/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 Consider a random sample of size... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider a random sample of size \(n\) from the "shifted exponential" distribution with pdf \(f(x ; \theta)=e^{-(x-\theta)} \quad\) for \(x>\theta\) and 0 otherwise (the graph is that of the ordinary exponential pdf with \(\lambda=1\) shifted so that it begins its descent at \(\theta\) rather than at 0 ). Let \(Y_{1}\) denote the smallest order statistic, and show that the likelihood ratio test of \(H_{0}: \theta \leq 1\) versus \(H_{\mathrm{a}}: \theta>1\) rejects the null hypothesis if \(y_{1}\), the observed value of \(Y_{1}\), is \(\geq c\).

Short Answer

Expert verified
Reject \(H_0\) if the smallest observed value \(y_1 \geq c\), where \(c\) is determined by the critical value.

Step by step solution

01

Define the likelihood function

The likelihood function for a sample \( x_1, x_2, \ldots, x_n \) from a shifted exponential distribution with \( \theta \) is given by: \[L(\theta; x_1, x_2, \ldots, x_n) = \prod_{i=1}^{n} e^{-(x_i - \theta)} = e^{-(\sum_{i=1}^{n} x_i - n\theta)}.\]This result follows because each \(x_i\) is independent and follows an exponential distribution with scale parameter 1, shifted by \(\theta\). The likelihood is valid for \( \theta < x_i \).
02

Define the likelihood ratio test statistic

The likelihood ratio test for testing \( H_0: \theta \leq 1 \) versus \( H_a: \theta > 1 \) compares the likelihood under the null hypothesis to the likelihood under the alternative hypothesis. For \( \theta = \theta_0 = 1 \), the likelihood under \(H_0\) is: \[ L(1; x_1, x_2, \ldots, x_n) = e^{-(\sum_{i=1}^{n} x_i - n)}. \]For \( \theta = y_1 \) under \(H_a\), where \( y_1 \) is the smallest observed value: \[ L(y_1; x_1, x_2, \ldots, x_n) = e^{-(\sum_{i=1}^{n} x_i - n y_1)}. \]
03

Calculate the likelihood ratio

The likelihood ratio \( \lambda \) is given by: \[\lambda = \frac{L(1; x_1, x_2, \ldots, x_n)}{L(y_1; x_1, x_2, \ldots, x_n)} = \frac{e^{-(\sum_{i=1}^{n} x_i - n)}}{e^{-(\sum_{i=1}^{n} x_i - n y_1)}} = e^{n (y_1 - 1)}.\]The likelihood ratio compares the maximum likelihood assuming \(\theta = 1\) to the likelihood assuming \(\theta = y_1\).
04

Establish rejection condition

To reject \( H_0 \), the likelihood ratio should be less than a given critical value \( \alpha \), hence:\[ e^{n(y_1 - 1)} < \alpha. \]Taking the natural logarithm of both sides yields:\[ n(y_1 - 1) < \, \ln(\alpha), \]which simplifies to:\[\ y_1 < 1 + \frac{\ln(\alpha)}{n}. \]Thus, the null hypothesis \(H_0\) is rejected if \(y_1\) is greater than or equal to a certain critical value \(c\) depending on \(\alpha\).
05

Interpret the result

From Step 4, the test concludes that we reject \( H_0\) if the smallest order statistic \(y_1\) is sufficiently large. This implies that larger values of \(y_1\) indicate that \(\theta > 1\), supporting the alternative hypothesis \(H_a\). The exact rejection region depends on \(\alpha\), the chosen significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Shifted Exponential Distribution
In probability theory, the shifted exponential distribution is a modification of the standard exponential distribution. The probability density function (pdf) for a shifted exponential distribution is expressed as: \(f(x; \theta) = e^{-(x-\theta)}\) for \(x > \theta\), and \(0\) otherwise. This formula represents a standard exponential distribution with a shift of the origin by a parameter \(\theta\).
This shift moves the starting point of the distribution on the x-axis from zero to \(\theta\).
  • The parameter \(\theta\) signifies the location shift, indicating where the exponential decrease begins.
  • When \(\theta = 0\), the shifted exponential distribution reduces to a standard exponential distribution.
Understanding this concept is essential, as it provides the basis for assessing how the likelihood of data points changes as \(\theta\) shifts right to left along the x-axis.
Order Statistics
Order statistics are statistics that result from organizing a sample's data in increasing or decreasing order and analyzing specific data points or ranges within this ordered sequence. In the context of the shifted exponential distribution, we often focus on the smallest order statistic, denoted as \(Y_1\).
In statistical testing involving these distributions, the smallest order statistic can be particularly informative:
  • \(Y_1\) represents the minimum value observed in your data set, which is often used to test whether a shift in the distribution parameter \(\theta\) has occurred.
  • Key intuition lies in its sensitivity to shifts in the distribution, as it is directly related to the location parameter \(\theta\).
Order statistics thus provide a useful tool in understanding the behavior of sample data, particularly when making decisions based on distributions like the shifted exponential.
Hypothesis Testing
Hypothesis testing is a statistical method used to make inferences or decisions about population parameters. In the context of this problem, hypothesis testing involves comparing two competing hypotheses about the parameter \(\theta\) of a shifted exponential distribution:
  • The null hypothesis \(H_0: \theta \leq 1\) claims the parameter \(\theta\) is less than or equal to 1.
  • The alternative hypothesis \(H_a: \theta > 1\) suggests the parameter \(\theta\) is greater than 1.

In the process of testing these hypotheses, we employ a Likelihood Ratio Test (LRT). The LRT is an efficient tool for comparing the goodness of fit of two statistical models by using a ratio of their likelihood functions. In this context, the task is to determine a criterion (based on \(Y_1\)) under which \(H_0\) is rejected in favor of \(H_a\). The decision involves comparing the smallest order statistic \(y_1\) to a calculated critical value, thus helping to determine the most likely scenario.
Likelihood Function
The likelihood function is a fundamental concept in statistical inference, expressing the probability of observed data as a function of the parameters of some model. For the shifted exponential distribution, given a sample \(x_1, x_2, \ldots, x_n\), the likelihood function is given by:\[ L(\theta; x_1, x_2, \ldots, x_n) = e^{-(\sum_{i=1}^{n} x_i - n\theta)}. \]This equation is determined by the product of the probability densities for each data point, assuming independence among observations.

Understanding the likelihood function:
  • It allows us to identify different parameter values' relative ability to explain the given data.
  • In the likelihood ratio test, it is used to compare \(H_0\) and \(H_a\) by analyzing the ratio of likelihoods evaluated at specific parameters.
  • By evaluating this function for varying \(\theta\) values, we can decide which hypothesis is more plausible based on the observed data.
The result is a powerful approach for parameter estimation and hypothesis testing within statistical genetics, psychometrics, and many social sciences applications.

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Most popular questions from this chapter

For a random sample of \(n\) individuals taking a licensing exam, let \(X_{i}=1\) if the \(i\) th individual in the sample passes the exam and \(X_{i}=0\) otherwise \((i=1, \ldots, n)\). a. With \(p\) denoting the proportion of all examtakers who pass, show that the most powerful test of \(H_{0}: p=.5\) versus \(H_{\mathrm{a}}: p=.75\) rejects \(H_{0}\) when \(\Sigma x_{i} \geq c\). b. If \(n=20\) and you want \(\alpha \leq .05\) for the test of (a), would you reject \(H_{0}\) if 15 of the 20 individuals in the sample pass the exam? c. What is the power of the test you used in (b) when \(p=.75[\) i.e., what is \(\pi(.75)]\) ? d. Is the test derived in (a) UMP for testing the hypotheses \(H_{0}: p=.5\) versus \(H_{\mathrm{a}}: p>.5\) ? Explain your reasoning. e. Graph the power function \(\pi(p)\) of the test for the hypotheses of (d) when \(n=20\) and \(\alpha \leq .05\). f. Return to the scenario of (a), and suppose the test is based on a sample size of 50 . If the probability of a type II error is approximately \(.025\), what is the approximate significance level of the test (use a normal approximation)?

A university library ordinarily has a complete shelf inventory done once every year. Because of new shelving rules instituted the previous year, the head librarian believes it may be possible to save money by postponing the inventory. The librarian decides to select at random 1000 books from the library's collection and have them searched in a preliminary manner. If evidence indicates strongly that the true proportion of misshelved or unlocatable books is \(<.02\), then the inventory will be postponed. a. Among the 1000 books searched, 15 were misshelved or unlocatable. Test the relevant hypotheses and advise the librarian what to do (use \(\alpha=.05\) ). b. If the true proportion of misshelved and lost books is actually \(.01\), what is the probability that the inventory will be (unnecessarily) taken? c. If the true proportion is \(.05\), what is the probability that the inventory will be postponed?

Because of variability in the manufacturing process, the actual yielding point of a sample of mild steel subjected to increasing stress will usually differ from the theoretical yielding point. Let \(p\) denote the true proportion of samples that yield before their theoretical yielding point. If on the basis of a sample it can be concluded that more than \(20 \%\) of all specimens yield before the theoretical point, the production process will have to be modified. a. If 15 of 60 specimens yield before the theoretical point, what is the \(P\)-value when the appropriate test is used, and what would you advise the company to do? b. If the true percentage of "early yields" is actually \(50 \%\) (so that the theoretical point is the median of the yield distribution) and a level \(.01\) test is used, what is the probability that the company concludes a modification of the process is necessary?

A pen has been designed so that true average writing lifetime under controlled conditions (involving the use of a writing machine) is at least \(10 \mathrm{~h}\). A random sample of 18 pens is selected, the writing lifetime of each is determined, and a normal probability plot of the resulting data supports the use of a one-sample \(t\) test. a. What hypotheses should be tested if the investigators believe a priori that the design specification has been satisfied? b. What conclusion is appropriate if the hypotheses of part (a) are tested, \(t=-2.3\), and \(\alpha=.05 ?\) c. What conclusion is appropriate if the hypotheses of part (a) are tested, \(t=-1.8\), and \(\alpha=.01 ?\) d. What should be concluded if the hypotheses of part (a) are tested and \(t=-3.6\) ?

A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a specified number of times, and determines that 14 of the plates have blistered. a. Does this provide compelling evidence for concluding that more than \(10 \%\) of all plates blister under such circumstances? State and test the appropriate hypotheses using a significance level of .05. In reaching your conclusion, what type of error might you have committed? b. If it is really the case that \(15 \%\) of all plates blister under these circumstances and a sample size of 100 is used, how likely is it that the null hypothesis of part (a) will not be rejected by the level 05 test? Answer this question for a sample size of 200 . c. How many plates would have to be tested to have \(\beta(.15)=.10\) for the test of part (a)?

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