/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 In a study to assess the effects... [FREE SOLUTION] | 91Ó°ÊÓ

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In a study to assess the effects of malaria infection on mosquito hosts ("Plasmodium cynomolgi: Effects of Malaria Infection on Laboratory Flight Performance of Anopheles stephensi Mosquitos," Exp. Parasitol., 1977: 397-404), mosquitoes were fed on either infective or noninfective rhesus monkeys. Subsequently the distance they flew during a 24 -h period was measured using a flight mill. The mosquitoes were divided into four groups of eight mosquitoes each: infective rhesus and sporozites present (IRS), infective rhesus and oocysts present (IRD), infective rhesus and no infection developed (IRN), and noninfective (C). The summary data values are \(\bar{x}_{1}=4.39(\mathrm{IRS}), \quad \bar{x}_{2}=4.52(\mathrm{IRD}), \quad \bar{x}_{3}=\) \(5.49(\mathrm{IRN}), \quad \bar{x}_{4}=6.36(\mathrm{C}), \quad \bar{x}_{. .}=5.19, \quad\) and \(\sum \sum x_{i j}^{2}=911.91\). Use the ANOVA \(F\) test at level \(.05\) to decide whether there are any differences between true average flight times for the four treatments.

Short Answer

Expert verified
There are differences between the groups' average flight times.

Step by step solution

01

State Hypotheses

In an ANOVA test, we begin by setting up the null hypothesis (\(H_0\)) that all group means are equal and the alternative hypothesis (\(H_1\)) that at least one group mean is different. - \(H_0: \mu_1 = \mu_2 = \mu_3 = \mu_4\)- \(H_1:\) At least one mean is different.
02

Calculate Group Variance (Between-Groups)

First, calculate the group mean variance (sum of squares between) using the formula: \[SS_{between} = n \sum (\bar{x}_i - \bar{x}_{. .})^2\]where \(n\) is the number of data points per group (8 in each group). Thus, \[SS_{between} = 8 \times ((4.39 - 5.19)^2 + (4.52 - 5.19)^2 + (5.49 - 5.19)^2 + (6.36 - 5.19)^2)\] \[= 8 \times (0.6400 + 0.4489 + 0.0900 + 1.3729)\] \[= 8 \times 2.5518 = 20.4144\]
03

Calculate Total Variance

Compute the total variance using the formula: \[SS_{total} = \sum\sum x_{ij}^2 - \frac{(\sum x_{..})^2}{N}\]Assuming \(\sum x_{..} = \bar{x}_{..} \times N = 5.19 \times 32 = 166.08\), the formula becomes:\[SS_{total} = 911.91 - \frac{166.08^2}{32} = 911.91 - 862.4481 = 49.4619\]
04

Calculate Error Variance (Within-Groups)

The error variance or within-groups variance is calculated by subtracting \(SS_{between}\) from \(SS_{total}\):\[SS_{within} = SS_{total} - SS_{between} = 49.4619 - 20.4144 = 29.0475\]
05

Calculate Mean Squares

Calculate the mean square for between-groups and within-groups:\[MS_{between} = \frac{SS_{between}}{k-1} = \frac{20.4144}{3} = 6.8048\]\[MS_{within} = \frac{SS_{within}}{N-k} = \frac{29.0475}{28} = 1.0370\]where \(k = 4\) (number of groups), and \(N = 32\) (total observations).
06

Calculate F-Statistic

The \(F\) statistic is calculated as:\[F = \frac{MS_{between}}{MS_{within}} = \frac{6.8048}{1.0370} \approx 6.5611\]
07

Determine Critical Value and Make Decision

For \(\alpha = 0.05\), with \(df_1 = 3\) and \(df_2 = 28\), use an \(F\)-distribution table or calculator to find the critical \(F\) value. The critical value is approximately 2.95. Since the computed \(F\) value (6.5611) is greater than the critical value (2.95), we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a key method in statistics that allows researchers to make inferences about populations based on sample data. It's like a scientific guesswork process, where we postulate two opposing hypothetical statements and use sample data to make a decision. In ANOVA tests, we begin with forming the null hypothesis, symbolized as \(H_0\). This hypothesis usually represents the idea that there are no differences among the group means in the population.
For example, in the exercise of mosquitoes' flight performance, the null hypothesis posits that all the group means are equal, i.e., \(\mu_1 = \mu_2 = \mu_3 = \mu_4\).
The alternative hypothesis, \(H_1\), suggests that at least one group differs in its mean from others. The ANOVA test helps decide whether to reject \(H_0\) based on calculated statistics such as the \(F\) value. This method is crucial when comparing more than two groups, as it prevents the increased error rate that could occur if multiple individual tests were performed instead.
Hence, it forms the backbone of experiments where we need to understand the variances between different groups or treatments.
Variance Analysis
Variance analysis is the process used to understand the variation in data by partitioning overall variability into components associated with certain sources of variation, such as treatment effects. In the context of ANOVA, variance analysis helps to understand how much of the total data variability is due to differences between group means, also called "between-group variance", and how much is due to variability within groups, named "within-group variance".
In the mosquito flight study, we compute the between-group variance \(SS_{between}\) to determine how much of the variation in flight times is due to the different mosquito treatments. It is calculated as:
  • \(SS_{between} = n \sum (\bar{x}_i - \bar{x}_{..})^2 \)
This calculation gives us an idea of the impact of each treatment compared to the grand mean of all observations. Likewise, the within-group variance \(SS_{within}\) reflects variability within each treatment group and is calculated by subtracting \(SS_{between}\) from the total variance \(SS_{total}\).
Such analysis tells us if the effect of a particular factor is significant or if differences are just random noise.
Statistical Significance
Statistical significance is a determination of whether or not an observed effect in an experimental study is caused by something other than chance. When computed statistics, like the \(F\)-value, exceed a critical value based on pre-defined significance levels (usually \(\alpha = 0.05\)), the result is deemed statistically significant. This means we have enough evidence to reject the null hypothesis and support the alternative hypothesis.
In the ANOVA test performed on mosquito data, the computed \(F\) statistic \(6.5611\) was greater than the critical value \(2.95\), which denotes statistical significance. Thus, there is a statistically significant difference in the flight performance of mosquitoes based on the different treatments.
Statistical significance does not imply practical significance, yet it helps in understanding whether an effect or result is genuine and worth further consideration or actionable in the research scope. By understanding statistical significance, researchers can assess the reliability of their findings within a scientific framework.
Experimental Study Design
Experimental study design is a careful arrangement of the different components of an experiment to ensure valid, reliable, and interpretable results. In the case of the mosquito flight study, the researchers structured the experiment with four distinct groups, each handled under different treatment conditions.
A well-thought-out study design helps to control extraneous variables and biases, focusing primarily on the variable of interest. It includes elements like randomization to assign subjects to treatments, replication to ensure findings are consistent across various samples, and controlling variables to minimize the effect of other factors.
In an experimental study design:
  • Randomized groups improve the validity of the findings.
  • Use of control groups allows for comparison against treatments.
  • Employing sufficient sample sizes strengthens the statistical power.
For the mosquitoes in this study, these factors ensure that the observed differences in flight distance are due to treatment conditions and not other miscellaneous variables. Crafting a solid experimental design is the bedrock for achieving reliable and reproducible results in scientific inquiries.

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Most popular questions from this chapter

The article "Towards Improving the Properties of Plaster Moulds and Castings" (J. Engrg. Manuf., 1991: 265-269) describes several ANOVAs carried out to study how the amount of carbon fiber and sand additions affect various characteristics of the molding process. Here we give data on casting hardness and on wet-mold strength. $$ \begin{array}{llll} \hline \begin{array}{l} \text { Sand } \\ \begin{array}{l} \text { Addition } \\ (\%) \end{array} & \begin{array}{l} \text { Carbon } \\ \text { Fiber } \\ \text { Addition } \\ (\%) \end{array} & & \begin{array}{l} \text { Casting } \\ \text { Hardness } \end{array} & \begin{array}{l} \text { Wet- } \\ \text { Mold } \\ \text { Strength } \end{array} \\ \hline 0 & 0 & 61.0 & 34.0 \\ 0 & 0 & 63.0 & 16.0 \\ 15 & 0 & 67.0 & 36.0 \\ 15 & 0 & 69.0 & 19.0 \\ 30 & 0 & 65.0 & 28.0 \\ 30 & 0 & 74.0 & 17.0 \\ 0 & .25 & 69.0 & 49.0 \\ 0 & .25 & 69.0 & 48.0 \\ 15 & .25 & 69.0 & 43.0 \\ 15 & .25 & 74.0 & 29.0 \\ 30 & .25 & 74.0 & 31.0 \\ 30 & .25 & 72.0 & 24.0 \\ 0 & .50 & 67.0 & 55.0 \\ 0 & .50 & 69.0 & 60.0 \\ 15 & .50 & 69.0 & 45.0 \\ 15 & .50 & 74.0 & 43.0 \\ 30 & .50 & 74.0 & 22.0 \\ 30 & .50 & 74.0 & 48.0 \end{array} \end{array} $$ a. An ANOVA for wet-mold strength gives SSSand \(=705\), SSFiber \(=1278\), SSE \(=843\), and SST \(=3105 .\) Test for the presence of any effects using \(\alpha=.05\). b. Carry out an ANOVA on the casting hardness observations using \(\alpha=.05\). c. Make an interaction plot with sand percentage on the horizontal axis, and discuss the results of part (b) in terms of what the plot shows.

In an experiment to compare the quality of four different brands of reel-to- reel recording tape, five \(2400-\mathrm{ft}\) reels of each brand (A-D) were selected and the number of flaws in each reel was determined. \(\begin{array}{lrrrrr}\text { A: } & 10 & 5 & 12 & 14 & 8 \\ \text { B: } & 14 & 12 & 17 & 9 & 8 \\ \text { C: } & 13 & 18 & 10 & 15 & 18 \\ \text { D: } & 17 & 16 & 12 & 22 & 14\end{array}\) It is believed that the number of flaws has approximately a Poisson distribution for each brand. Analyze the data at level \(.01\) to see whether the expected number of flaws per reel is the same for each brand.

In an experiment to see whether the amount of coverage of light-blue interior latex paint depends either on the brand of paint or on the brand of roller used, 1 gallon of each of four brands of paint was applied using each of three brands of roller, resulting in the following data (number of square feet covered). $$ \begin{array}{lc|ccc} & &{\text { Roller Brand }} \\ & & \mathbf{1} & \mathbf{2} & \mathbf{3} \\ & \mathbf{1} & 454 & 446 & 451 \\ \text { Paint } & \mathbf{2} & 446 & 444 & 447 \\ \text { Brand } & \mathbf{3} & 439 & 442 & 444 \\ & \mathbf{4} & 444 & 437 & 443 \\ \hline \end{array} $$ a. Construct the ANOVA table. [Hint: The com putations can be expedited by subtracting 400 (or any other convenient number) from each observation. This does not affect the final results.] b. State and test hypotheses appropriate for deciding whether paint brand has any effec on coverage. Use \(\alpha=.05\). c. Repeat part (b) for brand of roller. d. Use Tukey's method to identify significan differences among brands. Is there one bran that seems clearly preferable to the others? e. Check the normality and constant variance assumptions graphically.

Four plots were available for an experiment to compare clover accumulation for four different sowing rates ("Performance of Overdrilled Red Clover with Different Sowing Rates and Initial Grazing Managements," New Zeal. J. Exper. Agric., 1984: 71-81). Since the four plots had been grazed differently prior to the experiment and it was thought that this might affect clover accumulation, a randomized block experiment was used with all four sowing rates tried on a section of each plot. Use the given data to test the null hypothesis of no difference in true mean clover accumulation (kg DM/ha) for the different sowing rates. a. Test to see if the different sowing rates make a difference in true mean clover accumulation. b. Make appropriate plots to go with your analysis in (a): Make a plot like the one in Figure \(11.8\), make a normal plot of the residuals, and plot the residuals against the predicted values. Explain why, based on the plots, the assumptions do not appear to be satisfied for this data set. c. Repeat part (a) replacing the observations with their natural logarithms. d. Repeat the plots of (b) for the analysis in (c). Do the logged observations appear to satisfy the assumptions better? e. Summarize your conclusions for this experiment. Does mean clover accumulation increase with increasing sowing rate? $$ \begin{array}{lrrrr} & {\text { Sowing Rate (kg/ha) }} \\ \text { Plot } & {\mathbf{3 . 6}} & {\mathbf{6 . 6}} &{\mathbf{1 0 . 2}} & \mathbf{1 3 . 5} \\ \hline \mathbf{1} & 1155 & 2255 & 3505 & 4632 \\ \mathbf{2} & 123 & 406 & 564 & 416 \\ \mathbf{3} & 68 & 416 & 662 & 379 \\ \mathbf{4} & 62 & 75 & 362 & 564 \end{array} $$

Although tea is the world's most widely consumed beverage after water, little is known about its nutritional value. Folacin is the only B vitamin present in any significant amount in tea, and recent advances in assay methods have made accurate determination of folacin content feasible. Consider the accompanying data on folacin content for randomly selected specimens of the four leading brands of green tea. $$ \begin{array}{llllllll} \text { Brand } & & & {\text { Observations }} \\ \hline 1 & 7.9 & 6.2 & 6.6 & 8.6 & 8.9 & 10.1 & 9.6 \\ 2 & 5.7 & 7.5 & 9.8 & 6.1 & 8.4 & & \\ 3 & 6.8 & 7.5 & 5.0 & 7.4 & 5.3 & 6.1 & \\ 4 & 6.4 & 7.1 & 7.9 & 4.5 & 5.0 & 4.0 & \\ \hline \end{array} $$ (Data is based on "Folacin Content of Tea," J. Amer. Dietetic Assoc., 1983: 627-632.) Does this data suggest that true average folacin content is the same for all brands? a. Carry out a test using \(\alpha=.05\) via the \(P\)-value method. b. Assess the plausibility of any assumptions required for your analysis in part (a). c. Perform a multiple comparisons analysis to identify significant differences among brands.

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