Chapter 11: Problem 26
Find the interval of convergence of each power series. \(\sum_{n=1}^{x} \frac{(-1)^{n+1}}{n \cdot 10^{n}}(x-2)^{n}\)
Short Answer
Expert verified
The interval of convergence is \([-8, 12)\).
Step by step solution
01
Initial Setup and Identification
First, let's identify the given power series: \( \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n \cdot 10^{n}}(x-2)^{n} \). This is a power series centered at \(x = 2\). Our goal is to find the interval of convergence of this series.
02
Apply the Ratio Test
To find the interval of convergence, we use the Ratio Test. Consider \(a_n = \frac{(-1)^{n+1}}{n \cdot 10^{n}}(x-2)^{n}\). The Ratio Test requires evaluating \[\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \left| \frac{\frac{(-1)^{n+2}}{(n+1) \cdot 10^{n+1}}(x-2)^{n+1}}{\frac{(-1)^{n+1}}{n \cdot 10^{n}}(x-2)^{n}} \right|.\]
03
Simplify the Ratio
Simplifying the expression from the Ratio Test:\[\left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \left| \frac{n}{n+1} \cdot \frac{(x-2)}{10} \right| = \lim_{n \to \infty} \frac{n}{n+1} \cdot \left| \frac{x-2}{10} \right|.\]As \(n\) approaches infinity, \( \frac{n}{n+1} \to 1 \). So, the limit becomes:\[\left| \frac{x-2}{10} \right| < 1.\]
04
Solve the Inequality for Convergence
Solve the inequality \( \left| \frac{x-2}{10} \right| < 1\):\[\left| x-2 \right| < 10.\]This can be rewritten as:\[-10 < x-2 < 10.\]Adding 2 to each part, we get:\[-8 < x < 12.\]
05
Testing Endpoints
Check the endpoints \(x = -8\) and \(x = 12\) for convergence by substituting them back into the original series.1. At \(x = -8\): The series becomes \(\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n} \cdot (-1)^n \), which converges (alternating harmonic series).2. At \(x = 12\): The series becomes \(\sum_{n=1}^{\infty} \frac{1}{n} \), which diverges (harmonic series).
06
Determine the Interval of Convergence
Since the series converges at \(x = -8\) but not at \(x = 12\), the interval of convergence is \([-8, 12)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series
Power series are expressions of the form \( \sum_{n=0}^{\infty} a_n (x-c)^n \). These series are centered at a specific point \(c\), and involve terms that become increasingly more complex as \(n\) increases.
In the provided exercise, we are dealing with a power series centered at \(x = 2\), written as:
In the provided exercise, we are dealing with a power series centered at \(x = 2\), written as:
- \(\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n \cdot 10^{n}}(x-2)^{n} \)
Ratio Test
The Ratio Test is a powerful tool used to determine the convergence of a series. It simplifies and quantifies how the terms of a series grow relative to each other.
To apply the Ratio Test, you analyze the series’ terms, \(a_n\), and calculate the \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). This gives a clear criterion:
To apply the Ratio Test, you analyze the series’ terms, \(a_n\), and calculate the \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). This gives a clear criterion:
- If the limit is less than 1, the series converges absolutely.
- If the limit is greater than 1, the series diverges.
- When the limit equals 1, the test is inconclusive.
Convergence of Series
Understanding convergence means knowing when a series sums up to a finite value. For our power series, this convergence depends on the values of \(x\) in relation to the series' behavior. The derived inequality from the ratio test, \( \left| x-2 \right| < 10 \), translates into the interval \(-8 < x < 12\). This is where the series has the potential to converge.
Add 2 to each term of the inequality to account for the center of the series, ensuring it focuses on its convergence interval related to \(x\).When a series converges, it means the infinite sum of its terms approaches a specific, finite value. This behavior is tested at the interval's endpoints to check whether they are included.
Add 2 to each term of the inequality to account for the center of the series, ensuring it focuses on its convergence interval related to \(x\).When a series converges, it means the infinite sum of its terms approaches a specific, finite value. This behavior is tested at the interval's endpoints to check whether they are included.
Endpoints Testing
Endpoints testing involves checking the convergence of a series at the borders of its interval, determined through the ratio test.In the solution:
- We tested \(x = -8\) by substituting into the original series, leading to an alternating harmonic series which converges.
- We also tested \(x = 12\), yielding a harmonic series which is known to diverge.