Chapter 7: Problem 9
Let \(f_{n}(x)=x^{n}, 0 \leqslant x \leqslant 1 .\) Show that \(\left\\{f_{n}\right\\}\) converges almost uniformly, but not uniformly.
Short Answer
Expert verified
\(f_n(x)\) converges almost uniformly to 0 on \([0, 1]\) but not uniformly due to the behavior near \(x = 1\).
Step by step solution
01
Understand the Problem
We need to show that the sequence of functions \(f_n(x) = x^n\) converges almost uniformly on the interval \([0, 1]\). Almost uniform convergence implies that for any given \(\epsilon > 0\), there is a set \(E\) with a small measure (typically close to zero), outside of which \(f_n\) converges uniformly to a limiting function. Here, the limitation comes from behavior near \(x = 1\).
02
Analyze Pointwise Convergence
First, analyze pointwise convergence. For each fixed \(x \in [0, 1)\), \(f_n(x) = x^n\) converges pointwise to the function \(f(x) = 0\) as \(n \to \infty\). However, at \(x = 1\), \(f_n(1) = 1^n = 1\), so the function converges to \(f(1) = 1\). Thus, the limiting function \(f(x)\) is: \[ f(x) = \begin{cases} 0, & \text{if } 0 \leq x < 1 \ 1, & \text{if } x = 1 \end{cases} \]
03
Consider Uniform Convergence
Examining uniform convergence, we need \(\sup_{x \in [0, 1]} |f_n(x) - f(x)|\) to go to zero as \(n\) approaches infinity. However, near \(x = 1\), \(f_n(x) = x^n\) does not approach 0 uniformly because at \(x = 1 - \frac{1}{n}\), \(f_n(x) \approx (1 - \frac{1}{n})^n \approx \frac{1}{e}\), which does not go to 0. Thus, \(f_n(x)\) does not converge uniformly to \(f(x)\) on \([0, 1]\).
04
Demonstrate Almost Uniform Convergence
To show almost uniform convergence, for any given \(\epsilon > 0\), choose a small \(\delta > 0\) such that the measure of the set \(E = [1-\delta, 1]\) is less than \(\epsilon\). Outside this set, for \(x \in [0, 1-\delta]\), \(f_n(x) = x^n\) converges uniformly to 0 because \(x^n < \delta^n\) and \(\delta^n\) goes to 0 as \(n\) increases. Therefore, \(f_n(x)\) converges almost uniformly to \(f(x)\) on \([0, 1]\) except on a set of arbitrarily small measure.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Almost Uniform Convergence
Almost uniform convergence is a nuanced form of convergence crucial in measure theory. When dealing with a sequence of functions like \(f_n(x) = x^n\) on the interval \([0, 1]\), we aim to show that these functions converge almost uniformly to a limiting function. This happens when the convergence is uniform outside of a set with a very small measure.
For any fixed \(\epsilon > 0\), you can find a negligible set \(E\) such that outside \(E\), the convergence to the limiting function is uniform. It allows us to say that for all \(x\) not in \(E\), \(|f_n(x) - f(x)|\) becomes arbitrarily small for all sufficiently large \(n\).
In the given problem, by choosing \(E = [1 - \delta, 1]\), where the measure of \(E\) is less than \(\epsilon\), whence for \(x\) in \([0, 1-\delta]\), we see that \(f_n(x)\) converges uniformly towards zero. This demonstrates almost uniform convergence, while acknowledging the erratic behavior of the function near \(x = 1\).
For any fixed \(\epsilon > 0\), you can find a negligible set \(E\) such that outside \(E\), the convergence to the limiting function is uniform. It allows us to say that for all \(x\) not in \(E\), \(|f_n(x) - f(x)|\) becomes arbitrarily small for all sufficiently large \(n\).
In the given problem, by choosing \(E = [1 - \delta, 1]\), where the measure of \(E\) is less than \(\epsilon\), whence for \(x\) in \([0, 1-\delta]\), we see that \(f_n(x)\) converges uniformly towards zero. This demonstrates almost uniform convergence, while acknowledging the erratic behavior of the function near \(x = 1\).
Pointwise Convergence
Pointwise convergence is easier to understand as it looks at each point individually. For the sequence of functions \(f_n(x) = x^n\), pointwise convergence observes the behavior of the sequence as \(n\) increases at each specific \(x\).
For this sequence, at every \(x \in [0, 1)\), \(x^n\) moves towards zero as \(n\) gets larger. However, specifically at \(x = 1\), it remains constant because \(1^n\) always equals 1.
This results in the limiting function \(f(x)\) being defined as follows:
For this sequence, at every \(x \in [0, 1)\), \(x^n\) moves towards zero as \(n\) gets larger. However, specifically at \(x = 1\), it remains constant because \(1^n\) always equals 1.
This results in the limiting function \(f(x)\) being defined as follows:
- \(f(x) = 0\) for \(0 \leq x < 1\)
- \(f(x) = 1\) for \(x = 1\)
Uniform Convergence
Uniform convergence is a stronger type of convergence than pointwise. It requires that a sequence of functions \(f_n\) converges to \(f\) such that the maximum difference between \(f_n(x)\) and \(f(x)\) across all \(x\) approaches zero.
In the context of \(f_n(x) = x^n\) over \([0, 1]\), illustrating uniform convergence involves checking if \(\sup_{x \in [0,1]} |f_n(x) - f(x)|\) tends to zero as \(n\) becomes large.
However, for this case, near \(x = 1\), the behavior changes. Specifically, for \(x = 1 - \frac{1}{n}\), you have \( (1 - \frac{1}{n})^n \approx \frac{1}{e} \) which clearly does not go to 0 as \(n\) increases.
Thus we conclude that uniform convergence fails here, because the convergence is not uniform across the entire interval; it doesn't vanish when close to \(x = 1\). This uniform convergence failure highlights the significance of exploring almost uniform convergence instead.
In the context of \(f_n(x) = x^n\) over \([0, 1]\), illustrating uniform convergence involves checking if \(\sup_{x \in [0,1]} |f_n(x) - f(x)|\) tends to zero as \(n\) becomes large.
However, for this case, near \(x = 1\), the behavior changes. Specifically, for \(x = 1 - \frac{1}{n}\), you have \( (1 - \frac{1}{n})^n \approx \frac{1}{e} \) which clearly does not go to 0 as \(n\) increases.
Thus we conclude that uniform convergence fails here, because the convergence is not uniform across the entire interval; it doesn't vanish when close to \(x = 1\). This uniform convergence failure highlights the significance of exploring almost uniform convergence instead.
Sequence of Functions
Understanding a sequence of functions is fundamental in analysis as it involves exploring how sets of functions behave as a collective entity rather than individual elements. A sequence of functions is an ordered collection, \(\{f_n\}\), where \(n\) indicates the position within the sequence.
In practice, for \(f_n(x) = x^n\), we take each function one at a time, monitoring its behavior as \(n\) increases. This particular sequence showcases very interesting dynamics:
In practice, for \(f_n(x) = x^n\), we take each function one at a time, monitoring its behavior as \(n\) increases. This particular sequence showcases very interesting dynamics:
- For values \(x\) in \([0, 1)\), each term \(x^n\) ¯increasingly pulls towards zero as \(n\) grows.
- Specifically at \(x = 1\), \(x^n = 1\), hence maintaining a constant value.