] Simplify to find the equation: \[ y = \frac{7}{17}x - \frac{56}{17}. \]
02
Find the equation of the line for Part b
The line has a slope \(m\) of 8 and a y-intercept (b) of 6. Use the slope-intercept form \(y = mx + b\): \[ y = 8x + 6. \]
03
Find the equation of the line for Part c
Given the x-intercept (5,0) and y-intercept (0,-3), find the slope: \[ m = \frac{-3 - 0}{0 - 5} = \frac{-3}{-5} = \frac{3}{5}. \] Use the point-slope form with (0,-3): \[ y + 3 = \frac{3}{5}x. \] Simplify to get: \[ y = \frac{3}{5}x - 3. \]
04
Find the equation of the line for Part d
The line passes through the points (5,6) and (5,-9). Since the x-values are the same, this is a vertical line. Therefore, the equation does not depend on y and is simply \( x = 5 \).
05
Sketch the graphs
For Part a, plot the points (-4,-4) and (\frac{5}{3},-\frac{5}{3}) and draw the line passing through them using the equation \( y = \frac{7}{17}x - \frac{56}{17} \). For Part b, draw the line using the equation \( y = 8x + 6 \) with a slope of 8, starting at the y-intercept 6. For Part c, use the equation \( y = \frac{3}{5}x - 3 \) to plot the line through the x-intercept 5 and y-intercept -3. For Part d, recognize it's a vertical line at \( x = 5 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
When given two points, the point-slope form of a line is a useful tool to find the equation of the line. This form of the equation is written as \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a specific point on the line.
To calculate the slope \( m \), you need two points \( (x_1, y_1) \) and \( (x_2, y_2) \). The formula for the slope is \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
Use this slope with one of the points in the point-slope form: if you have a point \( (-4, -4) \) and \( \left(\frac{5}{3},-\frac{5}{3}\right) \), the slope \( m \) is calculated to be \( \frac{7}{17} \). Thus, the equation would be \( y + 4 = \frac{7}{17}(x + 4) \).
It provides a straightforward approach to deriving a line’s equation when you have distinct points.
To calculate the slope \( m \), you need two points \( (x_1, y_1) \) and \( (x_2, y_2) \). The formula for the slope is \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
Use this slope with one of the points in the point-slope form: if you have a point \( (-4, -4) \) and \( \left(\frac{5}{3},-\frac{5}{3}\right) \), the slope \( m \) is calculated to be \( \frac{7}{17} \). Thus, the equation would be \( y + 4 = \frac{7}{17}(x + 4) \).
It provides a straightforward approach to deriving a line’s equation when you have distinct points.
Slope-Intercept Form
The slope-intercept form is particularly popular because of its simplicity and ease of use. The equation is given by \( y = mx + b \), where \( m \) is the slope of the line and \( b \) is the y-intercept, which is the point where the line crosses the y-axis.
For instance, if you know a line has a slope of 8 and a y-intercept of 6, you can directly express its equation as \( y = 8x + 6 \). This format is very beneficial for graphing because the y-intercept \( b \) gives you a starting point on the graph and the slope determines the tilt and direction of the line.
For example, in the equation \( y = 8x + 6 \), the line will rise steeply because the slope is quite high, and it starts at point (0, 6) on the y-axis.
For instance, if you know a line has a slope of 8 and a y-intercept of 6, you can directly express its equation as \( y = 8x + 6 \). This format is very beneficial for graphing because the y-intercept \( b \) gives you a starting point on the graph and the slope determines the tilt and direction of the line.
For example, in the equation \( y = 8x + 6 \), the line will rise steeply because the slope is quite high, and it starts at point (0, 6) on the y-axis.
Graphing Lines
Graphing lines involves plotting the line defined by its equation on a coordinate plane. Start with the y-intercept for lines in slope-intercept form or use any point for point-slope form.
Then, apply the slope \( m \) by moving vertically and horizontally on the graph to plot another point. For instance, with the equation \( y = 8x + 6 \), begin at (0,6) on the y-axis and use the slope of 8 (rise/run = 8/1), moving 8 units up for every 1 unit to the right.
Draw a straight line through the plotted points to complete the graph. When using intercept form \( y = \frac{3}{5}x - 3 \), start at the y-intercept (0, -3) and move according to the slope \( \frac{3}{5} \), plotting subsequent points until the line is created.
Then, apply the slope \( m \) by moving vertically and horizontally on the graph to plot another point. For instance, with the equation \( y = 8x + 6 \), begin at (0,6) on the y-axis and use the slope of 8 (rise/run = 8/1), moving 8 units up for every 1 unit to the right.
Draw a straight line through the plotted points to complete the graph. When using intercept form \( y = \frac{3}{5}x - 3 \), start at the y-intercept (0, -3) and move according to the slope \( \frac{3}{5} \), plotting subsequent points until the line is created.
Intercepts
Intercepts are the points where a line crosses the x-axis and y-axis. These are vital to understanding the position and trajectory of a line in the coordinate plane.
The x-intercept occurs where the line crosses the x-axis \( (x, 0) \), and solving for \( x \) gives this intercept when \( y = 0 \). The y-intercept is found directly from equations in slope-intercept form \( y = mx + b \). Here, the point is \( (0, b) \).
For example, given an equation such as \( y = \frac{3}{5}x - 3 \), the y-intercept is immediately accessible as -3 (the point is (0, -3)), and solving \( \frac{3}{5}x - 3 = 0 \) finds the x-intercept. Grasping intercepts helps in effectively graphing the lines and understanding where they start and pass through the coordinate plane.
The x-intercept occurs where the line crosses the x-axis \( (x, 0) \), and solving for \( x \) gives this intercept when \( y = 0 \). The y-intercept is found directly from equations in slope-intercept form \( y = mx + b \). Here, the point is \( (0, b) \).
For example, given an equation such as \( y = \frac{3}{5}x - 3 \), the y-intercept is immediately accessible as -3 (the point is (0, -3)), and solving \( \frac{3}{5}x - 3 = 0 \) finds the x-intercept. Grasping intercepts helps in effectively graphing the lines and understanding where they start and pass through the coordinate plane.