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A trial has just resulted in a hung jury because eight members of the jury were in favor of a guilty verdict and the other four were for acquittal. If the jurors leave the jury room in random onder and each of the first four leaving the room is accosted by a reporter in quest of an interview, what is the pmf of \(X=\) the number of jurors favoring acquittal among those interviewed? How many of those favoring acquittal do you expect to be interviewed?

Short Answer

Expert verified
The pmf is determined by the hypergeometric distribution; expected value is 1.33 jurors.

Step by step solution

01

Define the Problem

Identify the random variable \(X\). The problem asks for the probability mass function (pmf) of \(X\), which represents the number of jurors favoring acquittal among the first four jurors interviewed. Jurors in favor of acquittal are 4 out of a total of 12.
02

Determine Possible Outcomes

Determine all possible values of \(X\). Each selected juror can either be one in favor of acquittal or guilty. Thus, \(X\) can take values 0, 1, 2, 3, or 4, representing the number of acquittal-voting jurors among the first four interviewed.
03

Calculate the Total Number of Ways to Choose Jurors

Calculate the total number of ways to choose 4 jurors out of 12. This is given by \(\binom{12}{4}=495\).
04

Calculate Probability for Each Outcome of X

For each possible value of \(X=x\), calculate the probability that exactly \(x\) jurors favor acquittal are among the first four interviewed. Use the hypergeometric distribution:- \(P(X=0) = \frac{\binom{4}{0} \binom{8}{4}}{\binom{12}{4}} = \frac{1 \times 70}{495} \approx 0.1414\)- \(P(X=1) = \frac{\binom{4}{1} \binom{8}{3}}{\binom{12}{4}} = \frac{4 \times 56}{495} \approx 0.4545\)- \(P(X=2) = \frac{\binom{4}{2} \binom{8}{2}}{\binom{12}{4}} = \frac{6 \times 28}{495} \approx 0.3404\)- \(P(X=3) = \frac{\binom{4}{3} \binom{8}{1}}{\binom{12}{4}} = \frac{4 \times 8}{495} \approx 0.0646\)- \(P(X=4) = \frac{\binom{4}{4} \binom{8}{0}}{\binom{12}{4}} = \frac{1 \times 1}{495} \approx 0.002\)
05

Verify the PMF

Ensure the probabilities sum to 1. Calculate: \(P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) = 0.1414 + 0.4545 + 0.3404 + 0.0646 + 0.002 = 1\). This confirms our pmf is correct.
06

Calculate the Expected Value of X

The expected value \(E(X)\) is found by calculating \(E(X) = \sum x P(X=x)\):\(E(X) = 0 \cdot 0.1414 + 1 \cdot 0.4545 + 2 \cdot 0.3404 + 3 \cdot 0.0646 + 4 \cdot 0.002 = 1.33\).
07

Interpret the Expected Value

On average, you can expect approximately 1.33 jurors favoring acquittal to be interviewed if the first four jurors leave at random.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypergeometric Distribution
The hypergeometric distribution is an important concept in probability and statistics, especially in scenarios where the sampling is done without replacement. Unlike the binomial distribution, which assumes that selections are independent, the hypergeometric distribution considers the impact of one selection on another, making it very useful in real-world situations where you can't put items back.

In the provided problem regarding jury members, we are tasked with finding the probability of selecting a certain number of jurors favoring acquittal from a specific pool. Here, the hypergeometric distribution is used because the jurors are selected without replacement.

To apply it, you need to know:
  • The total population size (N), which is 12 jurors in this case.
  • The number of success states in the population (K), which refers to 4 jurors in favor of acquittal.
  • Size of the sample taken (n), which is 4 jurors being interviewed.
  • The number of observed success states in the sample (x), which can range from 0 to 4 in this problem.
The probability mass function for a hypergeometric distribution is given by:\[ P(X=x) = \frac{\binom{K}{x} \binom{N-K}{n-x}}{\binom{N}{n}} \]Each term in this formula represents the different ways to choose jurors who favor acquittal, those who don’t, and the total combinations.
Expected Value
The expected value is a key concept in statistics that offers a measure of the center or average of a random variable. In simple terms, it provides the average outcome you would expect if you repeated an experiment a large number of times.

For the case of the jury selection problem, the expected value gives us an idea of how many jurors favoring acquittal we can expect to be interviewed out of the first four. This is calculated using the probability mass function that we derived using the hypergeometric distribution.

Here's the formula for expected value in our problem:\[ E(X) = \sum_{x=0}^{4} x \cdot P(X = x) \]This means we multiply each possible number of jury members favoring acquittal and interviewed by its probability, and sum these products. For the jury scenario, the expected value was calculated to be approximately 1.33.

Thus, on average, we expect around 1.33 jurors favoring acquittal to be interviewed, if the jurors exit in a random order.
Random Variable
A random variable is a fundamental concept in probability and statistics. It is essentially a variable that can take on multiple values, each with an associated probability. In our jury scenario, we're concerned with the random variable \(X\).

What makes \(X\) a random variable here? It represents the number of jurors favoring acquittal among the first four interviewed. Since the order in which jurors leave is random, \(X\) is an unpredictable quantity until the jurors are actually interviewed.

Random variables can be either discrete or continuous. In this case, \(X\) is discrete because it can only take on specific integer values: 0, 1, 2, 3, or 4, not any value in-between. Each possible value of \(X\) corresponds to a probability, which we determined using the hypergeometric distribution.

Understanding \(X\) as a random variable allows us to apply different probabilistic methods, like finding the probability mass function and expected value, helping us make informed predictions.

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Most popular questions from this chapter

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