/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Let $$ f(x, y)=\frac{2 x^{2}... [FREE SOLUTION] | 91Ó°ÊÓ

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Let $$ f(x, y)=\frac{2 x^{2} y}{x^{4}+y^{2}} $$ (a) Show that \(f(x, y) \rightarrow 0\) as \((x, y) \rightarrow(0,0)\) along any and every straight line through the origin. (b) Show that \(f(x, y) \rightarrow 1\) as \((x, y) \rightarrow(0,0)\) along the parabola \(y=x^{2}\). Conclude that the limit of \(f(x, y)\) as \((x, y) \rightarrow(0,0)\) does not exist. The graph of \(f\) is shown in Fig. 13.3.9.

Short Answer

Expert verified
The limit does not exist since different paths to (0,0) give different results.

Step by step solution

01

Evaluate the limit along a straight line through the origin

Consider the straight line through the origin given by \( y = mx \) where \( m \) is a constant. Substitute \( y = mx \) into \( f(x, y) \):\[f(x, mx) = \frac{2x^2(mx)}{x^4 + (mx)^2} = \frac{2mx^3}{x^4 + m^2x^2}\]Divide the numerator and the denominator by \( x^2 \) to simplify:\[f(x, mx) = \frac{2mx}{x^2 + m^2}\]As \( (x, mx) \to (0, 0) \), which means \( x \to 0 \), it follows that \( f(x, mx) \to 0 \) for any \( m \).
02

Evaluate the limit along the parabola y = x^2

Now consider the path described by \( y = x^2 \). Substitute \( y = x^2 \) into \( f(x, y) \):\[f(x, x^2) = \frac{2x^2(x^2)}{x^4 + (x^2)^2} = \frac{2x^4}{x^4 + x^4} = \frac{2x^4}{2x^4} = 1\]As \( (x, x^2) \to (0, 0) \), the function \( f(x, x^2) \to 1 \).
03

Conclusion about the existence of the limit

Since we found different limits along different paths:1. Along any line through the origin, \( f(x, y) \to 0 \).2. Along the parabola \( y = x^2 \), \( f(x, y) \to 1 \).These differing limits imply that the overall limit of \( f(x, y) \) as \( (x, y) \to (0,0) \) does not exist, because the multilinear approach yields different results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Path-Dependent Limits
When evaluating limits in multiple variables, it's essential to understand that the path we choose to approach a point can impact the result. A path-dependent limit arises when different paths to the same point yield different limit values. In our original exercise, we evaluated the function
  • First, along straight lines through the origin by substituting the path equation \( y = mx \). This simplified to \( \frac{2mx}{x^2 + m^2} \), and as \( x \to 0 \), it consistently approached 0.
  • Then, along the parabola defined by \( y = x^2 \). Substituting \( y = x^2 \) simplified the original function to a constant value of 1.
These two different paths clearly showed distinct limits, indicating the function is path-dependent. Such cases are crucial to identify, especially when the limit at a point is being determined in a multivariable function.
Limits in Two Variables
In dealing with functions of two variables, understanding how limits work is a bit more intricate than in single-variable calculus. Instead of a single point on a line, the limit in two variables involves approaching a point through the plane from any direction. Thus, for a function \( f(x, y) \), the idea is that as you come closer to a point \( (a, b) \) from various directions in the plane, the function's output should approach a specific value.In the exercise, \( f(x, y) = \frac{2x^2y}{x^4+y^2} \) included two different approaches:
  • Using a path like the line \( y=mx \), where after simplification, as \( (x, y) \rightarrow (0,0) \), the result was consistently 0.
  • Using a nonlinear path such as \( y = x^2 \), where simplification led to a limit of 1.
In problems with more than one variable, it becomes vital to evaluate numerous potential paths to rightly determine or disprove the existence of a common limit.
Existence of Limits
A central question in studying multivariable limits is whether or not the limit exists. For a function of two variables, like in our example, a limit \( \lim_{(x, y) \to (0,0)} f(x, y) \) is said to exist if, and only if, the value approached by the function \( f(x, y) \) is the same along every possible path to the point \( (0,0) \).Here's what happened in the problem:
  • Along any line through the origin, the function approached 0.
  • Along the parabola \( y = x^2 \), the function approached 1.
Since these outcomes are different, the overall limit does not exist. Distinct paths yielding different results showcase the non-existence of a consistent limit at that point. In essence, for a limit to exist in a multivariable setting, consistency across all possible paths is necessary. Otherwise, as demonstrated, the varied limits from different paths lead to the conclusion that a unified limit does not exist. This understanding reinforces the importance of checking multiple paths in multivariable calculus to determine limit existence accurately.

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