/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Let \(X\) and \(Y\) be the times... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(X\) and \(Y\) be the times for a randomly selected individual to complete two different tasks, and assume that \((X, Y)\) has a bivariate normal distribution with \(\mu_{X}=100, \sigma_{X}=50, \mu_{Y}=25, \sigma_{Y}=5, \rho=.5\). From statistical software we obtain \(P(X<100\), \(Y<25)=.3333, P(X<50, Y<20)=.0625\), \(P(X<50, Y<25)=.1274\), and \(P(X<100, Y<\) \(20)=.1274 .\) (a) Determine \(P(50

Short Answer

Expert verified
(a) 0.141 with \(\rho=0.5\); (b) 0.0961 with \(\rho=0\). Positive correlation increases intersecting probability.

Step by step solution

01

Understand Given Probabilities

List the probabilities provided: \(P(X<100, Y<25)=0.3333\), \(P(X<50, Y<20)=0.0625\), \(P(X<50, Y<25)=0.1274\), and \(P(X<100, Y<20)=0.1274\). These probabilities are cumulative values for specific conditions.
02

Use Inclusion-Exclusion Principle

To find \(P(50<X<100,20<Y<25)\), we apply the inclusion-exclusion principle: \(P(A\cap B) = P(A) + P(B) - P(A\cup B)\). Define \(A\) as \((X<100, Y<25)\) and \(B\) as \((X<50, Y<20)\). Substitute the probabilities as: \(P(X<100, Y<25) - P(X<100, Y<20) - P(X<50, Y<25) + P(X<50, Y<20)\).
03

Calculate the Initial Probability Value

Substitute the given probabilities into the inclusion-exclusion formula: \(0.3333 - 0.1274 - 0.1274 + 0.0625 = 0.141\). This is the value of \(P(50 < X < 100, 20 < Y < 25)\) with \(\rho = 0.5\).
04

Recalculate with \(\rho = 0\)

When \(\rho = 0\), \(X\) and \(Y\) are independent. You must calculate \(P(50 < X < 100)\) and \(P(20 < Y < 25)\) separately, using the previously known cumulative probabilities: \(P(50 < X < 100)\) can be calculated from \(P(X<100)=0.5\) and \(P(X<50)=0.0625+0.1274=0.19\); \(P(20 < Y < 25)\) can be calculated from \(P(Y<25)=0.5\) and \(P(Y<20)=0.0625+0.1274\). Multiply the two to give: \(0.31\times0.31=0.0961\).
05

Conclusion and Intuition

The value of \(P(50 < X < 100, 20 < Y < 25)\) is larger when \(\rho = 0.5\) than when \(\rho = 0\). Intuitively, positive correlation increases the likelihood that both variables exceed their means concurrently, hence increasing the probability of their intersecting values being in the given range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculations involve determining the likelihood of a particular outcome or event.
In the context of a bivariate normal distribution, this means calculating the probability that two random variables, say, X and Y, each fall within a specific range.
This can be accomplished using the cumulative distribution function (CDF) values derived from statistical software. Consider probabilities such as
  • \(P(X < 100, Y < 25) = 0.3333\)
  • \(P(X < 100, Y < 20) = 0.1274\)
These are CDF values indicating the probability that the values lie below the specified limits.
A firm understanding of these cumulative probabilities is essential for performing calculations involving more complex ranges.
Inclusion-Exclusion Principle
The Inclusion-Exclusion Principle is a key method used to calculate probabilities of overlapping events.
This principle can be used to find the probability that two particular conditions both occur.
In mathematical terms, it is expressed as:\[ P(A \cap B) = P(A) + P(B) - P(A \cup B) \]

Application in Bivariate Analysis

In this exercise, let A be the condition \((X < 100, Y < 25)\) and B be \((X < 50, Y < 20)\). By substituting the provided probabilities, we have:
  • \(P(A) = 0.3333\)
  • \(P(B) = 0.0625\)
  • \(P(A \cap B) = 0.1274 + 0.0625\)
The inclusion-exclusion principle helps to correctly account for the overlapping regions of these conditions, preventing double counting and ensuring accurate probability outcomes.
Correlation and Independence
Correlation measures the degree of relationship between two variables.
In the context of this problem, we have \(\rho = 0.5\) (moderate positive correlation), which suggests some degree of relationship between X and Y. When \(\rho = 0.5\), the probability of \((50 < X < 100, 20 < Y < 25)\) is calculated using the values derived under the provided correlation.

When Correlation is Zero

If \(\rho = 0\), it indicates independence between X and Y.
Independence simplifies calculation because the probabilities of X and Y can be treated separately.
The joint probability is the product of individual probabilities, which is \[ P(50 < X < 100 \text{ and } 20 < Y < 25) = P(50 < X < 100) \times P(20 < Y < 25) \]This highlights how independence or correlation impacts probability calculations, emphasizing correlation's influence on joint outcomes.
Bivariate Data Analysis
Bivariate data analysis is the exploration and examination of relationships between two variables, often using statistical methods.
For bivariate normal distributions like \((X, Y)\), we assess how two variables interact and correlate. This is vital in understanding behaviors where two dimensions influence outcomes.

Tools and Interpretation

In these analyses, correlation coefficients (\(\rho\)) play a crucial role. They provide insights into whether changes in one variable are associated with changes in another. Moreover, the graphical visualization of bivariate data and the computation of joint probabilities allows us to fully understand complex interactions.When analyzing bivariate data, beware of assuming causation solely based on correlation, as other unobserved factors might influence the relationship between variables.
This comprehensive understanding guides accurate predictions and informed decisions.

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Conjecture the form of the joint pdf of three order statistics \(Y_{i}, Y_{j}, Y_{k}\) in a random sample of size \(n\).

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