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Give as much information as you can about the \(P\)-value of the \(F\) test in each of the following situations: a. \(v_{1}=5, v_{2}=10\), upper-tailed test, \(f=4.75\) b. \(v_{1}=5, v_{2}=10\), upper-tailed test, \(f=2.00\) c. \(v_{1}=5, v_{2}=10\), two-tailed test, \(f=5.64\) d. \(v_{1}=5, v_{2}=10\), lower-tailed test, \(f=.200\) e. \(v_{1}=35, v_{2}=20\), upper-tailed test, \(f=3.24\)

Short Answer

Expert verified
P-values for the F-test are determined by finding values in F-distribution tables or using statistical software, and they indicate the strength of evidence against a null hypothesis. Generally, small P-values suggest strong evidence against the null hypothesis.

Step by step solution

01

Understanding the F-Test Context

The F-test is used to compare two variances and its outcome is based on an F-distribution. The P-value indicates the probability of observing an F-value at least as extreme as the one given in the test. The degrees of freedom for the numerator and denominator ( v_1 and v_2 ) along with the F-value determine the P-value. We'll examine each situation based on this information.
02

Situation a: Upper-tailed Test Analysis

For v_1 = 5 and v_2 = 10 , with an upper-tailed test and f = 4.75 , find the P-value by looking up or using a calculator/computer to find the distribution with these degrees of freedom. Generally, an F-value of 4.75 with these parameters corresponds to a small P-value, indicating significant evidence against the null hypothesis.
03

Situation b: Upper-tailed Test Analysis

For v_1 = 5 and v_2 = 10 , with an upper-tailed test and f = 2.00 , look up or use a calculator/computer to find the P-value. Typically, this F-value with given degrees of freedom suggests a P-value greater than typical significance levels (such as 0.05), providing less evidence against the null hypothesis.
04

Situation c: Two-tailed Test Analysis

For v_1 = 5 and v_2 = 10 , with a two-tailed test and f = 5.64 , determine the P-value by finding the upper-tail region's P-value and doubling it (since it's two-tailed). This F-value likely results in a small P-value, implying strong evidence against the null hypothesis under a two-tailed setting.
05

Situation d: Lower-tailed Test Analysis

For v_1 = 5 and v_2 = 10 , with a lower-tailed test and f = 0.200 , find the P-value by looking at the area to the left of 0.200 in the F-distribution table. This typically results in a small P-value since the F-value is significantly low, indicating strong evidence against the null hypothesis when hypothesizing lesser variance.
06

Situation e: Upper-tailed Test Analysis

For v_1 = 35 and v_2 = 20 , with an upper-tailed test and f = 3.24 , likely results in a moderate to small P-value, suggesting moderate to strong evidence against the null hypothesis. The exact P-value needs to be checked using tables or statistical software tailored to these specific degrees of freedom.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
In statistics, "degrees of freedom" refers to the number of values in a calculation that are free to vary. When conducting an F-test, the degrees of freedom is an essential concept because it directly affects the shape of the F-distribution curve and, consequently, the P-value.

The degrees of freedom for an F-test consist of two parts: the numerator ( v_1 ) and the denominator ( v_2 ). In the context of the exercise provided, v_1 = 5 and v_2 = 10 for most cases. These values play a critical role because they indicate how variable the numerator's and denominator's variances are, which can change the P-value outcome.

Considering F-distribution tables or calculators, both v_1 and v_2 must be input precisely to find the correct P-value. As these numbers increase, the distribution curve changes, affecting test sensitivity. Thus, understanding degrees of freedom helps provide insight into how closely your test statistic resembles the true variance ratio.
Upper-Tailed Test
An upper-tailed test in statistics tests whether a sample statistic is greater than a specified value. In the case of the F-test, we are concerned with determining if the variance in the numerator is significantly larger than that in the denominator.

When conducting an upper-tailed F-test, such as in situations (a), (b), and (e) in the exercise, the focus is on finding the area to the right of the observed F-statistic in the F-distribution. This calculated area represents the P-value. In a practical sense:
  • If the P-value is small (e.g., less than 0.05), there is strong evidence against the null hypothesis, suggesting a significant difference in variances with a bias towards a larger numerator variance.
  • A larger P-value indicates a lack of evidence to reject the null hypothesis.
Using statistical software or tables can help determine this area exactly, providing insight into test results.
Two-Tailed Test
In a two-tailed test, the hypothesis under investigation looks at both ends of the probability distribution to determine if a sample statistic is significantly different from a hypothesized value in either direction.

For the F-test, a two-tailed test like situation (c) in the exercise evaluates both whether the numerator's variance is either larger or smaller than the denominator's with substantial significance. The P-value calculation involves doubling the area of one tail, effectively considering both possibilities:
  • This approach is crucial when differences in either direction are equally important.
  • If the resulting P-value is low, it suggests significant discrepancies either way, leading to a rejection of the null hypothesis.
Understanding this concept aids in comprehensively analyzing differences in variance directionally, rather than focusing on one side alone.
Lower-Tailed Test
Unlike its upper-tailed counterpart, a lower-tailed test analyzes whether the sample statistic is significantly less than a specific hypothesized value. In F-test terminology, it looks to see if the variance from the numerator is notably smaller compared to the denominator.

When performing a lower-tailed F-test, like in situation (d) from the exercise, you focus on the left tail of the F-distribution:
  • This requires recognizing the P-value by determining the area to the left of the observed F-statistic.
  • A small P-value usually indicates substantial evidence against the null hypothesis, suggesting a considerably smaller variance in the numerator.
Utilizing tables or statistical tools simplifies finding this left area, delivering insights into variance comparisons in contexts needing reduced numerator variances.

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Most popular questions from this chapter

Sometimes experiments involving success or failure responses are run in a paired or before/ after manner. Suppose that before a major policy speech by a political candidate, \(n\) individuals are selected and asked whether \((S)\) or not \((F)\) they favor the candidate. Then after the speech the same \(n\) people are asked the same question. The responses can be entered in a table as follows: where \(X_{1}+X_{2}+X_{3}+X_{4}=n\). Let \(p_{1}, p_{2}, p_{3}\), and \(P_{4}\) denote the four cell probabilities, so that \(P_{1}=P(S\) before and \(S\) after \()\), and so on. We wish to test the hypothesis that the true proportion of supporters \((S)\) after the speech has not increased against the alternative that it has increased. a. State the two hypotheses of interest in terms of \(p_{1}, p_{2}, p_{3}\), and \(p_{4}\). b. Construct an estimator for the after/before difference in success probabilities. c. When \(n\) is large, it can be shown that the rv \(\left(X_{i}-X_{j}\right) / n\) has approximately a normal distribution with variance \(\left[p_{i}+p_{j}-\left(p_{i}-p_{j}\right)^{2}\right] / n\). Use this to construct a test statistic with approximately a standard normal distribution when \(H_{0}\) is true (the result is called MeNemar's test). d. If \(x_{1}=350, x_{2}=150, x_{3}=200\), and \(x_{4}=300\), what do you conclude?

The level of monoamine oxidase (MAO) activity in blood platelets \((\mathrm{nm} / \mathrm{mg}\) protein/ \(\mathrm{h})\) was determined for each individual in a sample of 43 chronic schizophrenics, resulting in \(\bar{x}=2.69\) and \(s_{1}=2.30\), as well as for 45 normal subjects, resulting in \(\bar{y}=6.35\) and \(s_{2}=4.03\). Does this data strongly suggest that true average MAO activity for normal subjects is more than twice the activity level for schizophrenics? Derive a test procedure and carry out the test using \(\alpha=.01\). [Hint: \(H_{0}\) and \(H_{\mathrm{a}}\) here have a different form from the three standard cases. Let \(\mu_{1}\) and \(\mu_{2}\) refer to true average MAO activity for schizophrenics and normal subjects, respectively, and consider the parameter \(\theta=2 \mu_{1}-\mu_{2}\). Write \(H_{0}\) and \(H_{\mathrm{a}}\) in terms of \(\theta\), estimate \(\theta\), and derive \(\hat{\sigma}_{\hat{\theta}}\) ("Reduced Monoamine Oxidase Activity in Blood Platelets from Schizophrenic Patients," Nature, July 28, 1972: 225-226).]

Let \(\mu_{1}\) and \(\mu_{2}\) denote true average tread lives for two competing brands of size P205/65R 15 radial tires. Test \(H_{0}: \mu_{1}-\mu_{2}=0\) versus \(H_{\mathrm{a}}: \mu_{1}-\) \(\mu_{2} \neq 0\) at level \(.05\) using the following data: \(m=45, \quad \bar{x}=42,500, \quad s_{1}=2200, \quad n=45\), \(\bar{y}=40,400\), and \(s_{2}=1900\).

Torsion during hip external rotation (ER) and extension may be responsible for certain kinds of injuries in golfers and other athletes. The article "Hip Rotational Velocities during the Full Golf Swing" (J. Sport Sci. Med., 2009: 296-299) reported on a study in which peak ER velocity and peak IR (internal rotation) velocity (both in \(\mathrm{deg} / \mathrm{s}\) ) were determined for a sample of 15 female collegiate golfers during their swings. The following data was supplied by the article's authors. a. Is it plausible that the differences came from a normally distributed population? b. The article reported that Mean \((\pm S D)=\) \(-145.3(68.0)\) for ER velocity and = \(-227.8(96.6)\) for IR velocity. Based just on this information, could a test of hypotheses about the difference between true average IR velocity and true average ER velocity be carried out? Explain. c. Do an appropriate hypothesis test about the difference between true average IR velocity and true average ER velocity and interpret the result.

A student project by Heather Kral studied students on "lifestyle floors" of a dormitory in comparison to students on other floors. On a lifestyle floor the students share a common major, and there are a faculty coordinator and resident assistant from that department. Here are the grade point averages of 30 students on lifestyle floors (L) and 30 students on other floors \((\mathrm{N})\) : L: \(2.00,2.25,2.60,2.90,3.00,3.00,3.00,3.00\), \(3.00,3.20,3.20,3.25,3.30,3.30,3.32,3.50\), \(3.50,3.60,3.60,3.70,3.75,3.75,3.79,3.80\), \(3.80,3.90,4.00,4.00,4.00,4.00\). \(\mathrm{N}: 1.20,2.00,2.29,2.45,2.50,2.50,2.50,2.50\), \(2.65,2.70,2.75,2.75,2.79,2.80,2.80,2.80\), \(2.86,2.90,3.00,3.07,3.10,3.25,3.50,3.54\), \(3.56,3.60,3.70,3.75,3.80,4.00\). Notice that the lifestyle grade point averages have a large number of repeats and the distribution is skewed, so there is some question about normality. a. Obtain a \(95 \%\) confidence interval for the difference of population means using the method based on the theorem of Section 10.2. b. Obtain a bootstrap sample of 999 differences of means. Check the bootstrap distribution for normality using a normal probability plot. c. Use the standard deviation of the bootstrap distribution along with the mean and \(t\) critical value from (a) to get a \(95 \%\) confidence interval for the difference of means. d. Use the bootstrap sample and the percentile method to obtain a \(95 \%\) confidence interval for the difference of means. e. Compare your three confidence intervals. If they are very similar, why do you think this is the case? f. Interpret your results. Is there a substantial difference between lifestyle and other floors? Why do you think the difference is as big as it is?

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