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Suppose that vehicles taking a particular freeway exit can turn right \((R)\), turn left \((L)\), or go straight \((S)\). Consider observing the direction for each of three successive vehicles. a. List all outcomes in the event \(A\) that all three vehicles go in the same direction. b. List all outcomes in the event \(B\) that all three vehicles take different directions. c. List all outcomes in the event \(C\) that exactly two of the three vehicles turn right. d. List all outcomes in the event \(D\) that exactly two vehicles go in the same direction. e. List outcomes in \(D^{\prime}, C \cup D\), and \(C \cap D\).

Short Answer

Expert verified
a) RRR, LLL, SSS b) RLS, RSL, LRS, LSR, SLR, SRL c) RRL, RRS, LRR, SRR d) RRL, RRS, RLR, RSR, LRR, LLR, LLS, LLL, LSR, SSR, SSL, SSS, SLR e) D': RLS, RSL, LRS, LSR, SLR, SRL; C∪D: RRL, RRS, LRR, SRR, RLR, LLR, LLS, LLL, LSR, SSR, SSL, SSS, SLR; C∩D: RRL, RRS, LRR, SRR.

Step by step solution

01

Identify All Possible Outcomes

First, identify all possible outcomes for the directions of three vehicles. Each vehicle can take one of three directions: Right (R), Left (L), or Straight (S). Consequently, the number of possible outcomes is \(3 imes 3 imes 3 = 27\). These outcomes are: RRR, RRL, RRS, RLR, RLL, RLS, RSR, RSL, RSS, LRR, LRL, LRS, LLR, LLL, LLS, LSR, LSL, LSS, SRR, SRL, SRS, SLR, SLL, SLS, SSR, SSL, SSS.
02

List Outcomes in Event A (Same Direction)

Event A occurs when all three vehicles go in the same direction. Therefore, the possible outcomes are: RRR, LLL, SSS.
03

List Outcomes in Event B (All Different Directions)

Event B occurs when all three vehicles take different directions. With three directions available (R, L, S), there are 6 permutations for choosing different directions for all cars: RLS, RSL, LRS, LSR, SLR, SRL.
04

List Outcomes in Event C (Exactly Two Right)

Event C occurs when exactly two vehicles turn right (R), and one vehicle takes a different direction (either L or S). The possible outcomes are: RRL, RRS, LRR, SRR.
05

List Outcomes in Event D (Exactly Two Same Direction)

Event D includes those outcomes where exactly two vehicles go the same direction and the third vehicle differently. For each direction, we find such outcomes: RRL, RRS, RLR, RSR, LRR, LLR, LLS, LLL, LSR, SSR, SSL, SSS, SLR.
06

Find D Complement, D'

The complement of event D, \(D'\), includes outcomes where no two vehicles go in the same direction, i.e., all different, or all the same. The outcomes are: RLS, RSL, LRS, LSR, SLR, SRL (from Event B).
07

Find Union of C and D, C \cup D

To find \(C \cup D\), combine the outcomes of events C and D, ensuring no duplicates. Outcomes: RRL, RRS, LRR, SRR, RLR, LLR, LLS, LLL, LSR, SSR, SSL, SSS, SLR.
08

Find Intersection of C and D, C \cap D

The intersection \(C \cap D\) includes outcomes common to both C and D, i.e., where exactly two vehicles are turning right. Outcomes: RRL, RRS, LRR, SRR.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is the field of mathematics focused on counting, arrangements, and combinations. It helps us calculate the number of different ways things can happen when dealing with discrete structures. In this problem, we use combinatorics to figure out how vehicles can turn in different directions at an intersection.
For example, if each vehicle can make one of three choices—Right (R), Left (L), or Straight (S)—then for three vehicles, we calculate possible outcomes as \(3 \times 3 \times 3 = 27\). This multiplication represents the product rule, where the number of outcomes for each vehicle is multiplied together. Combinatorics becomes essential when solving for various events and exploring all possible outcomes in situation-based problems like these.
Outcome Spaces
An outcome space is the entirety of possible results in a probabilistic event. This term is crucial in probability because it defines the universe from which events are considered. In the freeway exit problem, the outcome space consists of every combination of turns three vehicles can make.
The space includes sequences like "RRR" (all turn right) or "RLS" (each vehicle chooses a different direction). These sequences highlight that each vehicle's choice influences the total outcome space of 27 distinct combinations—each a string of three letters representing their respective turns. Understanding outcome spaces gives us the groundwork for further decomposition into events and more intricate probability calculations.
Events and Sample Spaces
Events are specific sets of outcomes that we are interested in. When we talk about sample spaces, we mean the complete set of all possible outcomes.
  • Event A (All Same Direction): This event is concerned with outcomes like "RRR," "LLL," and "SSS," where all three vehicles turn in the same direction.
  • Event B (Different Directions): Here, we have outcomes such as "RLS," "RSL," where each vehicle chooses a distinct direction.
  • Event C (Exactly Two Right Turns): In this case, outcomes are "RRL," "RRS," showing two right turns.
  • Event D (Exactly Two Same Direction): This keeps track of outcomes like "RRL," "RRS," where exactly two directions match.
Understanding how to identify and count these events relative to the sample space is critical, especially when refining and analyzing the probability of more complex questions in the exercises.
Set Operations
Set operations help us analyze and simplify probability problems by combining different events. Here, we use basic set operations like union, intersection, and complement to evaluate complex scenarios.
  • Union (\(C \cup D\)): This operation combines outcomes from Events C and D, presenting all outcomes that belong to either one or both events. Here, it results in unique outcomes like "RRL," "LLR," "SRR."
  • Intersection (\(C \cap D\)): The intersection finds common outcomes between Events C and D. For this problem, include outcomes such as "RRL," "RRS," where the scenarios overlap exactly.
  • Complement (\(D'\)): This is the set of outcomes not included in Event D, showing sequences where not exactly two turn the same way.
These operations are vital because they allow us to build more complex probability models by understanding how different events interact and overlap, providing a basis for complex decision-making processes.

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