/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 A particular state has elected b... [FREE SOLUTION] | 91Ó°ÊÓ

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A particular state has elected both a govemor and a senator. Let \(A\) be the event that a randomly selected voter has a favorable view of a certain party's senatorial candidate, and let \(B\) be the corresponding event for that party's gubernatorial candidate. Suppose that \(P\left(A^{\prime}\right)=.44, P\left(B^{\prime}\right)=\) \(.57\), and \(P(A \cup B)=.68\) (these figures are suggested by the 2010 general election in California). a. What is the probability that a randomly selected voter has a favorable view of both candidates? b. What is the probability that a randomly selected voter has a favorable view of exactly one of these candidates? c. What is the probability that a randomly selected voter has an unfavorable view of at least one of these candidates.

Short Answer

Expert verified
a. 0.31 b. 0.37 c. 0.69

Step by step solution

01

Convert Complements to Probabilities

First, we need to find the probabilities of events \(A\) and \(B\) using their complements. Since \(P(A') = 0.44\), it follows that \(P(A) = 1 - P(A') = 1 - 0.44 = 0.56\). Similarly, \(P(B') = 0.57\) implies \(P(B) = 1 - P(B') = 1 - 0.57 = 0.43\).
02

Use the Union Formula for Probability

We are given \(P(A \cup B) = 0.68\) and want \(P(A \cap B)\). The formula is \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). Substitute the known values: \[0.68 = 0.56 + 0.43 - P(A \cap B)\].Simplify: \[0.68 = 0.99 - P(A \cap B)\].Thus, \(P(A \cap B) = 0.99 - 0.68 = 0.31\).
03

Find Probability of Exactly One Candidate

We seek \(P(A \Delta B)\), the probability of a favorable view of exactly one candidate. This is given by \(P(A \Delta B) = P(A \cup B) - P(A \cap B)\). We calculated \(P(A \cap B) = 0.31\), so:\[P(A \Delta B) = 0.68 - 0.31 = 0.37\].
04

Probability of Unfavorable View for At Least One Candidate

An unfavorable view for at least one candidate is the complement of a favorable view for both: \(P(A' \cup B') = 1 - P(A \cap B)\).Since \(P(A \cap B) = 0.31\), \(P(A' \cup B') = 1 - 0.31 = 0.69\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Events
When we discuss the union of events in probability, we are examining the probability that either one event or both events happen. Here, the union is represented as \(A \cup B\), where \(A\) and \(B\) are two distinct events. The union considers any scenario where either event occurs, including the possibility of both events happening at the same time.
For this concept, the formula used to calculate the probability of the union of two events is:
  • \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
The above formula sums up the probabilities of each event occurring but adjusts for the cases where both events happen, which are counted twice if not subtracted. In the original exercise, we used this formula to find the probability of both voters having a favorable view of candidates \(A\) and \(B\), given their respective complements and the union \(P(A \cup B) = 0.68\).
Understanding this operation is key in dissecting numerous probability scenarios, particularly when dealing with multiple events and their overlapping outcomes.
Intersection of Events
The intersection of events in probability theory deals with the likelihood of both events occurring simultaneously. For events \(A\) and \(B\), their intersection is denoted as \(A \cap B\). This essentially answers the question: "What is the probability that both events happen at the same time?"
In probability notation, the intersection can be found through the expression:
  • \(P(A \cap B) = P(A) + P(B) - P(A \cup B)\)
This formula results directly from rearranging the union formula for probability. In practice, it helps identify the overlap in outcomes between events, which is particularly useful in problems involving multiple criteria or conditions.
In our exercise, calculating \(P(A \cap B)\) involved subtracting the union from the sum of \(P(A)\) and \(P(B)\). This step is fundamental because it gives us the very specific joint probability that both \(A\) and \(B\) independently happen together. Recognizing and calculating intersections is crucial for complex problem-solving within probability frameworks.
Complementary Probability
Complementary probability refers to the concept of an event and its complement, usually symbolized as \(A\) and \(A'\). The complement of an event represents everything that is not part of the initial event. In any probability scenario, the total probability must equal 1, so \(P(A) + P(A') = 1\).
This principle allows us to easily determine the probability of an event if we know its complement. It is a fundamental mechanism in probability theory often used to simplify problems.
  • \(P(A) = 1 - P(A')\)
In the exercise, we were initially given the complements \(P(A')\) and \(P(B')\). We converted these to their respective probabilities for \(A\) and \(B\) by using the complementary probability formula. This approach helped us move forward with calculations such as determining union and intersection probabilities efficiently.
Appreciating the role of complementary events can help in solving various probability-related tasks, often providing a quicker route to the solution by making effective use of what is known about the complements.
Set Operations in Probability
Set operations in probability resemble mathematical set operations, focusing on union, intersection, and complements to solve probability problems. Probability theory often uses these set-like operations to determine the relationships and outcomes among different events. Understanding these operations enables solving probability problems more intuitively and efficiently.
The main set operations used in probability include:
  • Union (\(A \cup B\)): Describes the scenario where at least one of the events occurs.
  • Intersection (\(A \cap B\)): Denotes both events occurring simultaneously.
  • Complementary (\(A'\)): Refers to the probability of the event not occurring.
The overlap among these operations, paired with probability rules, forms the backbone of both theoretical and practical applications in probability settings. In our example, we used these operations to deduce several probabilities, like the probability of a favorable or unfavorable view on political candidates within a voter population. Such set operations simplify the observation and interpretation of probabilities, especially when handling multiple events or complex conditions.
Mastering these operations can greatly enhance understanding and manipulation of probabilities, offering a powerful toolkit for analyzing uncertain scenarios.

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Most popular questions from this chapter

a. Beethoven wrote 9 symphonies and Mozart wrote 27 piano concertos. If a university radio station announcer wishes to play first a Beethoven symphony and then a Mozart concerto, in how many ways can this be done? b. The station manager decides that on each successive night ( 7 days per week), a Beethoven symphony will be played, followed by a Mozart piano concerto, followed by a Schubert string quartet (of which there are 15). For roughly how many years could this policy be continued before exactly the same program would have to be repeated?

The probability that a grader will make a marking error on any particular question of a multiplechoice exam is .1. If there are ten questions and questions are marked independently, what is the probability that no errors are made? That at least one error is made? If there are \(n\) questions and the probability of a marking error is \(p\) rather than \(.1\), give expressions for these two probabilities.

Individual A has a circle of five close friends (B, C, D, E, and F). A has heard a certain rumor from outside the circle and has invited the five friends to a party to circulate the rumor. To begin, A selects one of the five at random and tells the rumor to the chosen individual. That individual then selects at random one of the four remaining individuals and repeats the rumor. Continuing, a new individual is selected from those not already having heard the rumor by the individual who has just heard it, until everyone has been told. a. What is the probability that the rumor is repeated in the order B, C, D, E, and F? b. What is the probability that \(F\) is the third person at the party to be told the rumor? c. What is the probability that \(\mathrm{F}\) is the last person to hear the rumor?

Three molecules of type \(A\), three of type \(B\), three of type \(C\), and three of type \(D\) are to be linked together to form a chain molecule. One such chain molecule is \(A B C D A B C D A B C D\), and another is \(B C D D A A A B D B C C\). a. How many such chain molecules are there? [Hint: If the three A's were distinguishable from one another- \(A_{1}, A_{2}, A_{3}\)-and the \(B\) 's, \(C\) 's, and \(D\) 's were also, how many molecules would there be? How is this number reduced when the subscripts are removed from the \(A\) 's?] b. Suppose a chain molecule of the type described is randomly selected. What is the probability that all three molecules of each type end up next to each other (such as in \(B B B A A A D D D C C C\) )?

The three major options on a car model are an automatic transmission \((A)\), a sunroof \((B)\), and an upgraded stereo \((C)\). If \(70 \%\) of all purchasers request \(A, 80 \%\) request \(B, 75 \%\) request \(C, 85 \%\) request \(A\) or \(B, 90 \%\) request \(A\) or \(C, 95 \%\) request \(B\) or \(C\), and \(98 \%\) request \(A\) or \(B\) or \(C\), compute the probabilities of the following events. [Hint: "A or \(B^{\prime \prime}\) is the event that at least one of the two options is requested; try drawing a Venn diagram and labeling all regions.] a. The next purchaser will request at least one of the three options. b. The next purchaser will select none of the three options. c. The next purchaser will request only an automatic transmission and neither of the other two options. d. The next purchaser will select exactly one of these three options.

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