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Suppose that \(\sum a_{n}\) is a convergent positive-term series and that \(\left\\{c_{n}\right\\}\) is a sequence of positive numbers with limit zero. Prove that \(\sum a_{n} c_{n}\) converges.

Short Answer

Expert verified
The series \( \sum a_n c_n \) converges because the terms \( a_n c_n \) become arbitrarily small as both \( a_n \) reduces (due to series convergence) and \( c_n \to 0 \), allowing the limit comparison test with \( \sum a_n \).

Step by step solution

01

Understand the Problem Statement

We are given a convergent series \( \sum a_n \) where all terms \( a_n \) are positive. Additionally, we have a sequence \( \{ c_n \} \) such that each \( c_n \) is positive and the limit of this sequence as \( n \to \infty \) is zero. We need to show that the series \( \sum a_n c_n \) also converges.
02

Analyze Given Conditions

The series \( \sum a_n \) is convergent, so its partial sums \( S_n = a_1 + a_2 + \cdots + a_n \) converge to a limit as \( n \to \infty \). Also, \( c_n \to 0 \) as \( n \to \infty \). These facts are central assumptions that we will leverage in our proof.
03

Utilize the Convergent Series

Since \( \sum a_n \) converges, by the definition of convergence for series, we can infer that terms \( a_n \) become very small as \( n \) becomes large. This affects the behavior of the series we are trying to prove convergence for, \( \sum a_n c_n \).
04

Use the Limit of Zero Condition

Given that \( c_n \to 0 \), for any given \( \epsilon > 0 \), there exists some \( N_1 \) such that for all \( n > N_1 \), \( c_n < \epsilon \). This means \( c_n \) can be made arbitrarily small.
05

Apply the Limit Comparison Test

Consider the series \( \sum a_n c_n \). Since both sequences are positive, we use the fact that both terms can be made small: \( |a_n c_n| \leq a_n \cdot \text{small number} \), making each \( |a_n c_n| \) small enough as \( n \to \infty \). For all \( n > \max(N, N_1) \), we have \( a_n c_n < \epsilon \cdot a_n \). Thus, since \( \sum a_n \) converges, \( \sum a_n c_n \) converges by the comparison test with terms \( a_n \cdot \epsilon \), where \( \epsilon \cdot a_n \to 0 \).
06

Conclude Convergence

Since \( a_n c_n \) can be made arbitrarily small and \( \sum a_n \) is a converging series, it follows that \( \sum a_n c_n \) converges as well, by leveraging the smallness of \( c_n \) to compare terms to those of \( \sum a_n \) which are themselves converging.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Positive-term Series
When working with series in mathematics, a **positive-term series** is a sequence of sums where each term is positive. In simpler terms, all its elements, like the terms of the series \( \sum a_n \) mentioned in the problem, have values greater than zero.

Positive-term series are easier to handle because you don't have to worry about cancellations between positive and negative terms. As they only increase or stay the same, these series offer a simplified environment for analyzing convergence behavior. This characteristic allows particular techniques, like the comparison test, to be applied more effectively. Understanding whether such a series converges or diverges can lead us to infer more about the nature of related series.
  • If the series converges, its partial sums approach a finite limit.
  • If it diverges, the sums might grow without bound, or fail to settle at a particular number.
Limit Comparison Test
The **Limit Comparison Test** is a handy tool for determining the convergence or divergence of a series. It compares the series in question with another series whose convergence properties are already known.

For two series \( \sum a_n \) and \( \sum b_n \), if the limit \( \lim_{n \to \infty} \frac{a_n}{b_n} = c \) exists, where \( c \) is a positive, finite number, then both series will either converge or diverge together.
  • This test is particularly useful when working with positive-term series because it ensures that terms don't cancel out.
  • Knowing one series converges or diverges can give insight into another, less obvious series.
In our exercise, this test helps in understanding \( \sum a_n c_n \) using the known properties of \( \sum a_n \). The positive elements allow us to apply this comparison test after manipulating \( c_n \) towards zero.
Convergent Series
A **convergent series** is a series whose sequence of partial sums approaches a finite limit as more terms are added. For the series \( \sum a_n \), this means that as you add up the terms \( a_1, a_2, a_3, \ldots \), the total will get closer and closer to a specific number, rather than growing indefinitely or oscillating.
  • This behavior is often the dealbreaker in determining the convergence of related series.
  • In this problem, the known convergence of \( \sum a_n \) acts as a critical starting point for proving that \( \sum a_n c_n \) also converges.
Recognizing a series as convergent simplifies validating modifications to it, like multiplying each term by a decaying sequence, \( c_n \), thereby helping derive the convergence of new constructs formed this way.
Limit of a Sequence
The concept of the **limit of a sequence** refers to the value that the elements of a sequence \( \{ c_n \} \) approach as the index \( n \) becomes very large. When we say \( c_n \to 0 \), it means that for large \( n \), the value of \( c_n \) becomes arbitrarily close to zero.

This notion is a pillar in the existing problem's solution. By proving that \( c_n \to 0 \), we can confidently state that the impact of \( c_n \) on the terms of \( \sum a_n c_n \) is progressively diminishing.
  • This characteristic allows us to argue that the additional product sequence doesn't disrupt previously witnessed convergence.
  • Sequences that tend towards zero gently introduce a shrinking factor, making them ideal for scaling positive terms without affecting overall convergence.
Thus, using this concept, one can effectively control the growth of terms in a series, ensuring that eventual sums do not diverge.

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