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Use the proposition on the expected product to show that when \(X\) and \(Y\) are independent, \(\operatorname{Cov}(X, Y)=\operatorname{Corr}(X, Y)=0\)

Short Answer

Expert verified
If \(X\) and \(Y\) are independent, both \(\operatorname{Cov}(X, Y)\) and \(\operatorname{Corr}(X, Y)\) are zero.

Step by step solution

01

Understand the Definitions

Before tackling the problem, recall the definitions of covariance and correlation. The covariance of two random variables, \(X\) and \(Y\), is defined as \( \text{Cov}(X, Y) = E((X - E(X))(Y - E(Y))) \). Correlation is defined as \( \text{Corr}(X, Y) = \frac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} \), where \( \sigma_X \) and \( \sigma_Y \) are the standard deviations of \(X\) and \(Y\), respectively.
02

Apply the Independence Property

Recall that if \(X\) and \(Y\) are independent random variables, then the expected value of the product is the product of expected values: \( E(XY) = E(X)E(Y) \). This is a key property that we will use in our calculations.
03

Calculate Covariance

Using the property from Step 2, covariance can be rewritten: \[ \text{Cov}(X, Y) = E(XY) - E(X)E(Y) \]. Since \(E(XY) = E(X)E(Y)\) when \(X\) and \(Y\) are independent, it follows that: \[ \text{Cov}(X, Y) = E(X)E(Y) - E(X)E(Y) = 0. \]
04

Calculate Correlation

Substituting into the correlation formula, we have: \[ \text{Corr}(X, Y) = \frac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} = \frac{0}{\sigma_X \sigma_Y} = 0. \] Since the covariance is zero from Step 3, the correlation is also zero, provided \( \sigma_X \sigma_Y eq 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation
Correlation helps us understand the strength and direction of a linear relationship between two random variables. It standardizes the covariance, making it easier to interpret. If two random variables, say \( X \) and \( Y \), are being analyzed for correlation, you are essentially examining how much they change together. The correlation is expressed as:
\[ \text{Corr}(X, Y) = \frac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} \]
Here, \( \sigma_X \) and \( \sigma_Y \) are the standard deviations of \( X \) and \( Y \), respectively. Values of correlation range from -1 to 1. A correlation of 1 means a perfect positive relationship, -1 means a perfect negative relationship, and 0 indicates no linear relationship.
  • Positive Correlation: As one variable increases, the other one tends to increase as well.
  • Negative Correlation: An increase in one variable tends to correspond with a decrease in the other.
  • No Correlation: No discernible pattern in how changes in one variable affect changes in the other.
Independence in Probability
Independence in probability speaks to the relationship between two random variables such that knowing the outcome of one does not give any information about the outcome of the other. Two random variables \( X \) and \( Y \) are independent if and only if the joint probability of their outcomes is the product of their individual probabilities.
Formally:
\[ P(X = x, Y = y) = P(X = x) \cdot P(Y = y) \]

This property is crucial when dealing with the calculation of expected values and covariance. Particularly, when \( X \) and \( Y \) are independent, it means:
  • Expected Value of Product: \( E(XY) = E(X)E(Y) \)
  • Covariance: \( \text{Cov}(X, Y) = 0 \), since \( E(XY) - E(X)E(Y) = 0 \)
These simplifications often make calculations much easier.
Expected Value
Expected value gives us an idea of what to anticipate in the long run for a random variable, essentially representing its mean value. When thinking about the expected value, it is useful to picture it as a weighted average of all possible values of the random variable, where each possible value’s contribution is weighed by the likelihood of that value occurring. Mathematically, for a discrete random variable \( X \), its expected value is:
\[ E(X) = \sum_{i} x_i P(X = x_i) \]
In the case of continuous variables, it switches to an integral:
\[ E(X) = \int_{-\infty}^{\infty} x f(x) \, dx \]
where \( f(x) \) is the probability density function.

For two random variables \( X \) and \( Y \), particularly if they are independent, the expected value of their product simplifies to:
\[ E(XY) = E(X)E(Y) \]
This simplification is incredibly useful in determining covariance and in analyzing the relationship between the two variables.
Random Variables
Random variables are fundamental to probability theory and statistics, representing quantities whose outcomes are determined by chance. There are two main types:
  • Discrete Random Variables: These can take on a countable number of distinct values. Examples include dice rolls or the number of heads in a series of coin flips.
    Discrete random variables have a probability mass function (PMF) that lists outcomes and the probabilities they occur.
  • Continuous Random Variables: These can take an infinite number of values within a given range. For example, the exact time it takes to run a race or the height of students in a classroom.
    Continuous random variables are described by a probability density function (PDF).
Random variables are the building blocks in defining and understanding concepts such as expected value, variance, and covariance. Within exercises, they help depict real-world phenomena statistically, enabling a deeper analysis through mathematical properties.

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Most popular questions from this chapter

Let \(X_{1}\) and \(X_{2}\) be quantitative and verbal scores on one aptitude exam, and let \(Y_{1}\) and \(Y_{2}\) be corresponding scores on another exam. If \(\operatorname{Cov}\left(X_{1}, Y_{1}\right)=5, \operatorname{Cov}\left(X_{1}, Y_{2}\right)=1, \operatorname{Cov}\left(X_{2}, Y_{1}\right)=2\), and \(\operatorname{Cov}\left(X_{2}, Y_{2}\right)=8\), what is the covariance between the two total scores \(X_{1}+X_{2}\) and \(Y_{1}+Y_{2}\) ?

This week the number \(X\) of claims coming into an insurance office is Poisson with mean 100 . The probability that any particular claim relates to automobile insurance is \(.6\), independent of any other claim. If \(Y\) is the number of automobile claims, then \(Y\) is binomial with \(X\) trials, each with "success" probability .6. a. Determine \(E(Y \mid X=x)\) and \(V(Y \mid X=x)\). b. Use part (a) to find \(E(Y)\). c. Use part (a) to find \(V(Y)\).

Suppose that \(X\) and \(Y\) are independent rv's with moment generating functions \(M_{X}(t)\) and \(M_{Y}(t)\), respectively. If \(Z=X+Y\), show that \(M_{Z}(t)=M_{X}(t) M_{Y}(t)\). [Hint: Use the proposition on the expected value of a product.]

A market has both an express checkout line and a superexpress checkout line. Let \(X_{1}\) denote the number of customers in line at the express checkout at a particular time of day, and let \(X_{2}\) denote the number of customers in line at the superexpress checkout at the same time. Suppose the joint pmf of \(X_{1}\) and \(X_{2}\) is as given in the accompanying table. $$ \begin{array}{cc|cccc} & & & &{x_{2}} & \\ & & 0 & 1 & 2 & 3 \\ \hline & 0 & .08 & .07 & .04 & .00 \\ & 1 & .06 & .15 & .05 & .04 \\ x_{1} & 2 & .05 & .04 & .10 & .06 \\ & 3 & .00 & .03 & .04 & .07 \\ & 4 & .00 & .01 & .05 & .06 \end{array} $$ a. What is \(P\left(X_{1}=1, X_{2}=1\right)\), that is, the probability that there is exactly one customer in each line? b. What is \(P\left(X_{1}=X_{2}\right)\), that is, the probability that the numbers of customers in the two lines are identical? c. Let \(A\) denote the event that there are at least two more customers in one line than in the other line. Express \(A\) in terms of \(X_{1}\) and \(X_{2}\), and calculate the probability of this event. d. What is the probability that the total number of customers in the two lines is exactly four? At least four? e. Determine the marginal pmf of \(X_{1}\), and then calculate the expected number of customers in line at the express checkout. f. Determine the marginal pmf of \(X_{2}\). g. By inspection of the probabilities \(P\left(X_{1}=4\right)\), \(P\left(X_{2}=0\right)\), and \(P\left(X_{1}=4, X_{2}=0\right)\), are \(X_{1}\) and \(X_{2}\) independent random variables? Explain.

A store is expecting \(n\) deliveries between the hours of noon and 1 p.m. Suppose the arrival time of each delivery truck is uniformly distributed on this one-hour interval and that the times are independent of each other. What are the expected values of the ordered arrival times?

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