Chapter 15: Problem 12
First show that the given vector field \(\mathbf{F}\) is irrotational; then apply the method of Example 3 to find a potential function \(\phi=\phi(x, y, z)\) for \(\mathbf{F}\). $$ \mathbf{F}=\left(3 y^{3}-10 x z^{2}\right) \mathbf{i}+9 x y^{2} \mathbf{j}-10 x^{2} z \mathbf{k} $$
Short Answer
Expert verified
The vector field \( \mathbf{F} \) is irrotational, and its potential function \( \phi(x, y, z) = 3y^3x - 5x^2z^2 + C \).
Step by step solution
01
Verify the Irrotational Property
To show that the vector field \( \mathbf{F} \) is irrotational, we need to check if its curl is zero. The curl of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by:\[abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k}\]Substitute \( P = 3y^3 - 10xz^2 \), \( Q = 9xy^2 \), and \( R = -10x^2z \):- \( \frac{\partial R}{\partial y} = 0 \) and \( \frac{\partial Q}{\partial z} = 0 \), giving \( \mathbf{i} \) component as 0.- \( \frac{\partial P}{\partial z} = -20xz \) and \( \frac{\partial R}{\partial x} = -20xz \), giving \( \mathbf{j} \) component as 0.- \( \frac{\partial Q}{\partial x} = 9y^2 \) and \( \frac{\partial P}{\partial y} = 9y^2 \), giving \( \mathbf{k} \) component as 0.Since all components of the curl are zero, \( \mathbf{F} \) is irrotational.
02
Set Up the Potential Function Equation
For an irrotational vector field, a potential function \( \phi \) exists such that \( \mathbf{F} = abla \phi \). Thus, we have the equations:\[\frac{\partial \phi}{\partial x} = 3y^3 - 10xz^2 \quad (1)\]\[\frac{\partial \phi}{\partial y} = 9xy^2 \quad (2)\]\[\frac{\partial \phi}{\partial z} = -10x^2z \quad (3)\]
03
Integrate to Find Potential Function (Step 1/3)
Start by integrating Equation (1) with respect to \( x \):\[\\phi(x, y, z) = \int (3y^3 - 10xz^2) \, dx = 3y^3x - 5x^2z^2 + g(y, z)\]where \( g(y, z) \) is an arbitrary function of \( y \) and \( z \) only.
04
Verify with Second Partial Derivative (Integration Check 2/3)
Differentiate \( \phi(x, y, z) = 3y^3x - 5x^2z^2 + g(y, z) \) with respect to \( y \), and set it equal to the \( \frac{\partial \phi}{\partial y} \) from Equation (2):\[\frac{\partial \phi}{\partial y} = 9xy^2 + \frac{\partial g}{\partial y}\]\[\9xy^2 + \frac{\partial g}{\partial y} = 9xy^2 \\implies \frac{\partial g}{\partial y} = 0\]Thus, \( g(y, z) \) is not dependent on \( y \), so \( g(y, z) = h(z) \).
05
Verify with Third Partial Derivative (Integration Check 3/3)
Substitute \( g(y, z) = h(z) \) and differentiate with respect to \( z \):\[\frac{\partial \phi}{\partial z} = -10x^2z + \frac{\partial h}{\partial z}\]Set it equal to \( \frac{\partial \phi}{\partial z} \) from Equation (3):\[-10x^2z + \frac{\partial h}{\partial z} = -10x^2z\]\[\implies \frac{\partial h}{\partial z} = 0\]Therefore, \( h(z) \) is a constant. Let \( h(z) = C \), where \( C \) is a constant. Hence, the potential function \( \phi(x, y, z) \) is:\[\phi(x, y, z) = 3y^3x - 5x^2z^2 + C\]
06
State the Potential Function
The potential function \( \phi(x, y, z) \) is found to be:\[\\phi(x, y, z) = 3y^3x - 5x^2z^2 + C\]This function is valid since the curl of \( \mathbf{F} \) is zero, confirming \( \mathbf{F} = abla \phi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Irrotational Vector Field
An irrotational vector field is a vector field where the curl is zero everywhere. In vector calculus, the curl is a measure of the field's rotation at a point. If a vector field is irrotational, it means that at no point does the field rotate around any axis. This is a very special condition in vector calculus, as it implies a certain type of symmetry and smoothness in the field.
To determine if a given vector field \( \mathbf{F} \) is irrotational, we calculate its curl. The curl of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by the vector:
To determine if a given vector field \( \mathbf{F} \) is irrotational, we calculate its curl. The curl of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by the vector:
- \( \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} \)
- \( \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \mathbf{j} \)
- \( \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k} \)
Potential Function
A potential function \( \phi \) for a vector field \( \mathbf{F} \) is a scalar function such that the gradient of \( \phi \) equals \( \mathbf{F} \). When we say a vector field is irrotational, it indicates the existence of such a potential function. This link between the field and the potential function simplifies the analysis of fields dramatically.
The method to find a potential function involves solving partial derivatives for equivalences to components of the field. In simpler terms, when \( \mathbf{F} \) is irrotational, it can be expressed by \( abla \phi = \mathbf{F} \), translating to a system of equations:
The method to find a potential function involves solving partial derivatives for equivalences to components of the field. In simpler terms, when \( \mathbf{F} \) is irrotational, it can be expressed by \( abla \phi = \mathbf{F} \), translating to a system of equations:
- \( \frac{\partial \phi}{\partial x} = F_x \)
- \( \frac{\partial \phi}{\partial y} = F_y \)
- \( \frac{\partial \phi}{\partial z} = F_z \)
Curl of a Vector Field
The curl of a vector field measures the rotation or curling behavior of the field. It is denoted and calculated through the cross-product of the del operator, \( abla \), with the vector field. The curl is represented as \( abla \times \mathbf{F} \).
In practical terms, the curl is like fingerprinting the swirling motion a fluid might have at a given point in the field. If the curl is zero, there's no such swirling or rotational behavior, and the field is defined as irrotational. This highlights a property making it possible for potential functions to be derived.
For the calculation, remember that for any vector field of form \( \mathbf{A} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), evaluate each component using:
In practical terms, the curl is like fingerprinting the swirling motion a fluid might have at a given point in the field. If the curl is zero, there's no such swirling or rotational behavior, and the field is defined as irrotational. This highlights a property making it possible for potential functions to be derived.
For the calculation, remember that for any vector field of form \( \mathbf{A} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), evaluate each component using:
- \( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \)
- \( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \)
- \( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \)
Gradient Field
The concept of a gradient field is centered around the idea that a vector field can be expressed as the gradient of some scalar field, \( \phi \). In mathematical terms, for a vector field \( \mathbf{F} \) to be a gradient field, it must satisfy \( \mathbf{F} = abla \phi \). If you imagine \( \phi \) as representing height on a topographic map, \( abla \phi \) points in the direction of steepest ascent.
A key characteristic of a gradient field is that it must be irrotational. This means that if it can be expressed as the gradient of a potential function, its curl must be zero. For students solving problems involving vector fields, recognizing that a non-zero curl implies no potential function is possible is important.
In the original exercise, once it was confirmed that \( \mathbf{F} \) was irrotational, the establishment of the gradient field \( \mathbf{F} = abla \phi \) became a straightforward process managed through systematic integration of the components of \( \mathbf{F} \). This provides a tangible link to the overall behavior of the field, leading us back to forming the potential function \( \phi \).
A key characteristic of a gradient field is that it must be irrotational. This means that if it can be expressed as the gradient of a potential function, its curl must be zero. For students solving problems involving vector fields, recognizing that a non-zero curl implies no potential function is possible is important.
In the original exercise, once it was confirmed that \( \mathbf{F} \) was irrotational, the establishment of the gradient field \( \mathbf{F} = abla \phi \) became a straightforward process managed through systematic integration of the components of \( \mathbf{F} \). This provides a tangible link to the overall behavior of the field, leading us back to forming the potential function \( \phi \).