Chapter 3: Problem 3
Let a be a point in \(\mathbb{R}^{n}\), and let \(r\) be a positive real number. Prove that the open ball \(B(\mathbf{a}, r)\) is an open set in \(\mathbb{R}^{n}\).
Short Answer
Expert verified
The open ball \(B(\mathbf{a}, r)\) is open because for every point in it, you can find a neighborhood entirely within the ball.
Step by step solution
01
Understanding the Open Ball
An open ball in \(\mathbb{R}^n\) centered at point \(\mathbf{a}\) with radius \(r\) is defined as the set \(B(\mathbf{a}, r) = \{ \mathbf{x} \in \mathbb{R}^n : \|\mathbf{x} - \mathbf{a}\| < r \}\), where \(\|\cdot\|\) denotes the Euclidean norm. An open set in \(\mathbb{R}^n\) is a set where, for any point in the set, there exists a neighborhood completely contained within the set.
02
Selecting an Arbitrary Point
Choose an arbitrary point \(\mathbf{p}\) from the open ball \(B(\mathbf{a}, r)\), which means \(\|\mathbf{p} - \mathbf{a}\| < r\). Our goal is to show that there is a neighborhood around \(\mathbf{p}\) that is entirely contained in \(B(\mathbf{a}, r)\).
03
Choosing a Neighborhood Radius
Since \(\|\mathbf{p} - \mathbf{a}\| < r\), define \(\epsilon = r - \|\mathbf{p} - \mathbf{a}\|\). This \(\epsilon\) is positive because \(\|\mathbf{p} - \mathbf{a}\|\) is strictly less than \(r\). We will use \(\epsilon\) to construct a neighborhood around \(\mathbf{p}\).
04
Constructing the Neighborhood
Consider the neighborhood \(N(\mathbf{p}, \epsilon) = \{ \mathbf{x} \in \mathbb{R}^n : \|\mathbf{x} - \mathbf{p}\| < \epsilon \}\). We need to show this neighborhood is contained within \(B(\mathbf{a}, r)\).
05
Proving the Neighborhood Containment
For any point \(\mathbf{x}\) in the neighborhood, \(\|\mathbf{x} - \mathbf{p}\| < \epsilon\). By the triangle inequality, \(\|\mathbf{x} - \mathbf{a}\| \leq \|\mathbf{x} - \mathbf{p}\| + \|\mathbf{p} - \mathbf{a}\|\). Since \(\|\mathbf{x} - \mathbf{p}\| < \epsilon\) and \(\epsilon = r - \|\mathbf{p} - \mathbf{a}\|\), it follows that \(\|\mathbf{x} - \mathbf{a}\| < r\). Thus, every \(\mathbf{x}\) in \(N(\mathbf{p}, \epsilon)\) is also in \(B(\mathbf{a}, r)\).
06
Conclusion
Since for every point \(\mathbf{p} \in B(\mathbf{a}, r)\) there exists a neighborhood \(N(\mathbf{p}, \epsilon)\) entirely contained within \(B(\mathbf{a}, r)\), this implies \(B(\mathbf{a}, r)\) is an open set in \(\mathbb{R}^n\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Euclidean norm
The Euclidean norm is a way to measure the length or size of a vector in the Euclidean space. For any vector \[ \mathbf{x} = (x_1, x_2, ..., x_n) \] in \( \mathbb{R}^n \), the Euclidean norm is defined as: \[ \| \mathbf{x} \| = \sqrt{x_1^2 + x_2^2 + ... + x_n^2} \] This formula essentially follows the Pythagorean theorem to calculate the distance from the origin to the point represented by the vector.
- It's the most natural way of measuring distance in our usual geometric concept of space.
- In the context of normed vector spaces, it's one of the most common and fundamental norms due to its simplicity and empirical origin from physical space measurement.
- The Euclidean norm is often denoted by double vertical bars "\( \| \cdot \| \)", reflecting its significance in indicating vector magnitude.
triangle inequality
The triangle inequality is a fundamental property of norms, and specifically the Euclidean norm in this case. It states that for any vectors \( \mathbf{u} \), \( \mathbf{v} \) in \( \mathbb{R}^n \): \[ \| \mathbf{u} + \mathbf{v} \| \leq \| \mathbf{u} \| + \| \mathbf{v} \| \] This inequality can be visualized by imagining the scenario in a triangle where the sum of the lengths of any two sides must be greater than or equal to the length of the third side.
- In geometric terms, it means the direct path between two points is the shortest.
- It ensures the distances behave in a consistent way, crucial for the properties of space like those seen in our exercise.
- This inequality simplifies understanding complex vector operations by providing a clear bound on how norms interact during addition.
neighborhood containment
In topology, the concept of a neighborhood is pivotal to understanding open sets, like the open ball in Euclidean space. A neighborhood of a point \( \mathbf{p} \) in \( \mathbb{R}^n \) is essentially a set of points surrounding \( \mathbf{p} \) that belongs to the larger set \( S \). Formally, for a point \( \mathbf{p} \) and radius \( \epsilon > 0 \), the neighborhood is defined as: \[ N(\mathbf{p}, \epsilon) = \{ \mathbf{x} \in \mathbb{R}^n : \| \mathbf{x} - \mathbf{p} \| < \epsilon \} \] Having neighborhoods contained within open sets is key in determining openness.
- An open set includes a neighborhood around each of its points.
- This property allows the open ball \( B(\mathbf{a}, r) \) itself to be open when every point \( \mathbf{p} \) has a fully enclosed neighborhood inside the ball.
- The concept helps generalize the understanding of continuity and limit processes within different spaces.