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Determine whether the sequence \(\left\\{a_{n}\right\\}\) converges, and find its limit if it does converge. \(a_{n}=n \cos \pi n\)

Short Answer

Expert verified
The sequence \(a_n = n \cos \pi n\) does not converge.

Step by step solution

01

Understand the Sequence

The sequence is given by \(a_{n} = n \cos \pi n\). We know that \(\cos \pi n\) alternates between \(1\) and \(-1\) depending on whether \(n\) is even or odd. Specifically, \(\cos \pi n = (-1)^n\). Thus, the sequence becomes \(a_n = n(-1)^n\).
02

Evaluate the Behavior of the Sequence

Substitute even and odd values for \(n\) to understand the sequence. For even \(n\), \(\cos \pi n = 1\), so \(a_n = n(1) = n\). For odd \(n\), \(\cos \pi n = -1\), so \(a_n = n(-1) = -n\). Thus, the sequence alternates between positive and negative, growing in absolute value.
03

Determine the Limit as \(n\) Approaches Infinity

As \(n\) increases, the terms of \(a_n\) increase in magnitude infinitely because the sequence behaves as \(n\) and \(-n\). Since there is no finite limit for the elements of the sequence becoming arbitrarily large (positive or negative), the sequence does not converge.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Sequences
When we talk about the convergence of sequences, we're asking whether a sequence of numbers approaches a specific value as it progresses towards infinity. Think of it like a row of dominoes lined up perfectly. As you follow the sequence of dominoes, they lead you directly to one spot — that's convergence.
For a sequence to converge, the terms must get closer and closer to a particular number, known as the limit, the further along you go. If the sequence keeps heading off and doesn't settle near a specific number, it fails to converge.
  • Every sequence that converges has a limit, but not all sequences have one.
  • If no such number exists that the sequence settles into, we say that the sequence diverges.
Grasping convergence is key to understanding whether a sequence behaves nicely (i.e., it converges) or whether it doesn't have a particular direction (i.e., it diverges). In our case, the sequence does not converge because the numbers grow indefinitely large in absoulte values.
Limits
The concept of a limit is central to calculus and helps define the behavior of a sequence or a function as it approaches a particular point. When determining the limit of a sequence, ask yourself what value the sequence seems to head towards as we move along the sequence.
When we express limits in mathematical notation, it typically looks like this: \\[ \\lim_{{n \to\infty}}a_n = L,\\] \where \(a_n\) is your sequence, and \(L\) is what you suspect the sequence is settling into. However, not all sequences have a limit.
For example, for the sequence \(a_n = n(-1)^n\), as \(n\) gets larger, the values are \(n\) and \(-n\). These values don't look like they're settling down to any particular number — they keep growing to infinity, both positively and negatively. Hence, this sequence doesn't have a limit.
Alternating Sequences
An alternating sequence is one that changes signs as it progresses. Imagine flipping a coin at every step — first heads, then tails — that back-and-forth pattern is akin to alternating sequences.
In mathematics, an alternating sequence can often be identified by expressions containing \((-1)^n\), where the sign flips depending on whether \(n\) is odd or even. This characteristic creates an 'alternating' effect in the sequence's terms. In our provided sequence, \(a_n = n(-1)^n\), the function \((-1)^n\) makes the sequence "switch sides":
  • When \(n\) is even, \(a_n\) is positive.
  • When \(n\) is odd, \(a_n\) is negative.
This flipping sign causes the sequence to alternate. Even though the sequence alternates, without bounding itself closer to a single limit point, in this case, it does not help the sequence to converge. Such sequences can oscillate wildly and might never zero in on a particular limit.

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