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For each of the triple integrals,(a) sketch the domain of integration in \(\mathbb{R}^{3},(\mathbf{b})\) write an equivalent expression in which the first integration is with respect to \(x,\) and \((\mathbf{c})\) write an equivalent expression in which the first integration is with respect to \(y\). $$ \int_{-1}^{1}\left(\int_{0}^{\sqrt{1-x^{2}}}\left(\int_{0}^{1} f(x, y, z) d z\right) d y\right) d x $$

Short Answer

Expert verified
1. Semi-cylinder region; 2. \\(\int_{0}^{1} \int_{-1}^{1} \int_{0}^{\sqrt{1-x^{2}}} f(x, y, z) \, dy \, dx \, dz\\); 3. \\(\int_{0}^{1} \int_{0}^{1} \int_{-\sqrt{1-y^{2}}}^{\sqrt{1-y^{2}}} f(x, y, z) \, dx \, dz \, dy\\).

Step by step solution

01

Sketch the Domain in 3D

The domain of integration is described by the bounds \(-1 \leq x \leq 1\), \(0 \leq y \leq \sqrt{1-x^2}\), and \(0 \leq z \leq 1\). In \(\mathbb{R}^3\), the region is a semi-cylinder along the z-axis, with its projection in the xy-plane being the upper half of a circle \(x^2 + y^2 \leq 1\) in the positive y-region, extending vertically from \(z=0\) to \(z=1\).
02

Adjust Order with Respect to x First

To reorder the triple integral with respect to x first, we keep z-constant limits as \(0 \, \text{to} \, 1\) and swap x and y limits. For a fixed z, x varies from \(-1\) to \(1\) and y becomes dependent on z and x. Thus, the integral becomes: \\[ \int_{0}^{1} \int_{-1}^{1} \int_{0}^{\sqrt{1-x^{2}}} f(x, y, z) \, dy \, dx \, dz.\]
03

Adjust Order with Respect to y First

To rewrite the triple integral with y first, identify y's range first from \(0 \, \text{to} \, 1\), and for each fixed y, x varies from \(-\sqrt{1-y^2}\) to \(\sqrt{1-y^2}\). Finally, z ranges from 0 to 1. Therefore, the integral becomes: \\[\int_{0}^{1} \int_{0}^{1} \int_{-\sqrt{1-y^{2}}}^{\sqrt{1-y^{2}}} f(x, y, z) \, dx \, yz \, dz \, dy.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Domain of Integration
When dealing with triple integrals, understanding the **domain of integration** is crucial. The domain describes the region over which we integrate in three-dimensional space. For the given exercise, the domain is defined with specific boundaries for the variables \(x\), \(y\), and \(z\). This region can be visualized in \(\mathbb{R}^3\) as having limits: \(-1 \leq x \leq 1\), \(0 \leq y \leq \sqrt{1-x^2}\), and \(0 \leq z \leq 1\). This forms a semi-cylindrical shape that lies along the z-axis.

The projection of this volume onto the xy-plane is the upper half of a circle with radius 1, described by \(x^2 + y^2 \leq 1\). The z-values stack this circular footprint vertically from \(z = 0\) to \(z = 1\), making it a three-dimensional volume. Understanding these boundaries helps visualize what part of the three-dimensional space is being considered in the integration process.
Importance of the Order of Integration
The **order of integration** in a triple integral changes the sequence in which integration is performed over the variables. Initially, the integration order in the given problem is \(dz\), \(dy\), \(dx\). But depending on the scenario, it might be useful to change this order. This may simplify the integration process by tackling more complex parts first, or aligning integration limits more conveniently.
  • *Integration with Respect to x First:* Here, we change the order to \(dx\), \(dy\), \(dz\). For this, the limits are adapted, keeping the z limit independent as \(0\ to \ 1\) and interchanging x and y such that y is dependent on \(x\).
  • *Integration with Respect to y First:* In this approach, y is integrated first \(dy\). The adjustment requires recognizing that y has definite limits \(0\) to \(1\), with x limits being dependent on y to ensure that inside the circular region \(-\sqrt{1-y^2}\leq x \leq \sqrt{1-y^2}\).
When multiple variables are integrated, the nesting of limits changes, impacting both the integral's setup and solving strategy.
Applying Cylindrical Coordinates
Though not directly required for this problem, using **cylindrical coordinates** can sometimes simplify integration in regions like cylinders or circular shapes. In cylindrical coordinates, we describe a point in \(\mathbb{R}^3\) using \((r, \theta, z)\) instead of \((x, y, z)\).
  • **Conversion Formulas:** Here, \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\). The limits of \(r\) often range from \(0\) to the radius of the circular region, and \(\theta\) from \(0\) to \(2\pi\), providing a full rotation.
  • **Benefits in Integration:** This system can simplify boundaries in circular or partially circular integration regions. The Jacobian, \(r\), adjusts the volume element in integral calculations as \(dr\,d\theta\,dz\).
This can make complex regions more intuitive to handle, though care must be taken with variable conversions and keeping track of the Jacobian determinant.

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Most popular questions from this chapter

For each of the triple integrals,(a) sketch the domain of integration in \(\mathbb{R}^{3},(\mathbf{b})\) write an equivalent expression in which the first integration is with respect to \(x,\) and \((\mathbf{c})\) write an equivalent expression in which the first integration is with respect to \(y\). $$ \int_{0}^{1}\left(\int_{x}^{1}\left(\int_{0}^{y} f(x, y, z) d z\right) d y\right) d x $$

Let \(D\) be the unit square \(0 \leq x \leq 1,0 \leq y \leq 1,\) and let \(f: D \rightarrow \mathbb{R}\) be the function given by \(f(x, y)=\min \\{x, y\\} .\) Find \(\iint_{D} f(x, y) d x d y\).

Let \(S\) be the surface described in cylindrical coordinates by \(z=\theta, 0 \leq r \leq 1,0 \leq \theta \leq 4 \pi\). It is called a helicoid. Converting to rectangular coordinates gives a parametrization: $$ \sigma:[0,1] \times[0,4 \pi] \rightarrow \mathbb{R}^{3}, \quad \sigma(r, \theta)=(r \cos \theta, r \sin \theta, \theta) $$ (a) Describe the curve that is traced out by \(\sigma\) if \(r=1 / 2\) is held fixed and \(\theta\) varies, that is, the curve parametrized by the path \(\alpha(\theta)=\sigma\left(\frac{1}{2}, \theta\right), 0 \leq \theta \leq 4 \pi\). (b) Similarly, describe the curve that is traced out by \(\sigma\) if \(\theta=\pi / 4\) is held fixed and \(r\) varies, that is, the curve parametrized by \(\beta(r)=\sigma\left(r, \frac{\pi}{4}\right), 0 \leq r \leq 1\) (c) Describe \(S\) in a few words, and draw a sketch.

Find the centroid of the triangular region in \(\mathbb{R}^{2}\) with vertices (0,0),(1,2) , and (1,3) .

The eye of a tornado is positioned directly over the origin in the plane. Suppose that the wind speed on the ground at the point \((x, y)\) is given by \(v(x, y)=30\left(x^{2}+y^{2}\right)\) miles per hour. (a) Find the average wind speed on the square \(R=[0,2] \times[0,2]\). (b) Find all points \((x, y)\) of \(R\) at which the wind speed equals the average.

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