Chapter 5: Problem 15
Let \(E_{n} \in \mathcal{S}, n=1, \ldots\) Show that (i) \(\mu\left(\lim \inf E_{n}\right) \leqslant \lim \inf \mu\left(E_{n}\right)\), (ii) if \(\mu(X)<\infty\) we have \(\lim\) sup \(\mu\left(E_{n}\right) \leqslant \mu\left(\lim \sup E_{n}\right)\), and that the condition \(\mu(X)<\infty\) is necessary.
Short Answer
Step by step solution
Understanding the Definitions
Prove Part (i): Showing \(\mu\left(\lim \inf E_{n}\right) \leqslant \lim \inf \mu\left(E_{n}\right)\)
Prove Part (ii): Showing \(\lim \sup \mu\left(E_{n}\right) \leqslant \mu\left(\lim \sup E_{n}\right)\)
Proving the Condition \(\mu(X)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Lim Inf and Lim Sup of Sets
- \[ \liminf E_n = \bigcup_{n=1}^{\infty} \bigcap_{k=n}^{\infty} E_k \]
On the other hand, the limit superior \(\limsup E_n\), reveals the points that appear infinitely often in the sequence of sets. Its definition is:
- \[ \limsup E_n = \bigcap_{n=1}^{\infty} \bigcup_{k=n}^{\infty} E_k \]
Continuity of Measure
One of the key applications is the continuity of measure from above which deals with decreasing sequences of sets. If \(F_k\) is a descending sequence such that \( F_1 \supseteq F_2 \supseteq \ldots \), the continuity from above gives us:
- \[ \mu\left(\bigcap_{k=1}^{\infty} F_k\right) = \lim_{k \to \infty} \mu(F_k) \]
The continuity of measure from below applies to increasing sequences where \(G_k\) is an ascending sequence such that \( G_1 \subseteq G_2 \subseteq \ldots \). For this, it says:
- \[ \mu\left(\bigcup_{k=1}^{\infty} G_k\right) = \lim_{k \to \infty} \mu(G_k) \]
Conditions for Finiteness
In these exercises, the condition \( \mu(X) < \infty \) became crucial for proving part (ii) of the expression, \( \limsup \mu(E_n) \leq \mu(\limsup E_n) \). Without this assumption, you may encounter discrepancies as showcased when using the counting measure on \( \mathbb{N} \). If \( X \) is infinite, taking each \( E_n = \{n, n+1, \ldots\} \), results in \( \limsup E_n = \emptyset \), making the measure \( \mu(\limsup E_n) = 0 \). However, each \( \mu(E_n) = \infty \) making \( \limsup \mu(E_n) = \infty \), leading to a contradiction.
Thus, such conditions are not merely administrative boundaries but rather pivotal elements that ensure finite results are logically consistent and align with theoretical expectations.